# 1.3 Labworks  (Page 11/11)

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• x, y coordinates
• a constructor with two parameters representing x, y coordinates (their default values are allowed to be 0)
• a member function named display, which prints out two coordinates on the screen.
• A member function named getInfo, which accepts two input data from the user for x, y coordinates.
• Two member functions named setX, setY to update values to x, y, respectively.
• Two member functions named getX, getY to retrieve values from x, y, respectively.
• A member function named distance, which accepts as parameter an object of class CPoint and calculates the distance from the object invoking the function to the parameter object.

b. Construct a derived class named CPoint_3D from the class CPoint, described as follows:

• There is one more data member: coordinate z.
• There are overriding member functions in CPoint_3D for all corresponding member functions in the class CPoint.

c. Include the class constructed in a) and b) in a working C++ program. Have your program call all of the member functions in the CPoint_3D class.

## Project 1

This project aims to review all the chapters from Chapter 1 (Introduction to Computers and Programming) to Chapter 6 (Functions and Pointers) which focus on structured programming.

An example of Project 1 can be described as follows:

The Colossus Airlines fleet consists of one plane with a seating capacity of 12. It makes one flight daily. Write a seating reservation program with the following features:

• The program uses an array of 12 structures. Each structure should hold a seat identification number, a marker that indicates whether the seat is assigned and the name of the seat holder. Assume that the name of a customer is not more than 20 characters long.
• The program displays the following menu with six choices:
• Show the number of empty seats
• Show the list of empty seats.
• Show the list of customers together with their seat numbers in the order of the seat numbers
• Assign a customer to a seat
• Remove a seat assignment
• Quit
• The program successfully executes the promises of its menu. Choices (4) and (5) need additional input from the user which is done inside the respective functions.
• After executing a particular function, the program shows the menu again, except for choice (6).

## Project 2

This project aims to review all the chapters from Chapter 7 (Introduction to Classes) to Chapter 8 (Object Manipulation - Inheritance) which focus on the basics of object-oriented programming.

An example of Project 2 can be described as follows:

A stack is an ordered collection of data items in which access is possible only at one end, called the top of the stack with the following basic operations:

• Push: add an element to the top of the stack.
• Pop: remove and return the top element of the stack.
• Check if the stack is empty
• Check if the stack is full.

It would be nice to have a stack class, because we could then use it to easily develop some applications which need stack data structure.

For the moment, assume that we need to define an integer stack class. Since a stack must stores a collection of integers, we can use an integer array to model the stack and a “pointer” named Top to indicate the location of the top of the stack. The array should have a fixed size. So we can begin the declaration of the class by selection two data members:

• Provide an integer array data member to hold the stack elements (the size of the array is a constant).
• Provide an integer data member to indicate the top of the stack.

As for the member functions of the stack class, we have to define 5 member functions: the constructor which creates an empty stack and four other member functions (push, pop, check if the stack is empty, check if the stack is full).

After defining the stack class, write a main() function which does the following tasks:

• Creating one stack object.
• Pushing into the stack object ten integer elements which take values from 1 to 10 with the increment of 1.
• Popping one by one element from the stack object and displaying it out, repeating this action until the stack becomes empty.

Next, apply the stack data structure in solving the following problem: write a program that accepts a string from the user and prints the string backward. (Hint: Use a character stack)

find the 15th term of the geometric sequince whose first is 18 and last term of 387
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
hmm well what is the answer
Abhi
how do they get the third part x = (32)5/4
can someone help me with some logarithmic and exponential equations.
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
hmm
Abhi
is it a question of log
Abhi
🤔.
Abhi
I rally confuse this number And equations too I need exactly help
salma
But this is not salma it's Faiza live in lousvile Ky I garbage this so I am going collage with JCTC that the of the collage thank you my friends
salma
Commplementary angles
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
hi
salma
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
a perfect square v²+2v+_
kkk nice
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
rolling four fair dice and getting an even number an all four dice
Kristine 2*2*2=8
Differences Between Laspeyres and Paasche Indices
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
how do you translate this in Algebraic Expressions
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
what's the easiest and fastest way to the synthesize AgNP?
China
Cied
types of nano material
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
what is nano technology
what is system testing?
preparation of nanomaterial
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
what is system testing
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
how did you get the value of 2000N.What calculations are needed to arrive at it
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