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u = 3 , −1 , 2 , v = −2 , 0 , 1

w = 1 3 6 i 7 3 6 j 2 3 6 k

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u = 2 , 6 , 1 , v = 3 , 0 , 1

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u = A B , v = A C , where A ( 1 , 0 , 1 ) , B ( 1 , −1 , 3 ) , and C ( 0 , 0 , 5 )

w = 4 21 i 2 21 j 1 21 k

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u = O P , v = P Q , where P ( −1 , 1 , 0 ) and Q ( 0 , 2 , 1 )

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Determine the real number α such that u × v and i are orthogonal, where u = 3 i + j 5 k and v = 4 i 2 j + α k .

α = 10

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Show that u × v and 2 i 14 j + 2 k cannot be orthogonal for any α real number, where u = i + 7 j k and v = α i + 5 j + k .

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Show that u × v is orthogonal to u + v and u v , where u and v are nonzero vectors.

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Show that v × u is orthogonal to ( u · v ) ( u + v ) + u , where u and v are nonzero vectors.

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Calculate the determinant | i j k 1 −1 7 2 0 3 | .

−3 i + 11 j + 2 k

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Calculate the determinant | i j k 0 3 −4 1 6 −1 | .

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For the following exercises, the vectors u and v are given. Use determinant notation to find vector w orthogonal to vectors u and v .

u = −1 , 0 , e t , v = 1 , e t , 0 , where t is a real number

w = −1 , e t , e t

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u = 1 , 0 , x , v = 2 x , 1 , 0 , where x is a nonzero real number

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Find vector ( a 2 b ) × c , where a = | i j k 2 −1 5 0 1 8 | , b = | i j k 0 1 1 2 −1 −2 | , and c = i + j + k .

−26 i + 17 j + 9 k

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Find vector c × ( a + 3 b ) , where a = | i j k 5 0 9 0 1 0 | , b = | i j k 0 −1 1 7 1 −1 | , and c = i k .

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[T] Use the cross product u × v to find the acute angle between vectors u and v , where u = i + 2 j and v = i + k . Express the answer in degrees rounded to the nearest integer.

72 °

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[T] Use the cross product u × v to find the obtuse angle between vectors u and v , where u = i + 3 j + k and v = i 2 j . Express the answer in degrees rounded to the nearest integer.

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Use the sine and cosine of the angle between two nonzero vectors u and v to prove Lagrange’s identity: u × v 2 = u 2 v 2 ( u · v ) 2 .

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Verify Lagrange’s identity u × v 2 = u 2 v 2 ( u · v ) 2 for vectors u = i + j 2 k and v = 2 i j .

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Nonzero vectors u and v are called collinear if there exists a nonzero scalar α such that v = α u . Show that u and v are collinear if and only if u × v = 0 .

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Nonzero vectors u and v are called collinear if there exists a nonzero scalar α such that v = α u . Show that vectors A B and A C are collinear, where A ( 4 , 1 , 0 ) , B ( 6 , 5 , −2 ) , and C ( 5 , 3 , −1 ) .

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Find the area of the parallelogram with adjacent sides u = 3 , 2 , 0 and v = 0 , 2 , 1 .

7

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Find the area of the parallelogram with adjacent sides u = i + j and v = i + k .

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Consider points A ( 3 , −1 , 2 ) , B ( 2 , 1 , 5 ) , and C ( 1 , −2 , −2 ) .

  1. Find the area of parallelogram A B C D with adjacent sides A B and A C .
  2. Find the area of triangle A B C .
  3. Find the distance from point A to line B C .

a. 5 6 ; b. 5 6 2 ; c. 5 6 59

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Consider points A ( 2 , −3 , 4 ) , B ( 0 , 1 , 2 ) , and C ( −1 , 2 , 0 ) .

  1. Find the area of parallelogram A B C D with adjacent sides A B and A C .
  2. Find the area of triangle A B C .
  3. Find the distance from point B to line A C .
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In the following exercises, vectors u , v , and w are given.

  1. Find the triple scalar product u · ( v × w ) .
  2. Find the volume of the parallelepiped with the adjacent edges u , v , and w .

u = i + j , v = j + k , and w = i + k

a. 2 ; b. 2

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u = −3 , 5 , −1 , v = 0 , 2 , −2 , and w = 3 , 1 , 1

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Calculate the triple scalar products v · ( u × w ) and w · ( u × v ) , where u = 1 , 1 , 1 , v = 7 , 6 , 9 , and w = 4 , 2 , 7 .

v · ( u × w ) = −1 , w · ( u × v ) = 1

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Calculate the triple scalar products w · ( v × u ) and u · ( w × v ) , where u = 4 , 2 , −1 , v = 2 , 5 , −3 , and w = 9 , 5 , −10 .

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Find vectors a , b , and c with a triple scalar product given by the determinant

| 1 2 3 0 2 5 8 9 2 | . Determine their triple scalar product.

a = 1 , 2 , 3 , b = 0 , 2 , 5 , c = 8 , 9 , 2 ; a · ( b × c ) = −9

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The triple scalar product of vectors a , b , and c is given by the determinant

| 0 −2 1 0 1 4 1 −3 7 | . Find vector a b + c .

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Consider the parallelepiped with edges O A , O B , and O C , where A ( 2 , 1 , 0 ) , B ( 1 , 2 , 0 ) , and C ( 0 , 1 , α ) .

  1. Find the real number α > 0 such that the volume of the parallelepiped is 3 units 3 .
  2. For α = 1 , find the height h from vertex C of the parallelepiped. Sketch the parallelepiped.

a. α = 1 ; b. h = 1 ,
This figure is the first octant of the 3-dimensional coordinate system. There is a parallelepided drawn. From the origin there are three vectors to vertices on the parallelepiped. They are vectors to the points A (2, 1, 0); B (1, 2, 0); and C (0, 1, alpha).

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Practice Key Terms 6

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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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