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The end of the class

Listing 5 also signals the end of the class named Prob02Runner and the end of the program.

Run the program

I encourage you to copy the code from Listing 6 . Compile the code and execute it. Experiment with the code, making changes, andobserving the results of your changes. Make certain that you can explain why your changes behave as they do.

Click Prob02a.jpg to download the required input image file for this program.


You learned how to mirror images both horizontally and vertically.

What's next?

In the next module, you will learn to use a variety of Java2D classes including GradientPaint.

While not a requirement of the course, you can select the following link to view an optional online video lecture on the material in this module.


This section contains a variety of miscellaneous information.

Housekeeping material
  • Module name: Java OOP: Mirroring Images
  • File: Java3024.htm
  • Published: 08/04/12

Financial : Although the Connexions site makes it possible for you to download a PDF file for thismodule at no charge, and also makes it possible for you to purchase a pre-printed version of the PDF file, you should beaware that some of the HTML elements in this module may not translate well into PDF.

I also want you to know that, I receive no financial compensation from the Connexions website even if you purchase the PDF version of the module.

In the past, unknown individuals have copied my modules from cnx.org, converted them to Kindle books, and placed them for sale on Amazon.com showing me as the author. Ineither receive compensation for those sales nor do I know who does receive compensation. If you purchase such a book, please beaware that it is a copy of a module that is freely available on cnx.org and that it was made and published withoutmy prior knowledge.

Affiliation : I am a professor of Computer Information Technology at Austin Community College in Austin, TX.

Complete program listing

A complete listing of the program discussed in this module is shown in Listing 6 below.

Listing 6 . Complete program listing.
/*File Prob02 Copyright 2008 R.G.Baldwin *********************************************************/import java.awt.Graphics2D; import java.awt.geom.AffineTransform;import java.awt.geom.Rectangle2D; import java.awt.Graphics;public class Prob02{ //DO NOT MODIFY THE CODE IN THIS CLASS DEFINITION.public static void main(String[] args){new Prob02Runner().run(); }//end main method}//end class Prob02 //======================================================//class Prob02Runner{ public Prob02Runner(){System.out.println("Display your name here."); }//end constructor//----------------------------------------------------// public void run(){Picture pix = new Picture("Prob02a.jpg"); //Add your name and display the output picture.pix.addMessage("Display your name here.",10,20); //Display the input picture.pix.explore(); pix = rotatePicture(pix,35);pix.explore(); pix = mirrorUpperQuads(pix);pix = mirrorHoriz(pix); pix.explore();System.out.println(pix); }//end run//----------------------------------------------------// private Picture rotatePicture(Picture pix,double angle){ //Set up the rotation transformAffineTransform rotateTransform = new AffineTransform();rotateTransform.rotate(Math.toRadians(angle), pix.getWidth()/2,pix.getHeight()/2); //Get the required dimensions of a rectangle that will// contain the rotated image. Rectangle2D rectangle2D =pix.getTransformEnclosingRect(rotateTransform); int resultWidth = (int)(rectangle2D.getWidth());int resultHeight = (int)(rectangle2D.getHeight()); //Set up the translation transform that will translate// the rotated image to the center of the new Picture // object.AffineTransform translateTransform = new AffineTransform();translateTransform.translate( (resultWidth - pix.getWidth())/2,(resultHeight - pix.getHeight())/2); //Concatenate the two transforms so that the image// will first be rotated around its center and then // translated to the center of the new Picture object.translateTransform.concatenate(rotateTransform); //Create a new Picture object to contain the results// of the transformation. Picture result = new Picture(resultWidth,resultHeight); //Get the graphics context of the new Picture object,// apply the transform to the incoming picture and // draw the transformed picture on the new Picture// object. Graphics2D g2 = (Graphics2D)result.getGraphics();g2.drawImage(pix.getImage(),translateTransform,null); return result;}//end rotatePicture //----------------------------------------------------////This method mirrors the upper-left quadrant of a // picture into the upper-right quadrant.private Picture mirrorUpperQuads(Picture pix){ Pixel leftPixel = null;Pixel rightPixel = null; int midpoint = pix.getWidth()/2;int width = pix.getWidth(); for(int row = 0;row<pix.getHeight()/2;row++){ for(int col = 0;col<midpoint;col++){ leftPixel = pix.getPixel(col,row);rightPixel = pix.getPixel(width-1-col,row);rightPixel.setColor(leftPixel.getColor()); }//end inner loop}//end outer loop return pix;}//end mirrorUpperQuads //----------------------------------------------------////This method mirrors the top half of a picture into // the bottom half.private Picture mirrorHoriz(Picture pix){ Pixel topPixel = null;Pixel bottomPixel = null; int midpoint = pix.getHeight()/2;int height = pix.getHeight(); for(int col = 0;col<pix.getWidth();col++){ for(int row = 0;row<midpoint;row++){ topPixel = pix.getPixel(col,row);bottomPixel = pix.getPixel(col,height-1-row);bottomPixel.setColor(topPixel.getColor()); }//end inner loop}//end outer loop return pix;}//end mirrorHoriz //----------------------------------------------------//}//end class Prob02Runner


Questions & Answers

how do you translate this in Algebraic Expressions
linda Reply
why surface tension is zero at critical temperature
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what is biological synthesis of nanoparticles
Sanket Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
many many of nanotubes
what is the k.e before it land
what is the function of carbon nanotubes?
I'm interested in nanotube
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
what is system testing
what is the application of nanotechnology?
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
anybody can imagine what will be happen after 100 years from now in nano tech world
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
silver nanoparticles could handle the job?
not now but maybe in future only AgNP maybe any other nanomaterials
I'm interested in Nanotube
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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