<< Chapter < Page Chapter >> Page >
A brief description of a diode and its inner workings.

Diode

v-i relation and schematic symbol for the diode. Here, the diode parameters were room temperature and I 0 1  μA .

The resistor, capacitor, and inductor are linear circuit elements in that their v-i relations are linear in the mathematical sense. Voltage and current sourcesare (technically) nonlinear devices: stated simply, doubling the current through a voltage source does not double the voltage. Amore blatant, and very useful, nonlinear circuit element is the diode ( learn more ). Its input-output relation has an exponential form.

i t I 0 q k T v t 1
Here, the quantity q represents the charge of a single electron in coulombs, k is Boltzmann's constant, and T is the diode's temperature in K . At room temperature, the ratio k T q 25 mV. The constant I 0 is the leakage current, and is usually very small. Viewing this v-i relation in [link] , the nonlinearity becomes obvious. When the voltage is positive,current flows easily through the diode. This situation is known as forward biasing . When we apply a negative voltage, the current is quite small, and equals I 0 , known as the leakage or reverse-bias current. A less detailed model for the diode has any positive current flowing through the diode when it is forward biased, andno current when negative biased. Note that the diode's schematic symbol looks like an arrowhead; the direction of current flowcorresponds to the direction the arrowhead points.

Diode circuit

Because of the diode's nonlinear nature, we cannot use impedances nor series/parallel combination rules to analyze circuits containing them. The reliablenode method can always be used; it only relies on KVL for its application, and KVL is a statement about voltage drops around aclosed path regardless of whether the elements are linear or not. Thus, for this simple circuit wehave

v out R I 0 q k T v in v out 1
This equation cannot be solved in closed form. We must understand what is going on from basic principles,using computational and graphical aids. As an approximation, when v in is positive, current flows through the diode so long as the voltage v out is smaller than v in (so the diode is forward biased). If the source is negative or v out "tries" to be bigger than v in , the diode is reverse-biased, and the reverse-bias current flowsthrough the diode. Thus, at this level of analysis, positive input voltages result in positive output voltages with negativeones resulting in v out R I 0 .

Diode circuit

We need to detail the exponential nonlinearity to determine how the circuit distorts the input voltage waveform. We can ofcourse numerically solve [link] to determine the output voltage when the input is a sinusoid. Tolearn more, let's express this equation graphically. We plot each term as a function of v out for various values of the input voltage v in ; where they intersect gives us the output voltage. The left side, the current through the output resistor, does notvary itself with v in , and thus we have a fixed straight line. As for the right side,which expresses the diode's v-i relation, the point at which the curve crosses the v out axis gives us the value of v in . Clearly, the two curves will always intersect just once for anyvalue of v in , and for positive v in the intersection occurs at a value for v out smaller than v in . This reduction is smaller if the straight line has a shallowerslope, which corresponds to using a bigger output resistor. For negative v in , the diode is reverse-biased and the output voltage equals R I 0 .

What utility might this simple circuit have? The diode'snonlinearity cannot be escaped here, and the clearly evident distortion must have some practical application if the circuitwere to be useful. This circuit, known as a half-wave rectifier , is present in virtually every AM radio twice and each serves very different functions! We'll learn what functions later.

Diode circuit

Here is a circuit involving a diode that is actually simpler toanalyze than the previous one. We know that the current through the resistor must equal that through the diode. Thus, thediode's current is proportional to the input voltage. As the voltage across the diode is related to the logarithm of itscurrent, we see that the input-output relation is

v out k T q v in R I 0 1
Clearly, the name logarithmic amplifier is justified for this circuit.

Questions & Answers

calculate molarity of NaOH solution when 25.0ml of NaOH titrated with 27.2ml of 0.2m H2SO4
Gasin Reply
what's Thermochemistry
rhoda Reply
the study of the heat energy which is associated with chemical reactions
Kaddija
How was CH4 and o2 was able to produce (Co2)and (H2o
Edafe Reply
explain please
Victory
First twenty elements with their valences
Martine Reply
what is chemistry
asue Reply
what is atom
asue
what is the best way to define periodic table for jamb
Damilola Reply
what is the change of matter from one state to another
Elijah Reply
what is isolation of organic compounds
IKyernum Reply
what is atomic radius
ThankGod Reply
Read Chapter 6, section 5
Dr
Read Chapter 6, section 5
Kareem
Atomic radius is the radius of the atom and is also called the orbital radius
Kareem
atomic radius is the distance between the nucleus of an atom and its valence shell
Amos
Read Chapter 6, section 5
paulino
Bohr's model of the theory atom
Ayom Reply
is there a question?
Dr
when a gas is compressed why it becomes hot?
ATOMIC
It has no oxygen then
Goldyei
read the chapter on thermochemistry...the sections on "PV" work and the First Law of Thermodynamics should help..
Dr
Which element react with water
Mukthar Reply
Mgo
Ibeh
an increase in the pressure of a gas results in the decrease of its
Valentina Reply
definition of the periodic table
Cosmos Reply
What is the lkenes
Da Reply
what were atoms composed of?
Moses Reply
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Fundamentals of electrical engineering i. OpenStax CNX. Aug 06, 2008 Download for free at http://legacy.cnx.org/content/col10040/1.9
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Fundamentals of electrical engineering i' conversation and receive update notifications?

Ask