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A brief introduction on how to filter digital signals

Because of the Sampling Theorem , we can process, in particular filter, analog signals "with a computer" by constructing the system shown in [link] . To use this system, we are assuming that the input signal has a lowpass spectrum andcan be bandlimited without affecting important signal aspects. Bandpass signals can also be filtered digitally, but require amore complicated system. Highpass signals cannot be filtered digitally. Note that the input and output filters must be analogfilters; trying to operate without them can lead to potentially very inaccurate digitization.

To process an analog signal digitally, the signal x t must be filtered with an anti-aliasing filter (to ensure a bandlimited signal) before A/D conversion. This lowpassfilter (LPF) has a cutoff frequency of W Hz, which determines allowable sampling intervals T s . The greater the number of bits in the amplitude quantization portion Q · of the A/D converter, the greater the accuracy of the entire system. Theresulting digital signal x n can now be filtered in the time-domain with a difference equation or in the frequency domain with Fouriertransforms. The resulting output y n then drives a D/A converter and a second anti-aliasing filter(having the same bandwidth as the first one).

Another implicit assumption is that the digital filter can operate in real time : The computer and the filtering algorithm must be sufficiently fast so that outputs are computedfaster than input values arrive. The sampling interval, which is determined by the analog signal's bandwidth, thus determines how longour program has to compute each output y n . The computational complexity for calculating each output with a difference equation is O p q . Frequency domain implementation of the filter is also possible. The idea begins by computing the Fouriertransform of a length- N portion of the input x n , multiplying it by the filter's transfer function, and computing the inverse transform of the result. This approachseems overly complex and potentially inefficient. Detailing the complexity, however, we have O N N for the two transforms (computed using the FFT algorithm) and O N for the multiplication by the transfer function, which makes the total complexity O N N for N input values . A frequency domain implementation thus requires O N computational complexity for each output value. The complexities of time-domain and frequency-domain implementations depend ondifferent aspects of the filtering: The time-domain implementation depends on the combined orders of the filterwhile the frequency-domain implementation depends on the logarithm of the Fourier transform's length.

It could well be that in some problems the time-domain version is more efficient (more easily satisfies the real timerequirement), while in others the frequency domain approach isfaster. In the latter situations, it is the FFT algorithm for computing the Fourier transforms that enables thesuperiority of frequency-domain implementations. Because complexity considerations only express how algorithm running-time increaseswith system parameter choices, we need to detail both implementations to determine which will be more suitable for anygiven filtering problem. Filtering with a difference equation is straightforward, and the number of computations that must bemade for each output value is 2 p q .

Derive this value for the number of computations for the general difference equation .

We have p q 1 multiplications and p q 1 additions. Thus, the total number of arithmetic operations equals 2 p q .

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Source:  OpenStax, Analog-to-digital conversion. OpenStax CNX. Sep 20, 2008 Download for free at http://cnx.org/content/col10578/1.2
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