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Find the values of x for which sin x 2 = 0 , 5 if it is given that x < 90 .

  1. Because we are told that x is an acute angle, we can simply apply an inverse trigonometric function to both sides.

    sin x 2 = 0 , 5 x 2 = arcsin 0 , 5 x 2 = 30 x = 60

We can, of course, solve trigonometric equations in any range by drawing the graph.

For what values of x does sin x = 0 , 5 , when - 360 x 360 ?

  1. We take a look at the graph of sin x = 0 , 5 on the interval [ - 360 , 360 ] . We want to know when the y value of the graph is 0 , 5 , so we draw in a line at y = 0 , 5 .

  2. Notice that this line touches the graph four times. This means that there are four solutions to the equation.

  3. Read off the x values of those intercepts from the graph as x = - 330 , - 210 , 30 and 150 .

This method can be time consuming and inexact. We shall now look at how to solve these problems algebraically.

Solution using cast diagrams

The sign of the trigonometric function

The first step to finding the trigonometry of any angle is to determine the sign of the ratio for a given angle. We shall do this for the sine function first and then do the same for the cosine and tangent.

The graph and unit circle showing the sign of the sine function.

In [link] we have split the sine graph into four quadrants , each 90 wide. We call them quadrants because they correspond to the four quadrants of the unit circle. We notice from [link] that the sine graph is positive in the 1 st and 2 nd quadrants and negative in the 3 rd and 4 th . [link] shows similar graphs for cosine and tangent.

Graphs showing the sign of the cosine and tangent functions.

All of this can be summed up in two ways. [link] shows which trigonometric functions are positive and which are negative in each quadrant.

The signs of the three basic trigonometric functions in each quadrant.
1 st 2 nd 3 rd 4 th
sin +VE +VE -VE -VE
cos +VE -VE -VE +VE
tan +VE -VE +VE -VE

A more convenient way of writing this is to note that all functions are positive in the 1 st quadrant, only sine is positive in the 2 nd , only tangent in the 3 rd and only cosine in the 4 th . We express this using the CAST diagram ( [link] ). This diagram is known as a CAST diagram as the letters, taken anticlockwise from the bottom right, read C-A-S-T. The letter in each quadrant tells us which trigonometric functions are positive in that quadrant. The `A' in the 1 st quadrant stands for all (meaning sine, cosine and tangent are all positive in this quadrant). `S', `C' and `T' ,of course, stand for sine, cosine and tangent. The diagram is shown in two forms. The version on the left shows the CAST diagram including the unit circle. This version is useful for equations which lie in large or negative ranges. The simpler version on the right is useful for ranges between 0 and 360 . Another useful diagram shown in [link] gives the formulae to use in each quadrant when solving a trigonometric equation.

The two forms of the CAST diagram and the formulae in each quadrant.

Magnitude of the trigonometric functions

Now that we know in which quadrants our solutions lie, we need to know which angles in these quadrants satisfy our equation.

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Source:  OpenStax, Siyavula textbooks: grade 11 maths. OpenStax CNX. Aug 03, 2011 Download for free at http://cnx.org/content/col11243/1.3
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