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Calculating rest energy: rest energy is very large

Calculate the rest energy of a 1.00-g mass.

Strategy

One gram is a small mass—less than half the mass of a penny. We can multiply this mass, in SI units, by the speed of light squared to find the equivalent rest energy.

Solution

  1. Identify the knowns. m = 1 .00 × 10 3 kg size 12{m=1 "." "00" times "10" rSup { size 8{ - 3} } `"kg"} {} ; c = 3 . 00 × 10 8 m/s size 12{c=3 "." "00" times "10" rSup { size 8{8} } `"m/s"} {}
  2. Identify the unknown. E 0 size 12{E rSub { size 8{0} } } {}
  3. Choose the appropriate equation. E 0 = mc 2 size 12{E rSub { size 8{0} } = ital "mc" rSup { size 8{2} } } {}
  4. Plug the knowns into the equation.
    E 0 = mc 2 = ( 1.00 × 10 3 kg ) ( 3.00 × 10 8 m/s ) 2 = 9.00 × 10 13 kg m 2 /s 2
  5. Convert units.

    Noting that 1 kg m 2 /s 2 = 1 J size 12{1`"kg" cdot m rSup { size 8{2} } "/s" rSup { size 8{2} } =1`J} {} , we see the rest mass energy is

    E 0 = 9 . 00 × 10 13 J . size 12{E rSub { size 8{0} } =9 "." "00" times "10" rSup { size 8{"13"} } `J} {}

Discussion

This is an enormous amount of energy for a 1.00-g mass. We do not notice this energy, because it is generally not available. Rest energy is large because the speed of light c size 12{c} {} is a large number and c 2 size 12{c rSup { size 8{2} } } {} is a very large number, so that mc 2 size 12{ ital "mc" rSup { size 8{2} } } {} is huge for any macroscopic mass. The 9 . 00 × 10 13 J size 12{9 "." "00" times "10" rSup { size 8{"13"} } `J} {} rest mass energy for 1.00 g is about twice the energy released by the Hiroshima atomic bomb and about 10,000 times the kinetic energy of a large aircraft carrier. If a way can be found to convert rest mass energy into some other form (and all forms of energy can be converted into one another), then huge amounts of energy can be obtained from the destruction of mass.

Today, the practical applications of the conversion of mass into another form of energy , such as in nuclear weapons and nuclear power plants, are well known. But examples also existed when Einstein first proposed the correct form of relativistic energy, and he did describe some of them. Nuclear radiation had been discovered in the previous decade, and it had been a mystery as to where its energy originated. The explanation was that, in certain nuclear processes, a small amount of mass is destroyed and energy is released and carried by nuclear radiation. But the amount of mass destroyed is so small that it is difficult to detect that any is missing. Although Einstein proposed this as the source of energy in the radioactive salts then being studied, it was many years before there was broad recognition that mass could be and, in fact, commonly is converted to energy. (See [link] .)

Part a of the figure shows a solar storm on the Sun. Part b of the figure shows the Susquehanna Steam Electric Station, which produces electricity by nuclear fission.
The Sun (a) and the Susquehanna Steam Electric Station (b) both convert mass into energy—the Sun via nuclear fusion, the electric station via nuclear fission. (credits: (a) NASA/Goddard Space Flight Center, Scientific Visualization Studio; (b) U.S. government)

Because of the relationship of rest energy to mass, we now consider mass to be a form of energy rather than something separate. There had not even been a hint of this prior to Einstein’s work. Such conversion is now known to be the source of the Sun’s energy, the energy of nuclear decay, and even the source of energy keeping Earth’s interior hot.

Stored energy and potential energy

What happens to energy stored in an object at rest, such as the energy put into a battery by charging it, or the energy stored in a toy gun’s compressed spring? The energy input becomes part of the total energy of the object and, thus, increases its rest mass. All stored and potential energy becomes mass in a system. Why is it we don’t ordinarily notice this? In fact, conservation of mass (meaning total mass is constant) was one of the great laws verified by 19th-century science. Why was it not noticed to be incorrect? The following example helps answer these questions.

Practice Key Terms 3

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Source:  OpenStax, General physics i phy2201ca. OpenStax CNX. Jul 03, 2013 Download for free at http://legacy.cnx.org/content/col11523/1.4
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