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Wiskunde

Ontmoet vir bonnie en tommie

Opvoeders afdeling

Memorandum

Die module is opgestel volgens die Leeruitkomstes en Assesseringstandaarde soos vervat in die dokument, uitgegee deur die Nasionale Onderwysraad.

Die take en aktiwiteite is in lyn met die kurrikulum, maar dit kan nie die taak van die opvoeder, om te onderrig, vervang nie. Nuwe begrippe moet eers konkreet en deeglik onderrig word, voordat die take vir die leerder van enige nut kan wees.

Hierdie aktiwiteite kan gebruik word vir toepassing, konsolidering, vaslegging, verryking en assessering van werk wat vooraf onderrig is.

Onderaan elke bladsy van die leerders, verskyn die nommer van die leeruitkoms wat op die betrokke bladsy ter sprake is. Die nommers is in ooreenstemming met dié van die raamwerk voor in elke leereenheid. Hierby is ook ‘n ruit, vir onmiddellike assessering, aangebring. Aan die einde van die module verskyn die assesseringsruit waar ‘n gemiddelde punt vir die betrokke module bereken en aangedui kan word.

Dit mag wees dat die “vinnige” leerders baie vinnig deur ‘n module sal gaan, in watter geval van soortgelyke aktiwiteite gebruik gemaak kan word. Dit is dus dringend noodsaaklik dat die opvoeder deeglik bewus sal wees van die inhoud van elke taak, alvorens dit aan die leerders gegee word.

Sommige opdragte en take vereis ook vooraf beplanning deur die opvoeder . Om die taak van die opvoeder te vergemaklik, is daar inligting op die bladsye genommer O - 1 tot O - 7 aangeheg. Hierdie bladsye word nie aan die leerders uitgedeel nie.

Die opvoeder moet die leerders help om die inligting van hul verjaardae in die klas te bekom sodat hulle die blokgrafiek kan voltooi.

Laat die leerders hulle hande opsteek in die maand waarin hulle verjaar en tel dan hoeveel daar in elke maand is. Hierdie inligting skryf die leerder dan in die sirkel bokant elke maand,

bv. 3 kinders verjaar in Januarie. Die 3 word in die sirkel reg bokant Jan . geskryf.

Hierdie taak kan al die leerders gelyktydig doen.

Dit is ook ‘n goeie geleentheid om nou die name van die maande in die regte volgorde aan te leer. Dit is nie nodig dat hulle dit in hierdie stadium moet kan skryf nie.

Gee die leerders genoeg tyd om hul bevindings, afleidings en gevolgtrekkings na die voltooiing van die blokgrafiek te bespreek.

Wanneer met bewerkings begin word, sal dit goed wees om die leerders bewus te maak dat die 4 bewerkings (optel, vermenigvuldig, aftrek en deel) slegs 2 verskillende prosesse behels:

Kyk na Hoe meer die leerder hierdie voorstelling sien en die verduideliking hoor , hoe beter sal hy dit begryp en kan toepas by die oplossing van probleme.

Die leerders moet die kommutatiewe eienskap van optelling ( 3 + 4 = 7 en4 + 3 = 7 ) en vermenigvuldiging ( 2 x 5 = 10 en 5 x 2 = 10 ) verstaan, maar hy hoef nie die woorde “ kommutatiewe eienskap ” te ken of te gebruik nie.

Die leerder moet die assosiatiewe eienskap van aftrekking(9 – 4 = 5 en 9 - 5 = 4 ) en deling ( 10  2 = 5 en 10  5 = 2 ) verstaan.

Leerders moet eers met konkrete voorwerpe ervaar hoe die antwoorde van die aftrekbewerkings getoets kan word: bring terug wat jy weggeneem het en as jy weer die getal waarmee jy begin het, kry, dan weet jy dit is reg.

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
Abhi
how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
hmm
Abhi
is it a question of log
Abhi
🤔.
Abhi
I rally confuse this number And equations too I need exactly help
salma
But this is not salma it's Faiza live in lousvile Ky I garbage this so I am going collage with JCTC that the of the collage thank you my friends
salma
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
hi
salma
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Wiskunde graad 3. OpenStax CNX. Oct 14, 2009 Download for free at http://cnx.org/content/col11129/1.1
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