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PROBLEMS

This lecture note is based on the textbook # 1. Electric Machinery - A.E. Fitzgerald, Charles Kingsley, Jr., Stephen D. Umans- 6th edition- Mc Graw Hill series in Electrical Engineering. Power and Energy

1.1 A magnetic circuit with a single air gap is shown in Fig.1.1. The core dimensions are:

Cross-sectional area Ac = 1 . 8x 10 3 m 2 size 12{1 "." 8x"10" rSup { size 8{ - 3} } m rSup { size 8{2} } } {}

Mean core length lc = 0.6 m

Gap length g = 2.3 x 10 3 size 12{"10" rSup { size 8{ - 3} } } {} m

N = 83 turns

Figure 1.1 Magnetic circuit.

Assume that the core is of infinite permeability ( μ size 12{μ rightarrow infinity } {} ) and neglect the effects of fringing fields at the air gap and leakage flux. (a) Calculate the reluctance of the core R C size 12{R rSub { size 8{C} } } {} and that of the gap R g size 12{R rSub { size 8{g} } } {} . For a current of i = 1.5 A, calculate (b) the total flux φ size 12{φ} {} , (c) the flux linkages ) λ size 12{λ} {} of the coil, and (d) the coil inductance L.

1.2 Repeat Problem 1.1 for a finite core permeability of μ = 2500 μ 0 size 12{μ="2500"μ rSub { size 8{0} } } {} .

1.3 Consider the magnetic circuit of Fig.1.1 with the dimensions of Problem1.1. Assuming infinite core permeability, calculate (a) the number of turns required to achieve an inductance of 12 mH and (b) the inductor current which will result in a core flux density of 1.0 T.

1.4 Repeat Problem 1.3 for a core permeability of μ = 1300 μ 0 size 12{μ="1300"μ rSub { size 8{0} } } {} .

1.5 The magnetic circuit of Problem 1.1 has a nonlinear core material whose permeability as a function of B m size 12{B rSub { size 8{m} } } {} is given by

μ = μ o 1 + 3499 1 + 0 . 047 ( B m ) 7 . 8 size 12{μ=μ rSub { size 8{o} } left [1+ { {"3499"} over { sqrt {1+0 "." "047" \( B rSub { size 8{m} } \) rSup { size 8{7 "." 8} } } } } right ]} {}

where B m size 12{B rSub { size 8{m} } } {} is the material flux density.

a. Using MATLAB, plot a dc magnetization curve for this material ( B m size 12{B rSub { size 8{m} } } {} vs. H m size 12{H rSub { size 8{m} } } {} ) over the range 0 B size 12{<= B<= {}} {} 2.2 T.

b. Find the current required to achieve a flux density of 2.2 T in the core.

c. Again, using MATLAB, plot the coil flux linkages as a function of coil current as the current is varied from 0 to the value found in part (b).

1.6 The magnetic circuit of Fig.1.2 consists of a core and a moveable plunger of width l p size 12{l rSub { size 8{p} } } {} , each of permeability . The core has cross-sectional area Ac and mean length . The overlap area of the two air gaps Ag is a function of the plunger position x and can be assumed to vary as

A g = A c 1 x X 0 size 12{A rSub { size 8{g} } =A rSub { size 8{c} } left [1 - { {x} over {X rSub { size 8{0} } } } right ]} {}

You may neglect any fringing fields at the air gap and use approximations consistent with magnetic-circuit analysis.

a. Assuming that μ size 12{μ rightarrow infinity } {} , derive an expression for the magnetic flux density in the air gap B g size 12{B rSub { size 8{g} } } {} as a function of the winding current I and as the

Figure 1.2 Magnetic circuit for Problem 1.6.

plunger position is varied ( 0 x 0 . 8X 0 size 12{0<= x<= 0 "." 8X rSub { size 8{0} } } {} ). What is the corresponding flux density in the core?

b. Repeat part (a) for a finite permeability μ size 12{μ} {} .

1.7 The magnetic circuit of Fig.1.2 and Problem 1.6 has the following dimensions"

A C = 8 . 2 cm 2 size 12{A rSub { size 8{C} } =8 "." 2 ital "cm" rSup { size 8{2} } } {} l C = 23 cm size 12{l rSub { size 8{C} } ="23" ital "cm"} {}

l p = 2 . 8 cm size 12{l rSub { size 8{p} } =2 "." 8 ital "cm"} {} g = 0.8 mm

X 0 size 12{X rSub { size 8{0} } } {} = 2.5 cm N = 430 turns

a. Assuming a constant permeability of μ = 2800 μ 0 size 12{μ="2800"μ rSub { size 8{0} } } {} , calculate the current required to achieve a flux density of 1.3T in the air gap when the plunger is fully retracted (x =0).

b. Repeat the calculation of part (a) for the case in which the core and plunger are composed of a nonlinear material whose permeability is given by

μ = μ 0 1 + 1199 1 + 0 . 05 B m 8 size 12{μ=μ rSub { size 8{0} } left [1+ { {"1199"} over { sqrt {1+0 "." "05"B rSub { size 8{m} } rSup { size 8{8} } } } } right ]} {}

where B m size 12{B rSub { size 8{m} } } {} is the magnetic flux density in the material.

c. For the nonlinear material of part (b), use MATLAB to plot the air-gap flux density as a function of winding current for x = 0 and x = 0.5 X 0 size 12{X rSub { size 8{0} } } {} .

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Source:  OpenStax, Electrical machines. OpenStax CNX. Jul 29, 2009 Download for free at http://cnx.org/content/col10767/1.1
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