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By the end of this section, you will be able to:
  • Solve equations with fraction coefficients
  • Solve equations with decimal coefficients

Before you get started, take this readiness quiz.

  1. Multiply: 8 · 3 8 .
    If you missed this problem, review Multiply and Divide Fractions.
  2. Find the LCD of 5 6 and 1 4 .
    If you missed this problem, review Add and Subtract Fractions with Different Denominators.
  3. Multiply: 4.78 by 100 .
    If you missed this problem, review Decimal Operations.

Solve equations with fraction coefficients

Let’s use the General Strategy for Solving Linear Equations introduced earlier to solve the equation 1 8 x + 1 2 = 1 4 .

.
To isolate the x term, subtract 1 2 from both sides. .
Simplify the left side. .
Change the constants to equivalent fractions with the LCD. .
Subtract. .
Multiply both sides by the reciprocal of 1 8 . .
Divide. .
Simplify. .

This method worked fine, but many students don’t feel very confident when they see all those fractions. So we are going to show an alternate method to solve equations with fractions. This alternate method eliminates the fractions.

We will apply the Multiplication Property of Equality and multiply both sides of an equation by the least common denominator of all the fractions in the equation. The result of this operation will be a new equation, equivalent to the first, but with no fractions. This process is called clearing the equation of fractions . Let’s solve the same equation again, but this time use the method that clears the fractions.

Solve: 1 8 x + 1 2 = 1 4 .

Solution

Find the least common denominator of all the fractions in the equation. .
Multiply both sides of the equation by that LCD, 8. This clears the fractions. .
Use the Distributive Property. .
Simplify — and notice, no more fractions! .
Solve using the General Strategy for Solving Linear Equations. .
Simplify. .
Check: Let x = −2
.
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Solve: 1 4 x + 1 2 = 5 8 .

x = 1 2

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Solve: 1 6 y 1 3 = 1 6 .

y = 3

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Notice in [link] that once we cleared the equation of fractions, the equation was like those we solved earlier in this chapter. We changed the problem to one we already knew how to solve! We then used the General Strategy for Solving Linear Equations.

Solve equations with fraction coefficients by clearing the fractions.

  1. Find the least common denominator of all the fractions in the equation.
  2. Multiply both sides of the equation by that LCD. This clears the fractions.
  3. Solve using the General Strategy for Solving Linear Equations.

Solve: 7 = 1 2 x + 3 4 x 2 3 x .

Solution

We want to clear the fractions by multiplying both sides of the equation by the LCD of all the fractions in the equation.

Find the least common denominator of all the fractions in the equation. .
Multiply both sides of the equation by 12. .
Distribute. .
Simplify — and notice, no more fractions! .
Combine like terms. .
Divide by 7. .
Simplify. .
Check: Let x = 12 .
.

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Solve: 6 = 1 2 v + 2 5 v 3 4 v .

v = 40

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Solve: −1 = 1 2 u + 1 4 u 2 3 u .

u = −12

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In the next example, we’ll have variables and fractions on both sides of the equation.

Solve: x + 1 3 = 1 6 x 1 2 .

Solution

Find the LCD of all the fractions in the equation. .
Multiply both sides by the LCD. .
Distribute. .
Simplify — no more fractions! .
Subtract x from both sides. .
Simplify. .
Subtract 2 from both sides. .
Simplify. .
Divide by 5. .
Simplify. .
Check: Substitute x = −1 .
.
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Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
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Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Prealgebra. OpenStax CNX. Jul 15, 2016 Download for free at http://legacy.cnx.org/content/col11756/1.9
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