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This module is from Fundamentals of Mathematics by Denny Burzynski and Wade Ellis, Jr. This module discusses how to add signed numbers. By the end of the module students should be able to add numbers with like signs and with unlike signs and be able to use the calculator for addition of signed numbers.

Section overview

  • Addition of Numbers with Like Signs
  • Addition with Zero
  • Addition of Numbers with Unlike Signs
  • Calculators

Addition of numbers with like signs

The addition of the two positive numbers 2 and 3 is performed on the number line as follows.

Begin at 0, the origin.

Since 2 is positive, move 2 units to the right.

Since 3 is positive, move 3 more units to the right.

We are now located at 5.

A number line with has marks for the numbers -2 to 7. An arrow is drawn from 0 to 2, and from 2 to 5.

Thus, 2 + 3 = 5 size 12{"2 "+" 3 "=" 5"} {} .

Summarizing, we have

( 2 positive units ) + ( 3 positive units ) = ( 5 positive units ) size 12{ \( "2 positive units" \) + \( "3 positive units" \) = \( "5 positive units" \) } {}

The addition of the two negative numbers -2 and -3 is performed on the number line as follows.

Begin at 0, the origin.

Since -2 is negative, move 2 units to the left.

Since -3 is negative, move 3 more units to the left.

We are now located at -5.

A number line with has marks for the numbers -7 to 2. An arrow is drawn from 0 to -2, and from -2 to -5.

Thus, ( 2 ) + ( 3 ) = 5 size 12{ \( - 2 \) + \( - 3 \) = - 5} {} .

Summarizing, we have

( 2 negative units ) + ( 3 negative units ) = ( 5 negative units ) size 12{ \( "2 negative units" \) + \( "3 negative units" \) = \( "5 negative units" \) } {}

Observing these two examples, we can suggest these relationships:

( positive number ) + ( positive number ) = ( positive number ) size 12{ \( "positive number" \) + \( "positive number" \) = \( "positive number" \) } {}

( negative number ) + ( negative number ) = ( negative number ) size 12{ \( "negative number" \) + \( "negative number" \) = \( "negative number" \) } {}

Adding numbers with the same sign

Addition of numbers with like sign:
To add two real numbers that have the same sign, add the absolute values of the numbers and associate with the sum the common sign.

Sample set a

Find the sums.

3 + 7 size 12{3+7} {}

| 3 | = 3 | 7 | = 7 Add these absolute values.

3 + 7 = 10

The common sign is “+.”

Thus, 3 + 7 = + 10 size 12{"3 "+" 7 "= +"10"} {} , or 3 + 7 = 10 size 12{"3 "+" 7 "=" 10"} {} .

( 4 ) + ( 9 ) size 12{ \( - 4 \) + \( - 9 \) } {}

| - 4 | = 4 | - 9 | = 9 Add these absolute values.

4 + 9 = 13

The common sign is “ - .“

Thus, ( 4 ) + ( 9 ) = 13 size 12{ \( - 4 \) + \( - 9 \) = - "13"} {} .

Practice set a

Find the sums.

8 + 6 size 12{"8 "+" 6"} {}

14

41 + 11 size 12{"41 "+" 11"} {}

52

( - 4 ) + ( - 8 ) size 12{ \( "-4" \) + \( "–8" \) } {}

-12

36 + 9 size 12{ left ( - "36" right )+ left ( - 9 right )} {}

-45

14 + 20 size 12{ - "14"+ left ( - "20" right )} {}

-34

2 3 + 5 3 size 12{ - { {2} over {3} } + left ( - { {5} over {3} } right )} {}

7 3 size 12{- { {7} over {3} } } {}

- 2 . 8 + ( - 4 . 6 ) size 12{"–2" "." 8+ \( " –4" "." 6 \) } {}

7 . 4 size 12{-7 "." 4} {}

0 + ( 16 ) size 12{0+ \( - "16" \) } {}

16 size 12{-"16"} {}

Addition with zero

Addition with zero

Notice that
( 0 ) + ( a positive number ) = ( that same positive number ) size 12{ \( 0 \) + \( "a positive number" \) = \( "that same positive number" \) } {} .
( 0 ) + ( a negative number ) = ( that same negative number ) size 12{ \( 0 \) + \( "a negative number" \) = \( "that same negative number" \) } {} .

The additive identity is zero

Since adding zero to a real number leaves that number unchanged, zero is called the additive identity .

Addition of numbers with unlike signs

The addition 2 + ( - 6 ) size 12{"2 "+ \( " –6" \) } {} , two numbers with unlike signs , can also be illustrated using the number line.

Begin at 0, the origin.

Since 2 is positive, move 2 units to the right.

Since -6 is negative, move, from 2, 6 units to the left.

We are now located at -4.

A number line with has marks for the numbers -5 to 4. An arrow is drawn from 2 to -4, and from 0 to 2.

We can suggest a rule for adding two numbers that have unlike signs by noting that if the signs are disregarded, 4 can be obtained by subtracting 2 from 6. But 2 and 6 are precisely the absolute values of 2 and -6. Also, notice that the sign of the number with the larger absolute value is negative and that the sign of the resulting sum is negative.

Adding numbers with unlike signs

Addition of numbers with unlike signs: To add two real numbers that have unlike signs , subtract the smaller absolute value from the larger absolute value and associate with this difference the sign of the number with the larger absolute value.

Sample set b

Find the following sums.

7 + ( - 2 ) size 12{"7 "+ \( "–2" \) } {}

| 7 | = 7 Larger absolute value. Sign is positive.       | - 2 | = 2 Smaller absolute value.

Subtract absolute values: 7 - 2 = 5 size 12{"7 – 2 "=" 5"} {} .

Attach the proper sign: "+."

Thus, 7 + ( - 2 ) = + 5 size 12{"7 "+ \( "–2" \) = +5} {} or 7 + ( - 2 ) = 5 size 12{"7 "+ \( " –2" \) =" 5"} {} .

3 + ( - 11 ) size 12{"3 "+ \( "–11" \) } {}

| 3 | = 3 Smaller absolute value.       | - 11 | = 11 Larger absolute value. Sign is negative.

Subtract absolute values: 11 - 3 = 8 size 12{"11 – 3 "=" 8"} {} .

Attach the proper sign: " - ."

Thus, 3 + ( - 11 ) = - 8 size 12{3+ \( "–11" \) =" –8"} {} .

The morning temperature on a winter's day in Lake Tahoe was -12 degrees. The afternoon temperature was 25 degrees warmer. What was the afternoon temperature?

We need to find - 12 + 25 size 12{"–12 "+" 25"} {} .

| - 12 | = 12 Smaller absolute value.       | 25 | = 25 Larger absolute value. Sign is positive.

Subtract absolute values: 25 - 12 = 16 size 12{"25 – 12 "=" 16"} {} .

Attach the proper sign: "+."

Thus, - 12 + 25 = 13 size 12{"–12 "+" 25 "=" 13"} {} .

Practice set b

Find the sums.

4 + ( - 3 ) size 12{"4 "+ \( "–3" \) } {}

1

3 + 5 size 12{ - 3+5} {}

2

15 + ( 18 ) size 12{"15"+ \( - "18" \) } {}

-3

0 + ( 6 ) size 12{0+ \( - 6 \) } {}

-6

26 + 12 size 12{ - "26"+"12"} {}

-14

35 + ( 78 ) size 12{"35"+ \( - "78" \) } {}

-43

15 + ( - 10 ) size 12{"15 "+ \( "–10" \) } {}

5

1 . 5 + ( 2 ) size 12{1 "." 5+ \( - 2 \) } {}

-0.5

8 + 0 size 12{ - 8+0} {}

-8

0 + ( 0 . 57 ) size 12{"0 "+ \( 0 "." "57" \) } {}

0.57

879 + 454 size 12{ - "879"+"454"} {}

-425

Calculators

Calculators having the A square with a plus and minus sign. key can be used for finding sums of signed numbers.

Sample set c

Use a calculator to find the sum of -147 and 84.

Display Reads
Type 147 147
Press A square with a plus and minus sign. -147 This key changes the sign of a number. It is different than - .
Press + -147
Type 84 84
Press = -63

Practice set c

Use a calculator to find each sum.

673 + ( - 721 ) size 12{"673 "+ \( "–721" \) } {}

-48

- 8,261 + 2,206 size 12{"–8,261 "+" 2,206"} {}

-6,085

- 1,345 . 6 + ( - 6,648 . 1 ) size 12{"–1,345" "." 6+ \( "–6,648" "." 1 \) } {}

-7,993.7

Exercises

Find the sums in the following 27 problems. If possible, use a calculator to check each result.

4 + 12 size 12{4+"12"} {}

16

8 + 6 size 12{8+6} {}

3 + 12 size 12{ left (-3 right )+ left (-"12" right )} {}

-15

6 + 20 size 12{ left (-6 right )+ left (-"20" right )} {}

10 + 2 size 12{"10"+ left (-2 right )} {}

8

8 + 15 size 12{8+ left (-"15" right )} {}

16 + 9 size 12{-"16"+ left (-9 right )} {}

-25

22 + 1 size 12{-"22"+ left (-1 right )} {}

0 + 12 size 12{0+ left (-"12" right )} {}

-12

0 + 4 size 12{0+ left (-4 right )} {}

0 + 24 size 12{0+ left ("24" right )} {}

24

6 + 1 + 7 size 12{-6+1+ left (-7 right )} {}

5 + 12 + 4 size 12{-5+ left (-"12" right )+ left (-4 right )} {}

-21

5 + 5 size 12{-5+5} {}

7 + 7 size 12{-7+7} {}

0

14 + 14 size 12{-"14"+"14"} {}

4 + 4 size 12{4+ left (-4 right )} {}

0

9 + 9 size 12{9+ left (-9 right )} {}

84 + 61 size 12{"84"+ left (-"61" right )} {}

23

13 + 56 size 12{"13"+ left (-"56" right )} {}

452 + 124 size 12{"452"+ left (-"124" right )} {}

328

636 + 989 size 12{"636"+ left (-"989" right )} {}

1, 811 + ( 935 ) size 12{1,"811"+ \( -"935" \) } {}

876

373 + 14 size 12{-"373"+ left (-"14" right )} {}

1, 211 + 44 size 12{-1,"211"+ left (-"44" right )} {}

-1,255

47 . 03 + 22 . 71 size 12{-"47" "." "03"+ left (-"22" "." "71" right )} {}

1 . 998 + 4 . 086 size 12{-1 "." "998"+ left (-4 "." "086" right )} {}

-6.084

In order for a small business to break even on a project, it must have sales of $21,000. If the amount of sales was $15,000, by how much money did this company fall short?

Suppose a person has $56 in his checking account. He deposits $100 into his checking account by using the automatic teller machine. He then writes a check for $84.50. If an error causes the deposit not to be listed into this person’s account, what is this person’s checking balance?

-$28.50

A person borrows $7 on Monday and then $12 on Tuesday. How much has this person borrowed?

A person borrows $11 on Monday and then pays back $8 on Tuesday. How much does this person owe?

$3.00

Exercises for review

( [link] ) Find the reciprocal of 8 5 6 size 12{8 { {5} over {6} } } {} .

( [link] ) Find the value of 5 12 + 7 18 1 3 size 12{ { {5} over {"12"} } + { {7} over {"18"} } - { {1} over {3} } } {} .

17 36 size 12{ { {"17"} over {"36"} } } {}

( [link] ) Round 0.01628 to the nearest tenth.

( [link] ) Convert 62% to a fraction.

62 100 = 31 50 size 12{ { {"62"} over {"100"} } = { {"31"} over {"50"} } } {}

( [link] ) Find the value of 12 size 12{ lline -"12" rline } {} .

Questions & Answers

can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
Commplementary angles
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The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
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At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
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Source:  OpenStax, Algebra i for the community college. OpenStax CNX. Dec 19, 2014 Download for free at http://legacy.cnx.org/content/col11598/1.3
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