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5. Skryf elk van die volgende as algebraïese vergelykings en los op.

5.1 Nege keer ’n sekere getal is 28 meer as vyf keer die getal. Wat is die getal?


5.2 ’n Reghoek, waarvan die omtrek 108 cm is, se lengte is vier meer as die breedte. Bereken:

5.2.1 die lengte en breedte


5.2.2 die oppervlakte van die reghoek


6. Die som van vier opeenvolgende onewe getalle is 112.Bepaal die vier getalle.


7. ’n Boek word oopgemaak, en die produk van die bladsynommer van die linkerblad en die van die regterblad, word bepaal. Die produk is 6 162.Wat is die linkerblad se nommer?


Assessering van myself: deur myself: Assessering deur opvoeder:
Ek kan… 1 2 3 4 Kritieke Uitkomste 1 2 3 4
’n vergelyking definieer; (Lu 1.2.1 ; 1.2.2); Kritiese en skeppende denke
eenvoudige vergelykings oplos d.m.v. inspeksie; (Lu 1.8 ; 2.5); Deelname
enige vergelyking oplos al is hakies teenwoordig; (Lu 1.8 ; 2.5); Organisering en bestuur
woordprobleme as vergelykings skryf en dit dan oplos; (Lu 1.8 ; 2.5; 2.8.6); Prosessering van inligting
ingewikkelde woordprobleme oplos. (Lu 1.8 ; 2.5 ; 2.8.6). Kommunikasie

goed gedeeltelik nie goed nie

Kommentaar deur die leerder: My plan van aksie: My punte:
Ek is besonder tevrede met die standaard van my werk. < Datum :
Ek is tevrede met die vordering van my werk. Uit:
Ek het hard gewerk, maar is nie tevrede met my prestasie nie. Leerder :
Ek het nie my beste gelewer nie. >
Kommentaar deur ouers: Kommentaar deur opvoeder:
Handtekening: Datum : Handtekening: Datum :

Toets: (Vergelykings)

Totaal: 45

1. Los op vir x :

1.1 x + 5 = 39 [2]

1.2 7 - 3 x = 1 [2]

1.3 2( x + 5) = 18 [3]

1.4 8 = 40 - 2 x [2]

1.5 2( x - 3) - ( x + 1) = 5 x - 4 [4]

1.6 3 x + 6 = 15 [2]

1.7 x 2 size 12{ { {x} over {2} } } {} = 4 [2]

1.8 2(3 x + 24) = 114 [3]

1.9 10 x + 9 = 7 x + 30 [3]

1.10 1 / 3 (3 x - 6) - 2( x + 1½) = 7 [4]


2. Los die volgende woordprobleme op:

2.1 As 5 van ’n sekere getal afgetrek word en die antwoord word deur 3 gedeel, is die antwoord 4. Bereken die getal.


2.2 Die som van drie opeenvolgende ewe getalle is 66. Bereken die drie getalle.


2.3 Die lengte van ’n reghoek is 5,5 cm langer as die breedte. As die omtrek van die reghoek 27 cm is, bereken die breedte.


2.4 Jonte se ouderdom is vyf keer die van sy dogter. As die som van hul ouderdomme 60 jaar is, hoe oud is die dogter?


2.5 Gareth is 5 keer so oud soos sy seun. Oor 5 jaar sal hy 3 keer so oud wees soos sy seun. Hoe oud is die seun nou?


3. Bonuspuntvraag

Gegee: 1 / 2 a + 2 a = 7

Bepaal die waarde van 1 4a 2 + 4a 2 size 12{ { {1} over {4a rSup { size 8{2} } } } `+`4a rSup { size 8{2} } } {}


Verrykingsoefening vir die vinnige werker

1. As die produk 2 12 x 5 8 ontwikkel word, hoeveel syfers sal daar in die antwoord wees?

2. 6² = 36. Hoeveel ander positiewe enkelsyfer getalle se kwadraat eindig in dieselfde syfer as die getal wat jy gekwadreer het?

3. Indien die driesyfer getal 2A3 by 326 getel word, gee dit 5T9. Indien 5T9 deelbaar is deur 9, dan is A + T gelyk aan ....

4. Indien ’n viersyfer getal wat met 34 begin, afgetrek word van ’n viersyfer getal wat met 199 begin, dan is die grootste moontlike antwoord ...

5. As jy 1,2,3,6 in elke moontlike volgorde skryf om 4-syfers getalle te vorm, hoeveel van hulle is deelbaar deur 4?

Questions & Answers

can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
Commplementary angles
Idrissa Reply
im all ears I need to learn
right! what he said ⤴⤴⤴
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
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Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
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Kristine 2*2*2=8
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Differences Between Laspeyres and Paasche Indices
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No. 7x -4y is simplified from 4x + (3y + 3x) -7y
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is it 3×y ?
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J, combine like terms 7x-4y
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how do you translate this in Algebraic Expressions
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Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
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Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
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In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
anybody can imagine what will be happen after 100 years from now in nano tech world
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
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silver nanoparticles could handle the job?
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Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
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Source:  OpenStax, Wiskunde graad 8. OpenStax CNX. Sep 11, 2009 Download for free at http://cnx.org/content/col11033/1.1
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