Consider the
$1\phantom{\rule{2pt}{0ex}}\mathrm{kg}$ suitcase on the cupboard that was discussed earlier. When the suitcase falls, it will gain velocity (fall faster), until it reaches the ground with a maximum velocity. The suitcase will not have any kinetic energy when it is on top of the cupboard because it is not moving. Once it starts to fall it will gain kinetic energy, because it gains velocity. Its kinetic energy will increase until it is a maximum when the suitcase reaches the ground.
A
$1\phantom{\rule{2pt}{0ex}}\mathrm{kg}$ brick falls off a
$4\phantom{\rule{2pt}{0ex}}m$ high roof. It reaches the ground with a velocity of
$\mathrm{8,85}\phantom{\rule{2pt}{0ex}}m\xb7s{}^{-1}$ . What is the kinetic energy of the brick when it starts to fall and when it reaches the ground?
The mass of the rock
$m=1\phantom{\rule{2pt}{0ex}}\mathrm{kg}$
The velocity of the rock at the bottom
${v}_{\mathrm{bottom}}=\mathrm{8,85}\phantom{\rule{2pt}{0ex}}m\xb7$ s
${}^{-1}$
These are both in the correct units so we do not have to worry about unit
conversions.
We are asked to find the kinetic energy of the brick at the top and the bottom. From the definition we know that to work out
$KE$ , we need to know the mass and the velocity of the object and we are given both of these values.
Since the brick is not moving at the top, its kinetic energy is zero.
According to the equation for kinetic energy, the unit should be
$\mathrm{kg}\xb7m{}^{2}\xb7s{}^{-2}$ . We can prove that this unit is equal to the joule, the unit for energy.
A bullet, having a mass of
$150\phantom{\rule{2pt}{0ex}}g$ , is shot with a muzzle velocity of
$960\phantom{\rule{2pt}{0ex}}m\xb7s{}^{-1}$ . Calculate its kinetic energy.
We are given the mass of the bullet
$m=150\phantom{\rule{2pt}{0ex}}g$ . This is not the
unit we want mass to be in. We need to convert to kg.
We are given the initial velocity with which the bullet leaves the barrel, called the muzzle velocity, and it is
$v=960\phantom{\rule{2pt}{0ex}}m\xb7s{}^{-1}$ .
We are asked to find the kinetic energy.
We just substitute the mass and velocity (which are known) into the equation for kinetic energy:
Describe the relationship between an object's kinetic energy and its:
mass and
velocity
A stone with a mass of
$100\phantom{\rule{2pt}{0ex}}g$ is thrown up into the air. It has an initial velocity of
$3\phantom{\rule{2pt}{0ex}}m\xb7s{}^{-1}$ . Calculate its kinetic energy
as it leaves the thrower's hand.
when it reaches its turning point.
A car with a mass of
$700\phantom{\rule{2pt}{0ex}}\mathrm{kg}$ is travelling at a constant velocity of
$100\phantom{\rule{2pt}{0ex}}\mathrm{km}\xb7\mathrm{hr}{}^{-1}$ . Calculate the kinetic energy of the car.
Mechanical energy
Mechanical energy is the sum of the gravitational potential energy and the kinetic energy.
Mechanical energy,
$U$ , is simply the sum of gravitational potential energy (
$PE$ ) and the kinetic energy (
$KE$ ). Mechanical energy is defined as:
fullerene is a bucky ball aka Carbon 60 molecule. It was name by the architect Fuller. He design the geodesic dome. it resembles a soccer ball.
Tarell
what is the actual application of fullerenes nowadays?
Damian
That is a great question Damian. best way to answer that question is to Google it. there are hundreds of applications for buck minister fullerenes, from medical to aerospace. you can also find plenty of research papers that will give you great detail on the potential applications of fullerenes.
Tarell
what is the Synthesis, properties,and applications of carbon nano chemistry
Yeah, it is a pain to say the least. You basically have to heat the substarte up to around 1000 degrees celcius then pass phosphene gas over top of it, which is explosive and toxic by the way, under very low pressure.
Harper
Do you know which machine is used to that process?