<< Chapter < Page Chapter >> Page >


‘n Leerprogram vir Graad R

Module 2






Hierdie program se aktiwiteite is ontwerp in ooreenstemming met die vereistes van uitkomsgebaseerde onderwys. Dit voorsien dus aan leerders geleenthede om hulle volle potensiaal te ontwikkel sodat hulle aktiewe, verantwoordelike, vervulde burgers kan word in ‘n demokratiese, nie-rassistiese en gelyke gemeenskap. Graad R vorm die brug tussen die leerder se voorskoolse ervarings en die formele skoolstelsel. Graad R-opvoeders benut leeruitkomste en die gepaardgaande assesseringstandaarde om in hulle leerders se besondere behoeftes te voorsien. Aan die hand daarvan beplan hulle dan leergeleenthede en –aktiwiteite waardeur die leerders hierdie uitkomste bereik.

Die aktiwiteite in hierdie program is

  • algemene aktiwiteite wat gerig is op die stimulasie van die basiese komponente van ontwikkeling; dit is die voorvereistes vir dink en leer;
  • spesifieke aktiwiteite wat toegepas word op die onderskeie leerareas (Geletterdheid, Wiskunde, Lewensvaardighede).

Die program is verdeel in vyf modules . Die tempo waarteen die leerders die eerste vier modules voltooi, word deur die opvoeder bepaal. Die vyfde module is ‘n verrykingsmodule wat na goeddunke deur die opvoeder benut kan word, maar is nie geskik vir alle leerders nie. Elke module sluit alle areas van ontwikkeling in en toon ‘n toenemende moeilikheidsgraad (dus, van maklik na moeilik).

Op elke werkblad word die leerarea in die blokkie linksbo aangedui, terwyl die voorvereistes vir dink en leer in die regterkantse blokkie aangedui word. Onderaan die werksblad is spesifieke vrae vir oorbrugging en assessering.


Die assesseringstandaarde wat betrekking het op die leerinhoud van elke module, word saam met die betrokke leeruitkomste in die moduleraamwerk van elke module aangedui, asook aan die begin van elke leereenheid. Sodoende kan nie net die opvoeder nie, maar ook die leerder en sy / haar ouerskennis neem volgens watter standaarde die leerder deurlopend geassesseer word. Elke aktiwiteit en opdrag in ‘n leereenheid kan geassesseer word. Die gemiddelde punt van die aktiwiteite wat betrekking het op elke leeruitkomste, word dan aangedui in die assesseringsruit wat die leerder se bekwaamheidsprofiel aandui aan die einde van elke leereenheid.

Assessering word volgens ‘n 4-puntskaal gedoen , naamlik

1: voldoen nie aan die vereistes nie;

2: voldoen gedeeltelik aan die vereistes;

3: voldoen aan die vereistes;

4: oorskry die vereistes.

Bo-aan elke werkblad is ‘n assesseringsblokkie wat die leerarea aandui, asook die leeruitkomste (sien voorbeeld bo-aan die volgende bladsy). Dit beteken dat die aktiwiteit na aanleiding van die betrokke leeruitkoms geassesseer moet word. Die opvoeder assesseer die leerder se respons en merk dit op die 4-puntskaal af.


Gesyferdheid: LU 1

Aan die einde van elke module is ‘n assesseringsblad waarop ‘n assesseringsruit vir elk van die 3 leerareas verskyn, naamlik Geletterdheid, Wiskunde en Lewensvaardighede. Die opvoeder neem die resultate in die voorafgaande assesseringsblokkies in ag en poog dus om die leerder se gemiddelde prestasie oor die langer tydperk aan te dui op die assesseringsruit. Op hierdie wyse word verseker dat die opvoeder se assessering verantwoordbaar is.

Questions & Answers

can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
Commplementary angles
Idrissa Reply
im all ears I need to learn
right! what he said ⤴⤴⤴
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
im not good at math so would this help me
Rachael Reply
I'm not good at math so would you help me
what is the problem that i will help you to self with?
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
many many of nanotubes
what is the k.e before it land
what is the function of carbon nanotubes?
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
what is system testing
what is the application of nanotechnology?
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
anybody can imagine what will be happen after 100 years from now in nano tech world
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
silver nanoparticles could handle the job?
not now but maybe in future only AgNP maybe any other nanomaterials
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
Privacy Information Security Software Version 1.1a
Got questions? Join the online conversation and get instant answers!
QuizOver.com Reply

Get the best Algebra and trigonometry course in your pocket!

Source:  OpenStax, Graad r 'n leerprogram. OpenStax CNX. Oct 28, 2009 Download for free at http://cnx.org/content/col11134/1.1
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Graad r 'n leerprogram' conversation and receive update notifications?