Discussion of Discrete-time Fourier Transforms. Topics include comparison with analog transforms and discussion of Parseval's theorem.
The Fourier transform of the discrete-time signal
is defined to be
Frequency here has no units. As should be expected, thisdefinition is linear, with the transform of a sum of signals
equaling the sum of their transforms. Real-valued signals haveconjugate-symmetric spectra:
.
A special property of the discrete-time Fourier transform isthat it is periodic with period one:
.
Derive this property from the definition of the DTFT.
Because of this periodicity, we need only plot the spectrum overone period to understand completely the spectrum's structure;
typically, we plot the spectrum over the frequency range
.
When the signal is real-valued, we can further simplify ourplotting chores by showing the spectrum only over
;
the spectrum at negative frequencies can be derived frompositive-frequency spectral values.
When we obtain the discrete-time signal via sampling an analog
signal, the
Nyquist frequency corresponds to the
discrete-time frequency
. To show this, note that a sinusoid having a
frequency equal to the Nyquist frequency
has a sampled waveform that equals
The exponential in the DTFT at frequency
equals
, meaning that discrete-time frequency equals analog
frequency multiplied by the sampling interval
and
represent discrete-time and analog frequency
variables, respectively. The
aliasing figure provides
another way of deriving this result. As the duration of eachpulse in the periodic sampling signal
narrows, the amplitudes of the signal's spectral
repetitions, which are governed by the
Fourier series coefficients of
, become increasingly equal. Examination of the
periodic pulse
signal reveals that as
decreases, the value of
,
the largest Fourier coefficient, decreases to zero:
.
Thus, to maintain a mathematically viable Sampling Theorem, theamplitude
must increase as
, becoming infinitely large as the pulse duration
decreases. Practical systems use a small value of
, say
and use amplifiers to rescale the signal. Thus, the sampledsignal's spectrum becomes periodic with period
.
Thus, the Nyquist frequency
corresponds to the frequency
.
Let's compute the discrete-time Fourier transform of the
exponentially decaying sequence
,
where
is the unit-step sequence. Simply plugging the signal'sexpression into the Fourier transform formula,
This sum is a special case of the
geometric
series .
Thus, as long as
,
we have our Fourier transform.
Using Euler's relation, we can express the magnitude and phase
of this spectrum.
No matter what value of
we
choose, the above formulae clearly demonstrate the periodicnature of the spectra of discrete-time signals.
[link] shows indeed that the spectrum
is a periodic function. We need only consider the spectrumbetween
and
to unambiguously define it. When
,
we have a lowpass spectrum—the spectrum diminishes asfrequency increases from 0 to
—with increasing
leading to a greater low frequency
content; for
,
we have a highpass spectrum(
[link] ).
Derive this formula for the finite geometric series sum.
The "trick" is to consider the difference between theseries' sum and the sum of the series multiplied by
.
which, after manipulation, yields the geometric sum formula.
The ratio of sine functions has the generic form of
,
which is known as the
discrete-time sinc function
.
Thus, our transform can be concisely expressed as
. The discrete-time pulse's spectrum contains many
ripples, the number of which increase with
, the pulse's duration.
The inverse discrete-time Fourier transform is easily derived
from the following relationship:
Therefore, we find that
The Fourier transform pairs in discrete-time are
The properties of the discrete-time Fourier transform mirror
those of the analog Fourier transform. The
DTFT properties table shows similarities and differences. One important common
property is Parseval's Theorem.
To show this important property, we simply substitute theFourier transform expression into the frequency-domain
expression for power.
Using the
orthogonality
relation , the integral equals
,
where
is the
unit sample . Thus, the double sum collapses
into a single sum because nonzero values occur only when
,
giving Parseval's Theorem as a result. We term
the energy in the discrete-time signal
in spite of the fact that discrete-time signals don't consume(or produce for that matter) energy. This terminology is a
carry-over from the analog world.
Suppose we obtained our discrete-time signal from values ofthe product
,
where the duration of the component pulses in
is
. How is
the discrete-time signal energy related to the total energycontained in
?
Assume the signal is bandlimited and that the sampling ratewas chosen appropriate to the Sampling Theorem's conditions.
If the sampling frequency exceeds the Nyquist frequency, thespectrum of the samples equals the analog spectrum, but overthe normalized analog frequency
. Thus, the energy in the sampled signal equals
the original signal's energy multiplied by
.
Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
pratica A on solution of hydro chloric acid,B is a solution containing 0.5000 mole ofsodium chlorid per dm³,put A in the burret and titrate 20.00 or 25.00cm³ portion of B using melting orange as the indicator. record the deside of your burret tabulate the burret reading and calculate the average volume of acid used?
No. According to Isac Newtons law. this two bodies maybe you and the wall beside you.
Attracting depends on the mass och each body and distance between them.
Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Specific heat capacity is a measure of the amount of energy required to raise the temperature of a substance by one degree Celsius (or Kelvin). It is measured in Joules per kilogram per degree Celsius (J/kg°C).
AI-Robot
specific heat capacity is the amount of energy needed to raise the temperature of a substance by one degree Celsius or kelvin
ROKEEB
Got questions? Join the online conversation and get instant answers!