# 4.3 Partial derivatives  (Page 7/11)

 Page 7 / 11

## Key concepts

• A partial derivative is a derivative involving a function of more than one independent variable.
• To calculate a partial derivative with respect to a given variable, treat all the other variables as constants and use the usual differentiation rules.
• Higher-order partial derivatives can be calculated in the same way as higher-order derivatives.

## Key equations

• Partial derivative of $f$ with respect to $x$
$\frac{\partial f}{\partial x}=\underset{h\to 0}{\text{lim}}\frac{f\left(x+h,y\right)-f\left(x,y\right)}{h}$
• Partial derivative of $f$ with respect to $y$
$\frac{\partial f}{\partial y}=\underset{k\to 0}{\text{lim}}\frac{f\left(x,y+k\right)-f\left(x,y\right)}{k}$

For the following exercises, calculate the partial derivative using the limit definitions only.

$\frac{\partial z}{\partial x}$ for $z={x}^{2}-3xy+{y}^{2}$

$\frac{\partial z}{\partial y}$ for $z={x}^{2}-3xy+{y}^{2}$

$\frac{\partial z}{\partial y}=-3x+2y$

For the following exercises, calculate the sign of the partial derivative using the graph of the surface.

${f}_{x}\left(1,1\right)$

${f}_{x}\left(-1,1\right)$

The sign is negative.

${f}_{y}\left(1,1\right)$

${f}_{x}\left(0,0\right)$

The partial derivative is zero at the origin.

For the following exercises, calculate the partial derivatives.

$\frac{\partial z}{\partial x}$ for $z=\text{sin}\left(3x\right)\text{cos}\left(3y\right)$

$\frac{\partial z}{\partial y}$ for $z=\text{sin}\left(3x\right)\text{cos}\left(3y\right)$

$\frac{\partial z}{\partial y}=-3\phantom{\rule{0.2em}{0ex}}\text{sin}\left(3x\right)\text{sin}\left(3y\right)$

$\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}$ for $z={x}^{8}{e}^{3y}$

$\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}$ for $z=\text{ln}\left({x}^{6}+{y}^{4}\right)$

$\frac{\partial z}{\partial x}=\frac{6{x}^{5}}{{x}^{6}+{y}^{4}};\frac{\partial z}{\partial y}=\frac{4{y}^{3}}{{x}^{6}+{y}^{4}}$

Find ${f}_{y}\left(x,y\right)$ for $f\left(x,y\right)={e}^{xy}\text{cos}\left(x\right)\text{sin}\left(y\right).$

Let $z={e}^{xy}.$ Find $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}.$

$\frac{\partial z}{\partial x}=y{e}^{xy};\frac{\partial z}{\partial y}=x{e}^{xy}$

Let $z=\text{ln}\left(\frac{x}{y}\right).$ Find $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}.$

Let $z=\text{tan}\left(2x-y\right).$ Find $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}.$

$\frac{\partial z}{\partial x}=2\phantom{\rule{0.2em}{0ex}}{\text{sec}}^{2}\left(2x-y\right),\frac{\partial z}{\partial y}=\text{−}{\text{sec}}^{2}\left(2x-y\right)$

Let $z=\text{sinh}\left(2x+3y\right).$ Find $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}.$

Let $f\left(x,y\right)=\text{arctan}\left(\frac{y}{x}\right).$ Evaluate ${f}_{x}\left(2,-2\right)$ and ${f}_{y}\left(2,-2\right).$

${f}_{x}\left(2,-2\right)=\frac{1}{4}={f}_{y}\left(2,-2\right)$

Let $f\left(x,y\right)=\frac{xy}{x-y}.$ Find ${f}_{x}\left(2,-2\right)$ and ${f}_{y}\left(2,-2\right).$

Evaluate the partial derivatives at point $P\left(0,1\right).$

Find $\frac{\partial z}{\partial x}$ at $\left(0,1\right)$ for $z={e}^{\text{−}x}\text{cos}\left(y\right).$

$\frac{\partial z}{\partial x}=\text{−}\text{cos}\left(1\right)$

Given $f\left(x,y,z\right)={x}^{3}y{z}^{2},$ find $\frac{{\partial }^{2}f}{\partial x\partial y}$ and ${f}_{z}\left(1,1,1\right).$

Given $f\left(x,y,z\right)=2\phantom{\rule{0.2em}{0ex}}\text{sin}\left(x+y\right),$ find ${f}_{x}\left(0,\frac{\pi }{2},-4\right),$ ${f}_{y}\left(0,\frac{\pi }{2},-4\right),$ and ${f}_{z}\left(0,\frac{\pi }{2},-4\right).$

$\begin{array}{ccc}{f}_{x}=0,\hfill & {f}_{y}=0,\hfill & {f}_{z}=0\hfill \end{array}$

The area of a parallelogram with adjacent side lengths that are $a\phantom{\rule{0.2em}{0ex}}\text{and}\phantom{\rule{0.2em}{0ex}}b,$ and in which the angle between these two sides is $\theta ,$ is given by the function $A\left(a,b,\theta \right)=ba\phantom{\rule{0.2em}{0ex}}\text{sin}\left(\theta \right).$ Find the rate of change of the area of the parallelogram with respect to the following:

1. Side a
2. Side b
3. $\text{Angle}\phantom{\rule{0.2em}{0ex}}\theta$

Express the volume of a right circular cylinder as a function of two variables:

1. its radius $r$ and its height $h.$
2. Show that the rate of change of the volume of the cylinder with respect to its radius is the product of its circumference multiplied by its height.
3. Show that the rate of change of the volume of the cylinder with respect to its height is equal to the area of the circular base.

a. $V\left(r,h\right)=\pi {r}^{2}h$ b. $\frac{\partial V}{\partial r}=2\pi rh$ c. $\frac{\partial V}{\partial h}=\pi {r}^{2}$

Calculate $\frac{\partial w}{\partial z}$ for $w=z\phantom{\rule{0.2em}{0ex}}\text{sin}\left(x{y}^{2}+2z\right).$

Find the indicated higher-order partial derivatives.

${f}_{xy}$ for $z=\text{ln}\left(x-y\right)$

${f}_{xy}=\frac{1}{{\left(x-y\right)}^{2}}$

${f}_{yx}$ for $z=\text{ln}\left(x-y\right)$

Let $z={x}^{2}+3xy+2{y}^{2}.$ Find $\frac{{\partial }^{2}z}{\partial {x}^{2}}$ and $\frac{{\partial }^{2}z}{\partial {y}^{2}}.$

$\frac{{\partial }^{2}z}{\partial {x}^{2}}=2,\frac{{\partial }^{2}z}{\partial {y}^{2}}=4$

Given $z={e}^{x}\text{tan}\phantom{\rule{0.2em}{0ex}}y,$ find $\frac{{\partial }^{2}z}{\partial x\partial y}$ and $\frac{{\partial }^{2}z}{\partial y\partial x}.$

Given $f\left(x,y,z\right)=xyz,$ find ${f}_{xyy},{f}_{yxy},$ and ${f}_{yyx}.$

${f}_{xyy}={f}_{yxy}={f}_{yyx}=0$

Given $f\left(x,y,z\right)={e}^{-2x}\text{sin}\left({z}^{2}y\right),$ show that ${f}_{xyy}={f}_{yxy}.$

Show that $z=\frac{1}{2}\left({e}^{y}-{e}^{\text{−}y}\right)\text{sin}\phantom{\rule{0.2em}{0ex}}x$ is a solution of the differential equation $\frac{{\partial }^{2}z}{\partial {x}^{2}}+\frac{{\partial }^{2}z}{\partial {y}^{2}}=0.$

$\begin{array}{ccc}\hfill \frac{{d}^{2}z}{d{x}^{2}}& =\hfill & -\frac{1}{2}\left({e}^{y}-{e}^{\text{−}y}\right)\text{sin}\phantom{\rule{0.2em}{0ex}}x\hfill \\ \hfill \frac{{d}^{2}z}{d{y}^{2}}& =\hfill & \frac{1}{2}\left({e}^{y}-{e}^{\text{−}y}\right)\text{sin}\phantom{\rule{0.2em}{0ex}}x\hfill \\ \hfill \frac{{d}^{2}z}{d{x}^{2}}+\frac{{d}^{2}z}{d{y}^{2}}& =\hfill & 0\hfill \end{array}$

Find ${f}_{xx}\left(x,y\right)$ for $f\left(x,y\right)=\frac{4{x}^{2}}{y}+\frac{{y}^{2}}{2x}.$

Let $f\left(x,y,z\right)={x}^{2}{y}^{3}z-3x{y}^{2}{z}^{3}+5{x}^{2}z-{y}^{3}z.$ Find ${f}_{xyz}.$

${f}_{xyz}=6{y}^{2}x-18y{z}^{2}$

Let $F\left(x,y,z\right)={x}^{3}y{z}^{2}-2{x}^{2}yz+3xz-2{y}^{3}z.$ Find ${F}_{xyz}.$

Given $f\left(x,y\right)={x}^{2}+x-3xy+{y}^{3}-5,$ find all points at which ${f}_{x}={f}_{y}=0$ simultaneously.

$\left(\frac{1}{4},\frac{1}{2}\right),\left(1,1\right)$

Given $f\left(x,y\right)=2{x}^{2}+2xy+{y}^{2}+2x-3,$ find all points at which $\frac{\partial f}{\partial x}=0$ and $\frac{\partial f}{\partial y}=0$ simultaneously.

Given $f\left(x,y\right)={y}^{3}-3y{x}^{2}-3{y}^{2}-3{x}^{2}+1,$ find all points on $f$ at which ${f}_{x}={f}_{y}=0$ simultaneously.

$\left(0,0\right),\left(0,2\right),\left(\sqrt{3},-1\right),\left(\text{−}\sqrt{3},-1\right)$

Given $f\left(x,y\right)=15{x}^{3}-3xy+15{y}^{3},$ find all points at which ${f}_{x}\left(x,y\right)={f}_{y}\left(x,y\right)=0$ simultaneously.

Show that $z={e}^{x}\text{sin}\phantom{\rule{0.2em}{0ex}}y$ satisfies the equation $\frac{{\partial }^{2}z}{\partial {x}^{2}}+\frac{{\partial }^{2}z}{\partial {y}^{2}}=0.$

$\frac{{\partial }^{2}z}{\partial {x}^{2}}+\frac{{\partial }^{2}z}{\partial {y}^{2}}={e}^{x}\text{sin}\left(y\right)-{e}^{x}\text{sin}\phantom{\rule{0.2em}{0ex}}y=0$

Show that $f\left(x,y\right)=\text{ln}\left({x}^{2}+{y}^{2}\right)$ solves Laplace’s equation $\frac{{\partial }^{2}z}{\partial {x}^{2}}+\frac{{\partial }^{2}z}{\partial {y}^{2}}=0.$

Show that $z={e}^{\text{−}t}\text{cos}\left(\frac{x}{c}\right)$ satisfies the heat equation $\frac{\partial z}{\partial t}=\text{−}{e}^{\text{−}t}\text{cos}\left(\frac{x}{c}\right).$

${c}^{2}\frac{{\partial }^{2}z}{\partial {x}^{2}}={e}^{\text{−}t}\text{cos}\left(\frac{x}{c}\right)$

Find $\underset{\text{Δ}x\to 0}{\text{lim}}\frac{f\left(x+\text{Δ}x\right)-f\left(x,y\right)}{\text{Δ}x}$ for $f\left(x,y\right)=-7x-2xy+7y.$

Find $\underset{\text{Δ}y\to 0}{\text{lim}}\frac{f\left(x,y+\text{Δ}y\right)-f\left(x,y\right)}{\text{Δ}y}$ for $f\left(x,y\right)=-7x-2xy+7y.$

$\frac{\partial f}{\partial y}=-2x+7$

Find $\underset{\text{Δ}x\to 0}{\text{lim}}\frac{\text{Δ}f}{\text{Δ}x}=\underset{\text{Δ}x\to 0}{\text{lim}}\frac{f\left(x+\text{Δ}x,y\right)-f\left(x,y\right)}{\text{Δ}x}$ for $f\left(x,y\right)={x}^{2}{y}^{2}+xy+y.$

Find $\underset{\text{Δ}x\to 0}{\text{lim}}\frac{\text{Δ}f}{\text{Δ}x}=\underset{\text{Δ}x\to 0}{\text{lim}}\frac{f\left(x+\text{Δ}x,y\right)-f\left(x,y\right)}{\text{Δ}x}$ for $f\left(x,y\right)=\text{sin}\left(xy\right).$

$\frac{\partial f}{\partial x}=y\phantom{\rule{0.2em}{0ex}}\text{cos}\phantom{\rule{0.2em}{0ex}}xy$

The function $P\left(T,V\right)=\frac{nRT}{V}$ gives the pressure at a point in a gas as a function of temperature $T$ and volume $V.$ The letters $n\phantom{\rule{0.2em}{0ex}}\text{and}\phantom{\rule{0.2em}{0ex}}R$ are constants. Find $\frac{\partial P}{\partial V}$ and $\frac{\partial P}{\partial T},$ and explain what these quantities represent.

The equation for heat flow in the $xy\text{-plane}$ is $\frac{\partial f}{\partial t}=\frac{{\partial }^{2}f}{\partial {x}^{2}}+\frac{{\partial }^{2}f}{\partial {y}^{2}}.$ Show that $f\left(x,y,t\right)={e}^{-2t}\text{sin}\phantom{\rule{0.2em}{0ex}}x\phantom{\rule{0.2em}{0ex}}\text{sin}\phantom{\rule{0.2em}{0ex}}y$ is a solution.

The basic wave equation is ${f}_{tt}={f}_{xx}.$ Verify that $f\left(x,t\right)=\text{sin}\left(x+t\right)$ and $f\left(x,t\right)=\text{sin}\left(x-t\right)$ are solutions.

The law of cosines can be thought of as a function of three variables. Let $x,y,$ and $\theta$ be two sides of any triangle where the angle $\theta$ is the included angle between the two sides. Then, $F\left(x,y,\theta \right)={x}^{2}+{y}^{2}-2xy\phantom{\rule{0.2em}{0ex}}\text{cos}\phantom{\rule{0.2em}{0ex}}\theta$ gives the square of the third side of the triangle. Find $\frac{\partial F}{\partial \theta }$ and $\frac{\partial F}{\partial x}$ when $x=2,y=3,$ and $\theta =\frac{\pi }{6}.$

$\frac{\partial F}{\partial \theta }=6,\frac{\partial F}{\partial x}=4-3\sqrt{3}$

Suppose the sides of a rectangle are changing with respect to time. The first side is changing at a rate of $2$ in./sec whereas the second side is changing at the rate of $4$ in/sec. How fast is the diagonal of the rectangle changing when the first side measures $16$ in. and the second side measures $20$ in.? (Round answer to three decimal places.)

A Cobb-Douglas production function is $f\left(x,y\right)=200{x}^{0.7}{y}^{0.3},$ where $x\phantom{\rule{0.2em}{0ex}}\text{and}\phantom{\rule{0.2em}{0ex}}y$ represent the amount of labor and capital available. Let $x=500$ and $y=1000.$ Find $\frac{\delta f}{\delta x}$ and $\frac{\delta f}{\delta y}$ at these values, which represent the marginal productivity of labor and capital, respectively.

$\frac{\delta f}{\delta x}$ at $\left(500,1000\right)=172.36,$ $\frac{\delta f}{\delta y}$ at $\left(500,1000\right)=36.93$

The apparent temperature index is a measure of how the temperature feels, and it is based on two variables: $h,$ which is relative humidity, and $t,$ which is the air temperature.

$A=0.885t-22.4h+1.20th-0.544.$ Find $\frac{\partial A}{\partial t}$ and $\frac{\partial A}{\partial h}$ when $t=20\text{°}\text{F}$ and $h=0.90.$

find the 15th term of the geometric sequince whose first is 18 and last term of 387
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
hmm well what is the answer
Abhi
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can someone help me with some logarithmic and exponential equations.
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
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Abhi
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Abhi
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Abhi
Commplementary angles
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