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You will work through a section of TI TMS320C55x assembly code by hand. The instructions include multiplication of fractional numbers in two's complement representation.

Assembly exercise

Analyze the following lines of code. Refer to Two's Complement and Fractional Arithmetic for 16-bit Processors , Addressing Modes for TI TMS320C55x , and the Mnemonic Instruction Set manual for help.

1 FIR_len .set 3 23 ; Assume: 4 ; BK03 = FIR_len5 ; firStateIndex is stored at memory location 1008h 6 ; AR2 = 1000h7 ; AR3 = 1004h 8 ; FRCT = 19 10 BSET AR3LC ; sets circular addressing for AR311 mov mmap(AR3), BSA23 12 mov #firStateIndex, AR413 mov *AR4, AR3 14 mov LO(AC0),*AR3+15 mov #0, AC0 16 rpt #(FIR_len-1)17 macm *AR2+,*AR3+,AC0

Anything following a " ; " is considered a comment. In this case, the comments indicate the contents of theauxiliary registers, the BK03 register, and the address registers before the execution of the first instruction, mov . The line FIR_len .set 3 defines the name FIR_len as equal to 3. The BK03 register contains the length of the circular buffer we want to use for auxiliary register 0 through 3. The BSET AR3LC modifies the increment operator + so that it behaves as a circular buffer. This means circular addressing will be used for AR3. Refer to Section 6.11 of the CPU Reference Guide for help on circular addressing.

Note that any number followed by an " h " or preceded with a 0x represents a hexadecimal value.

1000h and 0x1000 both refer to the decimal number 4096.

Assume that the data memory is initialized as follows starting at location 1000h .

Data Memory Assignment (before execution)
Data memory assignment (before execution)
Memory location Value
1000h 1000h
1001h 0000h
1002h 4000h
1004h 1000h
1005h 1000h
1006h 4000h
1007h 1000h
1008h 0000h

After familiarizing yourself with the mov , rpt , and macm instructions, step through each line of code and record the values of theaccumulator AC0 and auxiliary registers AR2 and AR3 in the spaces provided in [link] . Additionally, record the value of the memory contents after all three instructions have been"executed" in the blank data memory table in [link] .

Execution Results
AC0 AR2 AR3
00 0000 8000h 1000h 1004h at start of code
after mov instruction line 11
after mov instruction line 12
after mov instruction line 13
after mov instruction line 14
after mov instruction line 15
after rpt instruction line 16
after first macm instruction
after second macm instruction
after third macm instruction

When working through the exercise, take into account that the accumulator AC0 is a 40-bit register, and that the multiplier is in the fractional arithmetic mode . In this mode, integers on the DSP are interpreted asfractions, and the multiplier will treat them accordingly.This is done by shifting the result of the integer multiplier in the ALU left one bit. (All the arithmetic is fractional in these examples.)Multiplies performed by the ALU (via the macm instruction) produce a result that is twice what you would expect if you just multiplied the twointegers together. DSP numerical representation and arithmetic are described further in Two's Complement and Fractional Arithmetic for 16-bit Processors .

Data Memory Assignment (after execution)
Data memory assignment (after execution)
Memory location Value
1000h
1001h
1002h
1004h
1005h
1006h
1007h
1008h

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Source:  OpenStax, Ece 420 fall 2013. OpenStax CNX. Sep 26, 2013 Download for free at http://cnx.org/content/col11560/1.3
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