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Introduction of equivalent circuits, including the function in v-i relation.

We have found that the way to think about circuits is to locate and group parallel and series resistor combinations. Thoseresistors not involved with variables of interest can be collapsed into a single resistance. This result is known as an equivalent circuit : from the viewpoint of a pair of terminals, a group of resistors functions as a single resistor,the resistance of which can usually be found by applying the parallel and series rules.

This result generalizes to include sources in a very interesting and useful way. Let's consider our simple attenuator circuit (shown in the figure ) from the viewpoint of the output terminals. We want to find the v-i relation for the output terminal pair, and then find the equivalent circuit for the boxed circuit. Toperform this calculation, use the circuit laws and element relations, but do not attach anything to the outputterminals. We seek the relation between v and i that describes the kind of element that lurks within the dashed box. The result is

v R 1 R 2 i R 2 R 1 R 2 v in
If the source were zero, it could be replaced by a short circuit, which would confirm that the circuit does indeedfunction as a parallel combination of resistors. However, the source's presence means that the circuit is not well modeled as a resistor.

The Thévenin equivalent circuit.

If we consider the simple circuit of [link] , we find it has the v-i relation at its terminals of

v R eq i v eq
Comparing the two v-i relations, we find that they have the same form. In this case the Thévenin equivalent resistance is R eq R 1 R 2 and the Thévenin equivalent source has voltage v eq R 2 R 1 R 2 v in . Thus, from viewpoint of the terminals, you cannot distinguish thetwo circuits. Because the equivalent circuit has fewer elements, it is easier to analyze and understand than any otheralternative.

For any circuit containing resistors and sources, the v-i relation will be of the form

v R eq i v eq
and the Thévenin equivalent circuit for any such circuit is that of [link] . This equivalence applies no matter how many sources or resistors may be present in thecircuit. In the example below, we know the circuit's construction and element values, andderive the equivalent source and resistance. Because Thévenin's theorem applies in general, we should be ableto make measurements or calculations only from the terminals to determine the equivalent circuit.

To be more specific, consider the equivalent circuit of this figure . Let the terminals be open-circuited, which has the effect of setting thecurrent i to zero. Because no current flows through the resistor, the voltage across it iszero (remember, Ohm's Law says that v R i ). Consequently, by applying KVL we have that the so-calledopen-circuit voltage v oc equals the Thévenin equivalent voltage. Now consider the situation when we set the terminal voltage to zero(short-circuit it) and measure the resulting current. Referring to the equivalent circuit, the source voltage now appearsentirely across the resistor, leaving the short-circuit current to be i sc v eq R eq . From this property, we can determine the equivalent resistance.

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Source:  OpenStax, Fundamentals of electrical engineering i. OpenStax CNX. Aug 06, 2008 Download for free at http://legacy.cnx.org/content/col10040/1.9
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