# 1.7 The complex numbers  (Page 3/3)

 Page 3 / 3

Suppose $C$ were an ordered field, and write $P$ for its set of positive elements. Then, since every square in an ordered field must be in $P$ (part (e) of [link] ), we must have that $-1={i}^{2}$ must be in $P.$ But, by part (a) of [link] , we also must have that 1 is in $P,$ and this leads to a contradiction of the law of tricotomy. We can't have both 1 and $-1$ in $P.$ Therefore, $C$ is not an ordered field.

Although we may not define when one complex number is smaller than another, we can define the absolute value of a complex number and the distance between two of them.

If $z=x+yi$ is in $C$ , we define the absolute value of $z$ by

$|z|=\sqrt{{x}^{2}+{y}^{2}}.$

We define the distance $d\left(z,w\right)$ between two complex numbers $z$ and $w$ by

$d\left(z,w\right)=|z-w|.$

If $c\in C$ and $r>0,$ we define the open disk of radius $r$ around c , and denote it by ${B}_{r}\left(c\right),$ by

${B}_{r}\left(c\right)=\left\{z\in C:|z-c|

The closed disk of radius $r$ around $c$ is denoted by ${\overline{B}}_{r}\left(c\right)$ and is defined by

${\overline{B}}_{r}\left(c\right)=\left\{z\in C:|z-c|\le r\right\}.$

We also define open and closed punctured disks ${B}_{r}^{\text{'}}\left(c\right)$ and ${\overline{B}}_{r}^{\text{'}}\left(c\right)$ around $c$ by

${B}_{r}^{\text{'}}\left(c\right)=\left\{z:0<|z-c|

and

${\overline{B}}_{r}^{\text{'}}\left(c\right)=\left\{z:0<|z-c\le r\right\}.$

These punctured disks are just like the regular disks, except that they do not contain the central point $c.$

More generally, if $S$ is any subset of $C,$ we define the open neighborhood of radius r around $S,$ denoted by ${N}_{r}\left(S\right),$ to be the set of all $z$ such that there exists a $w\in S$ for which $|z-w| That is, ${N}_{r}\left(S\right)$ is the set of all complex numbers that are within a distance of $r$ of the set $S.$ We define the closed neighborhood of radius $r$ around $S,$ and denote it by ${\overline{N}}_{r}\left(S\right),$ to be the set of all $z\in C$ for which there exists a $w\in S$ such that $|z-w|\le r.$

1. Prove that the absolute value of a complex number $z$ is a nonnegative real number. Show in addition that ${|z|}^{2}=z\overline{z}.$
2. Let $x$ be a real number. Show that the absolute value of $x$ is the same whether we think of $x$ as a real number or as a complex number.
3. Prove that $max\left(|\Re \left(z\right)|,|\Im \left(z\right)|\right)\le |z|\le |\Re \left(z\right)|+|\Im \left(z\right)|.$ Note that this just amounts to verifying that
$max\left(|x|,|y|\right)\le \sqrt{{x}^{2}+{y}^{2}}\le |x|+|y|$
for any two real numbers $x$ and $y.$
4. For any complex numbers $z$ and $w,$ show that $\overline{z+w}=\overline{z}+\overline{w},$ and that $\overline{\overline{z}}=z.$
5. Show that $z+\overline{z}=2\Re \left(z\right)$ and $z-\overline{z}=2i\Im \left(z\right).$
6. If $z=a+bi$ and $w={a}^{\text{'}}+{b}^{\text{'}}i,$ prove that $|zw|=|z||w|.$ HINT: Just compute $|\left(a+bi\right)\left({a}^{\text{'}}+{b}^{\text{'}}i\right){|}^{2}.$

The next theorem is in a true sense the most often used inequality of mathematical analysis. We have already proved the triangle inequality for the absolute value of real numbers, and the proof wasnot very difficult in that case. For complex numbers, it is not at all simple, and this should be taken as a good indication that it is a deep result.

## Triangle inequality

If $z$ and ${z}^{\text{'}}$ are two complex numbers, then

$|z+{z}^{\text{'}}|\le |z|+|{z}^{\text{'}}|$

and

$|z-{z}^{\text{'}}|\ge ||z|-|{z}^{\text{'}}||.$

We use the results contained in [link] .

$\begin{array}{ccc}\hfill |z+{z}^{\text{'}}{|}^{2}& =& \left(z+{z}^{\text{'}}\right)\overline{\left(z+{z}^{\text{'}}\right)}\hfill \\ & =& \left(z+{z}^{\text{'}}\right)\left(\overline{z}+\overline{{z}^{\text{'}}}\right)\hfill \\ & =& z\overline{z}+{z}^{\text{'}}\overline{z}+z\overline{{z}^{\text{'}}}+{z}^{\text{'}}\overline{{z}^{\text{'}}}\hfill \\ & =& {|z|}^{2}+{z}^{\text{'}}\overline{z}+\overline{{z}^{\text{'}}\overline{z}}+{|{z}^{\text{'}}|}^{2}\hfill \\ & =& {|z|}^{2}+2\Re \left({z}^{\text{'}}\overline{z}\right)+{|{z}^{\text{'}}|}^{2}\hfill \\ & \le & {|z|}^{2}+2|\Re \left({z}^{\text{'}}\overline{z}\right)|+|{z}^{\text{'}}{|}^{2}\hfill \\ & \le & {|z|}^{2}+2|{z}^{\text{'}}\overline{z}|+|{z}^{\text{'}}{|}^{2}\hfill \\ & =& {|z|}^{2}+2|{z}^{\text{'}}||z|+|{z}^{\text{'}}{|}^{2}\hfill \\ & =& \left(|z|+|{z}^{\text{'}}{|\right)}^{2}.\hfill \end{array}$

The Triangle Inequality follows now by taking square roots.

REMARK The Triangle Inequality is often used in conjunction with what's called the “add and subtract trick.”Frequently we want to estimate the size of a quantity like $|z-w|,$ and we can often accomplish this estimation by adding and subtracting the same thing within the absolute value bars:

$|z-w|=|z-v+v-w|\le |z-v|+|v-w|.$

The point is that we have replaced the estimation problem of the possibly unknown quantity $|z-w|$ by the estimation problems of two other quantities $|z-v|$ and $|v-w|.$ It is often easier to estimate these latter two quantities, usually by an ingenious choice of $v$ of course.

1. Prove the second assertion of the preceding theorem.
2. Prove the Triangle Inequality for the distance function. That is, prove that
$d\left(z,w\right)\le d\left(z,v\right)+d\left(v,w\right)$
for all $z,w,v\in C.$
3. Use mathematical induction to prove that
$|\sum _{i=1}^{n}{a}_{i}|\le \sum _{i=1}^{n}|{a}_{i}|.$

It may not be necessary to point out that part (b) of the preceding exercise provides a justification for the name “triangle inequality.”Indeed, part (b) of that exercise is just the assertion that the length of one side of a triangle in the plane is less than or equalto the sum of the lengths of the other two sides. Plot the three points $z,w,$ and $v,$ and see that this interpretation is correct.

A subset $S$ of $C$ is called Bounded if there exists a real number $M$ such that $|z|\le M$ for every $z$ in $S.$

1. Let $S$ be a subset of $C$ . Let ${S}_{1}$ be the subset of $R$ consisting of the real parts of the complex numbers in $S,$ and let ${S}_{2}$ be the subset of $R$ consisting of the imaginary parts of the elements of $S.$ Prove that $S$ is bounded if and only if ${S}_{1}$ and ${S}_{2}$ are both bounded.

HINT: Use Part (c) of [link] ..

2. Let $S$ be the unit circle in the plane, i.e., the set of all complex numbers $z=x+iy$ for which $|z|=1.$ Compute the sets ${S}_{1}$ and ${S}_{2}$ of part (a).

1. Verify that the formulas for the sum of a geometric progression and the binomial theorem ( [link] and [link] ) are valid for complex numbers $z$ and ${z}^{\text{'}}.$ HINT: Check that, as claimed, the proofs of those theorems work in any field.
2. Prove [link] for complex numbers $z$ and ${z}^{\text{'}}.$

Introduction about quantum dots in nanotechnology
what does nano mean?
nano basically means 10^(-9). nanometer is a unit to measure length.
Bharti
do you think it's worthwhile in the long term to study the effects and possibilities of nanotechnology on viral treatment?
absolutely yes
Daniel
how to know photocatalytic properties of tio2 nanoparticles...what to do now
it is a goid question and i want to know the answer as well
Maciej
Abigail
for teaching engĺish at school how nano technology help us
Anassong
Do somebody tell me a best nano engineering book for beginners?
there is no specific books for beginners but there is book called principle of nanotechnology
NANO
what is fullerene does it is used to make bukky balls
are you nano engineer ?
s.
fullerene is a bucky ball aka Carbon 60 molecule. It was name by the architect Fuller. He design the geodesic dome. it resembles a soccer ball.
Tarell
what is the actual application of fullerenes nowadays?
Damian
That is a great question Damian. best way to answer that question is to Google it. there are hundreds of applications for buck minister fullerenes, from medical to aerospace. you can also find plenty of research papers that will give you great detail on the potential applications of fullerenes.
Tarell
what is the Synthesis, properties,and applications of carbon nano chemistry
Mostly, they use nano carbon for electronics and for materials to be strengthened.
Virgil
is Bucky paper clear?
CYNTHIA
carbon nanotubes has various application in fuel cells membrane, current research on cancer drug,and in electronics MEMS and NEMS etc
NANO
so some one know about replacing silicon atom with phosphorous in semiconductors device?
Yeah, it is a pain to say the least. You basically have to heat the substarte up to around 1000 degrees celcius then pass phosphene gas over top of it, which is explosive and toxic by the way, under very low pressure.
Harper
Do you know which machine is used to that process?
s.
how to fabricate graphene ink ?
for screen printed electrodes ?
SUYASH
What is lattice structure?
of graphene you mean?
Ebrahim
or in general
Ebrahim
in general
s.
Graphene has a hexagonal structure
tahir
On having this app for quite a bit time, Haven't realised there's a chat room in it.
Cied
what is biological synthesis of nanoparticles
what's the easiest and fastest way to the synthesize AgNP?
China
Cied
types of nano material
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
what is nano technology
what is system testing?
how did you get the value of 2000N.What calculations are needed to arrive at it
Privacy Information Security Software Version 1.1a
Good
Berger describes sociologists as concerned with
Got questions? Join the online conversation and get instant answers!