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Solve: 5 ( p 3 ) 4 p = −10 .

p = 5

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Solve: 4 ( q + 2 ) 3 q = −8 .

q = −16

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Solve: 2 ( 3 k 1 ) 5 k = −2 7 .

Solution

Both sides of the equation have expressions that we should simplify before we isolate the variable.

.
Distribute on the left, subtract on the right. .
Use the Commutative Property of Addition. .
Combine like terms. .
Undo subtraction by using the Addition Property of Equality. .
Simplify. .
Check.
Let k = −7 .
The top line says 2 times parentheses 3k minus 1 minus 5k equals negative 2 minus 7. Below this is 2 times parentheses red negative 7 minus 1 minus 5 times red negative 7 equals negative 2 minus 7. The next line says 2 times parentheses negative 21 minus 1 minus 5 times negative 7 equals negative 9. Below that is 2 times negative 22 plus 35 equals negative 9. Next is negative 44 plus 35 equals negative 9. The last line says negative 9 equals negative 9.
The solution checks.
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Solve: 4 ( 2 h 3 ) 7 h = −6 7 .

h = −1

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Solve: 2 ( 5 x + 2 ) 9 x = −2 + 7 .

x = 1

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Translate an equation and solve

In previous chapters, we translated word sentences into equations. The first step is to look for the word (or words) that translate(s) to the equal sign. [link] reminds us of some of the words that translate to the equal sign.

Equals (=)
is is equal to is the same as the result is gives was will be

Let’s review the steps we used to translate a sentence into an equation.

Translate a word sentence to an algebraic equation.

  1. Locate the "equals" word(s). Translate to an equal sign.
  2. Translate the words to the left of the "equals" word(s) into an algebraic expression.
  3. Translate the words to the right of the "equals" word(s) into an algebraic expression.

Now we are ready to try an example.

Translate and solve: five more than x is equal to 26 .

Solution

Translate. .
Subtract 5 from both sides. .
Simplify. .
Check:
Is 26 five more than 21 ?
.
.
The solution checks.
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Translate and solve: Eleven more than x is equal to 41 .

x + 11 = 41; x = 30

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Translate and solve: Twelve less than y is equal to 51 .

y − 12 = 51; y = 63

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Translate and solve: The difference of 5 p and 4 p is 23 .

Solution

Translate. .
Simplify. .
Check:
.
.
.
.
.
The solution checks.
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Translate and solve: The difference of 4 x and 3 x is 14 .

4 x − 3 x = 14; x = 14

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Translate and solve: The difference of 7 a and 6 a is −8 .

7 a − 6 a = −8; a = −8

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Translate and solve applications

In most of the application problems we solved earlier, we were able to find the quantity we were looking for by simplifying an algebraic expression. Now we will be using equations to solve application problems. We’ll start by restating the problem in just one sentence, assign a variable, and then translate the sentence into an equation to solve. When assigning a variable, choose a letter that reminds you of what you are looking for.

The Robles family has two dogs, Buster and Chandler. Together, they weigh 71 pounds.

Chandler weighs 28 pounds. How much does Buster weigh?

Solution

Read the problem carefully.
Identify what you are asked to find, and choose a variable to represent it. How much does Buster weigh?
Let b = Buster's weight
Write a sentence that gives the information to find it. Buster's weight plus Chandler's weight equals 71 pounds.
We will restate the problem, and then include the given information. Buster's weight plus 28 equals 71.
Translate the sentence into an equation, using the variable b . .
Solve the equation using good algebraic techniques. .
.
Check the answer in the problem and make sure it makes sense.
43 + 28 = ? 71
Is 43 pounds a reasonable weight for a dog? Yes. Does Buster's weight plus Chandler's weight equal 71 pounds?
71 = 71
Write a complete sentence that answers the question, "How much does Buster weigh?" Buster weighs 43 pounds
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Practice Key Terms 1

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Source:  OpenStax, Prealgebra. OpenStax CNX. Jul 15, 2016 Download for free at http://legacy.cnx.org/content/col11756/1.9
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