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viii) Sal JY dié huis koop as jy dit kon bekostig? _______________________

Hoekom/hoekom nie? ___________________________________________

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c) Maak ’n lys van pryse van nog 10 huise wat geadverteer word.

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i) Bereken die mediaan. ____________________________________________

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ii) Wat is die gemiddelde prys waarteen dié huise verkoop word?

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12.4 Versamel ook die volgende inligting:

a) Raadpleeg jou plaaslike koerant / TV-gids. Kyk hoeveel tyd aan die volgende spandeer word en voltooi die tabelle.

TV 2
Program Maan Dins Woens Don Vry
Nuus
Sepies
Flieks
Kindervermaak
Sport
TV 3
Program Maan Dins Woens Don Vry
Nuus
Sepies
Flieks
Kindervermaak
Sport

b) Beantwoord die volgende vrae:

i) Aan watter tipe program word die meeste tyd spandeer op TV 2?

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ii) Aan watter tipe program word die ministe tyd spandeer op TV 3?

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iii) Watter stasie/kanaal spandeer die meeste tyd aan sport? _________________

iv) Watter stasie/kanaal spandeer die minste tyd aan kindervermaak? __________

v) Na watter van die bogenoemde soorte programme kyk JY die meeste?

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12.5 Kan jy aan nog metodes dink om inligting te versamel?

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Assessering

Leeruitkomste 5: Die leerder is in staat om data te versamel, op te som, voor te stel en krities te ontleed om gevolgtrekkings en voorspellings te maak en om toevallige variasie te interpreteer en te bepaal.

Assesseringstandaard 5.1: Dit is duidelik wanneer die leerder vrae oor menseregte-, sosiale, politieke, kulturele, omgewing- en ekonomiese sake in eie omgewing stel;

Assesseringstandaard 5.2: Dit is duidelik wanneer die leerder geskikte bronne vir die versameling van data (insluitend maats, gesin en familie, koerante, boeke, tydskrifte) kies;

Assesseringstandaard 5.3: Dit is duidelik wanneer die leerder eenvoudige vraelyste (met ‘n verskeidenheid moontlike antwoorde) en ontwerp gebruik en vraelyste (met ja/nee-tipe-antwoorde) gebruik ten einde data te versamel (alleen en of as lid van ‘n groep of span) om vrae te beantwoord;

Assesseringstandaard 5.6: Dit is duidelik wanneer die leerder opsommings maak van ongegroepeerde numeriese data deur die gemiddeld, mediaan en modus as bepalers van sentrale neigings te bereken, en daartussen onderskei;

Assesseringstandaard 5.9: Dit is duidelik wanneer die leerder data wat op verskeie maniere voorgestel is krities lees en interpreteer ten einde gevolgtrekkings en voorspellings te maak wat sensitief is.

Questions & Answers

a perfect square v²+2v+_
Dearan Reply
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Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
y=10×
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if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
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rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
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Differences Between Laspeyres and Paasche Indices
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No. 7x -4y is simplified from 4x + (3y + 3x) -7y
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is it 3×y ?
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J, combine like terms 7x-4y
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f(x)= 2|x+5| find f(-6)
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f(n)= 2n + 1
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Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
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. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
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preparation of nanomaterial
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Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
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Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
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the Beer law works very well for dilute solutions but fails for very high concentrations. why?
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Source:  OpenStax, Wiskunde graad 7. OpenStax CNX. Oct 21, 2009 Download for free at http://cnx.org/content/col11076/1.2
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