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This method assumes that the inverse transform will produce purely real values in the space domain. Therefore, in the interest of computationalefficiency, the method does not compute the imaginary output values. Therefore, this is not a general purpose 2D complex-to-complex transform. For correct results, the input complex data must match that obtained by performing a forwardtransform on purely real data in the space domain.

Once again it was necessary to sacrifice indentation to force this very long equation to be compatible with this narrow publication format and still bereadable.

Listing 3. The inverseXform2D method.
static void inverseXform2D(double[][]real, double[][] imag,double[][]dataOut){ int height = real.length;int width = real[0].length;System.out.println("height = " + height);System.out.println("width = " + width); //Two outer loops iterate on output data.for(int ySpace = 0;ySpace<height;ySpace++){ for(int xSpace = 0;xSpace<width; xSpace++){//Two inner loops iterate on input data. for(int yWave = 0;yWave<height; yWave++){for(int xWave = 0;xWave<width; xWave++){//Compute real output data. dataOut[ySpace][xSpace] +=(real[yWave][xWave]*cos(2*PI*((1.0 * xSpace* xWave/width) + (1.0*ySpace*yWave/height))) -imag[yWave][xWave]*sin(2*PI*((1.0 * xSpace* xWave/width) + (1.0*ySpace*yWave/height))))/sqrt(width*height); }//end xWave loop}//end yWave loop }//end xSpace loop}//end ySpace loop }//end inverseXform2D method

Parameters

This method requires three parameters. The first two parameters are references to 2D arrays containing the real and imaginary parts of the complexwavenumber spectrum that is to be transformed into a surface in the space domain.

The third parameter is a reference to a 2D array of the same size that will be populated with the transform results.

The shiftOrigin method

This method deserves some explanation. The reason that this method is needed is illustrated by Figure 1 .

Two views of the same wavenumber spectrum

Both of the images in Figure 1 represent the same wavenumber spectrum, but they are plotted against different coordinate systems.

Figure 1. Two views of the same wavenumber spectrum.
missing image

How the wavenumber spectrum is actually computed

The top image shows how the wavenumber spectrum is actually computed.

The wavenumber spectrum is computed covering an area of wavenumber space with the 0,0 origin in the top-left corner. The computation extends to twice theNyquist folding wave number along each axis.

Computationally sound but not visually pleasing

While this format is computationally sound, it isn't what most of us are accustomed to seeing in plots in wavenumber space. Rather, we are accustomed toseeing wavenumber spectra plotted with the 0,0 origin at the center.

The wavenumber spectrum is periodic

Knowing that the area of wavenumber space shown in the top image of Figure 1 covers one complete period of a periodic surface, the shiftOrigin method rearranges the results (for display purposes only) to that shown in the bottom image in Figure 1 . The origin is at the center in the bottom image of Figure 1 . The edges of the lower image in Figure 1 are the Nyquist folding wave numbers.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
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what is inorganic
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Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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Magreth
progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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