<< Chapter < Page Chapter >> Page >

It is more likely that the amount of fishing is governed by the current number of fish present, so instead of a constant number of fish being caught, the rate is proportional to the current number of fish present, with proportionality constant k , as

P = 0.4 P ( 1 P 10000 ) k P .

[T] For the previous fishing problem, draw a directional field assuming k = 0.1 . Draw some solutions that exhibit this behavior. What are the equilibria and what are their stabilities?

Got questions? Get instant answers now!

[T] Use software or a calculator to draw directional fields for k = 0.4 . What are the nonnegative equilibria and their stabilities?


A direction field with arrows pointing to the right at P = 0. Below 0, the arrows point down and to the right. Above 0, the arrows point down and to the right. The further away from 0, the more vertical the arrows become.
P 1 = 0 is semi-stable

Got questions? Get instant answers now!

[T] Use software or a calculator to draw directional fields for k = 0.6 . What are the equilibria and their stabilities?

Got questions? Get instant answers now!

Solve this equation, assuming a value of k = 0.05 and an initial condition of 2000 fish.

y = −20 4 × 10 −6 0.002 e 0.01 t

Got questions? Get instant answers now!

Solve this equation, assuming a value of k = 0.05 and an initial condition of 5000 fish.

Got questions? Get instant answers now!

The following problems add in a minimal threshold value for the species to survive, T , which changes the differential equation to P ( t ) = r P ( 1 P K ) ( 1 T P ) .

Draw the directional field of the threshold logistic equation, assuming K = 10 , r = 0.1 , T = 2 . When does the population survive? When does it go extinct?


A direction field with arrows pointing horizontally to the right along y = 2 and y = 10. For P < 2, the arrows point down and to the right. For 2 < P < 10, the arrows point up and to the right. For P > 10, the arrows point down and to the right. The further the arrows are from 2 and 10, the steeper they become, and the closer they are from 2 and 10, the more horizontal the arrows become.

Got questions? Get instant answers now!

For the preceding problem, solve the logistic threshold equation, assuming the initial condition P ( 0 ) = P 0 .

Got questions? Get instant answers now!

Bengal tigers in a conservation park have a carrying capacity of 100 and need a minimum of 10 to survive. If they grow in population at a rate of 1 % per year, with an initial population of 15 tigers, solve for the number of tigers present.

P ( t ) = 850 + 500 e 0.009 t 85 + 5 e 0.009 t

Got questions? Get instant answers now!

A forest containing ring-tailed lemurs in Madagascar has the potential to support 5000 individuals, and the lemur population grows at a rate of 5 % per year. A minimum of 500 individuals is needed for the lemurs to survive. Given an initial population of 600 lemurs, solve for the population of lemurs.

Got questions? Get instant answers now!

The population of mountain lions in Northern Arizona has an estimated carrying capacity of 250 and grows at a rate of 0.25 % per year and there must be 25 for the population to survive. With an initial population of 30 mountain lions, how many years will it take to get the mountain lions off the endangered species list (at least 100 ) ?

13 years months

Got questions? Get instant answers now!

The following questions consider the Gompertz equation , a modification for logistic growth, which is often used for modeling cancer growth, specifically the number of tumor cells.

The Gompertz equation is given by P ( t ) = α ln ( K P ( t ) ) P ( t ) . Draw the directional fields for this equation assuming all parameters are positive, and given that K = 1 .

Got questions? Get instant answers now!

Assume that for a population, K = 1000 and α = 0.05 . Draw the directional field associated with this differential equation and draw a few solutions. What is the behavior of the population?


A direction field with arrows pointing down and to the right for P < 0, up for 0 < P < 1,000, and down for P > 1,000. The further the arrows are from P = 0 and P = 1,000, the more vertical they become, and the closer they are, the more horizontal they are.

Got questions? Get instant answers now!

Solve the Gompertz equation for generic α and K and P ( 0 ) = P 0 .

Got questions? Get instant answers now!

[T] The Gompertz equation has been used to model tumor growth in the human body. Starting from one tumor cell on day 1 and assuming α = 0.1 and a carrying capacity of 10 million cells, how long does it take to reach “detection” stage at 5 million cells?

31.465 days

Got questions? Get instant answers now!

[T] It is estimated that the world human population reached 3 billion people in 1959 and 6 billion in 1999 . Assuming a carrying capacity of 16 billion humans, write and solve the differential equation for logistic growth, and determine what year the population reached 7 billion.

Got questions? Get instant answers now!

[T] It is estimated that the world human population reached 3 billion people in 1959 and 6 billion in 1999 . Assuming a carrying capacity of 16 billion humans, write and solve the differential equation for Gompertz growth, and determine what year the population reached 7 billion. Was logistic growth or Gompertz growth more accurate, considering world population reached 7 billion on October 31 , 2011 ?

September 2008

Got questions? Get instant answers now!

Show that the population grows fastest when it reaches half the carrying capacity for the logistic equation P = r P ( 1 P K ) .

Got questions? Get instant answers now!

When does population increase the fastest in the threshold logistic equation P ( t ) = r P ( 1 P K ) ( 1 T P ) ?

K + T 2

Got questions? Get instant answers now!

When does population increase the fastest for the Gompertz equation P ( t ) = α ln ( K P ( t ) ) P ( t ) ?

Got questions? Get instant answers now!

Below is a table of the populations of whooping cranes in the wild from 1940 to 2000 . The population rebounded from near extinction after conservation efforts began. The following problems consider applying population models to fit the data. Assume a carrying capacity of 10,000 cranes. Fit the data assuming years since 1940 (so your initial population at time 0 would be 22 cranes).

Source: https://www.savingcranes.org/images/stories/site_images/conservation/whooping_crane/pdfs/historic_wc_numbers.pdf
Year (years since conservation began) Whooping Crane Population
1940 ( 0 ) 22
1950 ( 10 ) 31
1960 ( 20 ) 36
1970 ( 30 ) 57
1980 ( 40 ) 91
1990 ( 50 ) 159
2000 ( 60 ) 256

Find the equation and parameter r that best fit the data for the logistic equation.

r = 0.0405

Got questions? Get instant answers now!

Find the equation and parameters r and T that best fit the data for the threshold logistic equation.

Got questions? Get instant answers now!

Find the equation and parameter α that best fit the data for the Gompertz equation.

α = 0.0081

Got questions? Get instant answers now!

Graph all three solutions and the data on the same graph. Which model appears to be most accurate?

Got questions? Get instant answers now!

Using the three equations found in the previous problems, estimate the population in 2010 (year 70 after conservation). The real population measured at that time was 437 . Which model is most accurate?

Logistic: 361 , Threshold: 436 , Gompertz: 309 .

Got questions? Get instant answers now!
Practice Key Terms 6

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Calculus volume 2. OpenStax CNX. Feb 05, 2016 Download for free at http://cnx.org/content/col11965/1.2
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Calculus volume 2' conversation and receive update notifications?

Ask