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In the situation called 'meiotic drive', a particular allele ends up in gametes more frequently than others for the same locus. That is, the usual expectation that on average 50% of an individual's gametes contain one allele for a given locus and 50% the other allele for that locus, is violated resulting in the one of the two alleles being overrepresented in gametes of heterozygotes. (The gametes of homozygotes are not affected.)

a. Review Figure 1. What aspect of this diagram would be altered? Why? Please explain.

b. Even if all individuals have an equal probability of mating in this population (i.e. mating occurs randomly), would all alleles have an equal probability of ending up in a fertilization event and thus the next generation? Why or why not? Please explain.

a. The relative quantities of gametes in the 'buckets' of heterozygotes would no longer be 50:50. 'Buckets' corresponding to the allele that ends up in gametes more frequently would contain a larger quantity of gametes than 'buckets' representing the alternative allele.

b. No. All alleles would not have an equal likelihood of ending up in fertilization events even when all individuals are all equally likely to mate. This is true because, when a mating event involves a heterozygote, they will be more likely to contribute the over-represented allele than the alternative allele to fertilization. This is true because more than half their gametes contain the over-represented allele.

In 2005, Stefasson et al. reported the fascinating discovery of an allele, H2, in humans whose presence is associated with increased fertility in Icelandic and European populations. Females with at least one copy of the allele have approximately 3.5%, and males 2.9%, more children on average than non-carriers. The exact mechanism by which the allele affects fertility is unknown.

Do all people in Icelandic and European populations have an equal probability of contributing one of the two gametes to each fertilization event that successfully produces an offspring? Please explain your conclusion.

No, all individuals in these populations do not have an equal probability of contributing one of the two gametes to each fertilization event that produces a surviving offspring. This is true because individuals carrying at least one copy of the allele are more likely to successfully conceive, i.e. have more successful fertilization events, than those that do not carry it.

Researchers investigating the H2 allele discussed in problem 3 hypothesized that this allele could be spreading through the population because of 'transmission disequilibrium' a situation analagous to meiotic drive in that offspring are more likely to inherit the H2 allele over the alternative H1 allele from a heterozygotic parent.

To investigate this, researchers genotyped 3,286 offspring of parents, in which one parent was heterozygous for H2 and the other parent homozygous for the alternative H1 allele, and found that 1,614 of these offspring carried the H2 allele (Stefasson et al. , 2005). Do the data suggest that this allele is spreading through the population as a result of transmission disequilibrium? Yes or no? How do you know? Please explain.

No, the data suggest that this allele is not spreading through the population as a result of transmission disequilibrium because 49% of the offspring of heterozygotes [(1,614/3,286)*100] carry the H2 allele. This compares favorably to the expectation that, if transmission rates are not biased, approximately 50% of the offspring of heterozygotes will carry the H2 allele (and approximately 50% the H1 allele). The two 'buckets' of heterozygotes appear to contain equal quantities of H2 and H1 alleles.

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
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Abhi
how do they get the third part x = (32)5/4
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can someone help me with some logarithmic and exponential equations.
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ninjadapaul
20/(×-6^2)
Salomon
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ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
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I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
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is it a question of log
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Commplementary angles
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what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
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a perfect square v²+2v+_
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Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
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or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
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Kristine 2*2*2=8
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No. 7x -4y is simplified from 4x + (3y + 3x) -7y
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Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
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. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
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I start with an easy one. carbon nanotubes woven into a long filament like a string
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what is the function of carbon nanotubes?
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I'm interested in nanotube
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what is nanomaterials​ and their applications of sensors.
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what is nano technology
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what is system testing?
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preparation of nanomaterial
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Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
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AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
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anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
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how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
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silver nanoparticles could handle the job?
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I'm interested in Nanotube
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Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
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the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
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Source:  OpenStax, Understanding the hardy-weinberg equation. OpenStax CNX. Oct 22, 2007 Download for free at http://cnx.org/content/col10472/1.1
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