Now that we have graphs for
$sin\theta $ and
$cos\theta $ , there is an easy way to visualise the tangent graph. Let us look back at our definitions of
$sin\theta $ and
$cos\theta $ for a right-angled triangle.
This is the first of an important set of equations called
trigonometric identities . An identity is an equation, which holds true for any value which is put into it. In this case we have shown that
$$tan\theta =\frac{sin\theta}{cos\theta}$$
for any value of
$\theta $ .
So we know that for values of
$\theta $ for which
$sin\theta =0$ , we must also have
$tan\theta =0$ . Also, if
$cos\theta =0$ our value of
$tan\theta $ is undefined as we cannot divide by 0. The graph is shown in
[link] . The dashed vertical lines are at the values of
$\theta $ where
$tan\theta $ is not defined.
Functions of the form
$y=atan\left(x\right)+q$
In the figure below is an example of a function of the form
$y=atan\left(x\right)+q$ .
Functions of the form
$y=atan\left(\theta \right)+q$ :
On the same set of axes, plot the following graphs:
$a\left(\theta \right)=tan\theta -2$
$b\left(\theta \right)=tan\theta -1$
$c\left(\theta \right)=tan\theta $
$d\left(\theta \right)=tan\theta +1$
$e\left(\theta \right)=tan\theta +2$
Use your results to deduce the effect of
$q$ .
On the same set of axes, plot the following graphs:
$f\left(\theta \right)=-2\xb7tan\theta $
$g\left(\theta \right)=-1\xb7tan\theta $
$h\left(\theta \right)=0\xb7tan\theta $
$j\left(\theta \right)=1\xb7tan\theta $
$k\left(\theta \right)=2\xb7tan\theta $
Use your results to deduce the effect of
$a$ .
You should have found that the value of
$a$ affects the steepness of each of the branches. The larger the absolute magnitude of
a , the quicker the branches approach their asymptotes, the values where they are not defined. Negative
$\mathit{a}$ values switch the direction of the branches.
You should have also found that the value of
$q$ affects the vertical shift as for
$sin\theta $ and
$cos\theta $ .
These different properties are summarised in
[link] .
Table summarising general shapes and positions of graphs of functions of the form
$y=atan\left(x\right)+q$ .
$a>0$
$a<0$
$q>0$
$q<0$
Domain and range
The domain of
$f\left(\theta \right)=atan\left(\theta \right)+q$ is all the values of
$\theta $ such that
$cos\theta $ is not equal to 0. We have already seen that when
$cos\theta =0$ ,
$tan\theta =\frac{sin\theta}{cos\theta}$ is undefined, as we have division by zero. We know that
$cos\theta =0$ for all
$\theta ={90}^{\circ}+{180}^{\circ}n$ , where
$n$ is an integer. So the domain of
$f\left(\theta \right)=atan\left(\theta \right)+q$ is all values of
$\theta $ , except the values
$\theta ={90}^{\circ}+{180}^{\circ}n$ .
The range of
$f\left(\theta \right)=atan\theta +q$ is
$\left\{f\right(\theta ):f(\theta )\in (-\infty ,\infty \left)\right\}$ .
Intercepts
The
$y$ -intercept,
${y}_{int}$ , of
$f\left(\theta \right)=atan\left(x\right)+q$ is again simply the value of
$f\left(\theta \right)$ at
$\theta ={0}^{\circ}$ .
As
$\theta $ approaches
${90}^{\circ}$ ,
$tan\theta $ approaches infinity. But as
$\theta $ is undefined at
${90}^{\circ}$ ,
$\theta $ can only approach
${90}^{\circ}$ , but never equal it. Thus the
$tan\theta $ curve gets closer and closer to the line
$\theta ={90}^{\circ}$ , without ever touching it. Thus the line
$\theta ={90}^{\circ}$ is an asymptote of
$tan\theta $ .
$tan\theta $ also has asymptotes at
$\theta ={90}^{\circ}+{180}^{\circ}n$ , where
$n$ is an integer.
Graphs of trigonometric functions
Using your knowldge of the effects of
$a$ and
$q$ , sketch each of the following graphs, without using a table of values, for
$\theta \in [{0}^{\circ};{360}^{\circ}]$
$y=2sin\theta $
$y=-4cos\theta $
$y=-2cos\theta +1$
$y=sin\theta -3$
$y=tan\theta -2$
$y=2cos\theta -1$
Give the equations of each of the following graphs:
The following presentation summarises what you have learnt in this chapter.
Summary
We can define three trigonometric functions for right angled triangles: sine (sin), cosine (cos) and tangent (tan).
Each of these functions have a reciprocal: cosecant (cosec), secant (sec) and cotangent (cot).
We can use the principles of solving equations and the trigonometric functions to help us solve simple trigonometric equations.
We can solve problems in two dimensions that involve right angled triangles.
For some special angles, we can easily find the values of sin, cos and tan.
We can extend the definitions of the trigonometric functions to any angle.
Trigonometry is used to help us solve problems in 2-dimensions, such as finding the height of a building.
We can draw graphs for sin, cos and tan
End of chapter exercises
Calculate the unknown lengths
In the triangle
$PQR$ ,
$PR=20$ cm,
$QR=22$ cm and
$P\widehat{R}Q={30}^{\circ}$ . The perpendicular line from
$P$ to
$QR$ intersects
$QR$ at
$X$ . Calculate
the length
$XR$ ,
the length
$PX$ , and
the angle
$Q\widehat{P}X$
A ladder of length 15 m is resting against a wall, the base of the ladder is 5 m from the wall. Find the angle between the wall and the ladder?
A ladder of length 25 m is resting against a wall, the ladder makes an angle
${37}^{\circ}$ to the wall. Find the distance between the wall and the base of the ladder?
In the following triangle find the angle
$A\widehat{B}C$
In the following triangle find the length of side
$CD$
$A(5;0)$ and
$B(11;4)$ . Find the angle between the line through A and B and the x-axis.
$C(0;-13)$ and
$D(-12;14)$ . Find the angle between the line through C and D and the y-axis.
A
$5\phantom{\rule{0.166667em}{0ex}}\mathrm{m}$ ladder is placed
$2\phantom{\rule{0.166667em}{0ex}}\mathrm{m}$ from the wall. What is the angle the ladder makes with the wall?
Given the points: E(5;0), F(6;2) and G(8;-2), find angle
$F\widehat{E}G$ .
An isosceles triangle has sides
$9\phantom{\rule{0.166667em}{0ex}}\mathrm{cm},\phantom{\rule{0.166667em}{0ex}}9\phantom{\rule{0.166667em}{0ex}}\mathrm{cm}$ and
$2\phantom{\rule{0.166667em}{0ex}}\mathrm{cm}$ . Find the size of the smallest angle of the triangle.
A right-angled triangle has hypotenuse
$13\phantom{\rule{0.166667em}{0ex}}\mathrm{mm}$ . Find the length of the other two sides if one of the angles of the triangle is
${50}^{\circ}$ .
One of the angles of a rhombus (
rhombus - A four-sided polygon, each of whose sides is of equal length) with perimeter
$20\phantom{\rule{0.166667em}{0ex}}\mathrm{cm}$ is
${30}^{\circ}$ .
Find the sides of the rhombus.
Find the length of both diagonals.
Captain Hook was sailing towards a lighthouse with a height of
$10\phantom{\rule{0.166667em}{0ex}}\mathrm{m}$ .
If the top of the lighthouse is
$30\phantom{\rule{0.166667em}{0ex}}\mathrm{m}$ away, what is the angle of elevation of the boat to the nearest integer?
If the boat moves another
$7\phantom{\rule{0.166667em}{0ex}}\mathrm{m}$ towards the lighthouse, what is the new angle of elevation of the boat to the nearest integer?
(Tricky) A triangle with angles
${40}^{\circ},\phantom{\rule{0.166667em}{0ex}}{40}^{\circ}$ and
${100}^{\circ}$ has a perimeter of
$20\phantom{\rule{0.166667em}{0ex}}\mathrm{cm}$ . Find the length of each side of the triangle.
Questions & Answers
how do you translate this in Algebraic Expressions
In this morden time nanotechnology used in many field .
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2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc
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and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change .
maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.