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What is the overall behavior?

This method receives a list of Sprite objects as an incoming parameter. It tests for a collision with each sprite in the list beginning withthe sprite at the head of the list. If it detects a collision with a sprite, it stops testing immediately and returns a reference to the Sprite object for which it found the collision. If it doesn't find a collision with anysprite in the list, it returns null.

The IsCollision method code

The new method named IsCollision begins in Listing 5 .

Listing 5 . Beginning of a new IsCollision method.

public Sprite IsCollision(List<Sprite>target) { Rectangle thisRectangle =new Rectangle((int)(position.X), (int)(position.Y),image.Width, image.Height);

The code in Listing 5 constructs a new Rectangle object that describes the rectangular area currently occupied by the sprite's imagerelative to the upper left corner of the game window. The Rectangle object's reference is saved in the local variable named thisRectangle .

Test for a collision with other sprites

Listing 6 begins by declaring a pair of local variables named targetRectangle and cnt .

The variable named targetRectangle will be used to store a reference to a rectangular area that currently contains a target sprite. Thevariable named cnt will be used as a loop counter.

Listing 6 . Test for a collision with other sprites.

Rectangle targetRectangle; int cnt = 0;while(cnt<target.Count){ targetRectangle = target[cnt].GetRectangle(); if(thisRectangle.Intersects(targetRectangle)){return target[cnt];}//end if cnt++;}//end while loop return null;//no collision detected}//end IsCollision

A while loop

Then Listing 6 executes a while loop that:

  • Calls the GetRectangle method on the next Sprite object in the list (see Listing 4 ).
  • Tests to determine if this sprite's rectangle intersects the target sprite's rectangle.
  • Returns a reference to the target Sprite object if a collision is detected; keeps looping otherwise.

The first return statement

Executing a return statement in the middle of the while loop terminates the loop and also terminates the method.

The second return statement

If no collision is detected, the loop terminates when all of the Sprite objects in the list have been tested.

At that point, Listing 6 executes a different return statement to return null and terminate the method. The null value is returned in place of a reference to a Sprite object to signal that no collision was detected.

The end of the Sprite class

Listing 6 signals the end of the IsCollision method, which is also the end of the changes made to the Sprite class. Once again, you will find a complete listing of the new Sprite class in Listing 14 near the end of the module.

The Game1 class

I will explain only those portions of the Game1 class that are substantially new to this program. You will find a complete listing ofthe Game1 class in Listing 15 near the end of the module.

The overridden LoadContent method

The only code that is substantially new prior to the LoadContent method is the declaration of an instance variable of type Sprite named spiderWeb . Therefore, I will skip down and begin my discussion with the overridden LoadContent method, which begins in Listing 7 .

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
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how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
is it a question of log
Commplementary angles
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a perfect square v²+2v+_
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algebra 2 Inequalities:If equation 2 = 0 it is an open set?
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or infinite solutions?
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
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rolling four fair dice and getting an even number an all four dice
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Kristine 2*2*2=8
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Differences Between Laspeyres and Paasche Indices
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No. 7x -4y is simplified from 4x + (3y + 3x) -7y
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Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
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. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
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Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
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what is system testing
what is the application of nanotechnology?
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
anybody can imagine what will be happen after 100 years from now in nano tech world
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
silver nanoparticles could handle the job?
not now but maybe in future only AgNP maybe any other nanomaterials
I'm interested in Nanotube
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
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Source:  OpenStax, Xna game studio. OpenStax CNX. Feb 28, 2014 Download for free at https://legacy.cnx.org/content/col11634/1.6
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