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Solve: 8 q 5 = −4 q + 7 .

q = 1

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Solve: 7 n 3 = n + 3 .

n = 1

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Solve: 2 a 7 = 5 a + 8 .

Solution

This equation has 2 a on the left and 5 a on the right. Since 5 > 2 , make the right side the variable side and the left side the constant side.

.
Subtract 2 a from both sides to remove the variable term from the left. .
Combine like terms. .
Subtract 8 from both sides to remove the constant from the right. .
Simplify. .
Divide both sides by 3 to make 1 the coefficient of a . .
Simplify. .
Check: Let a = −5 .
.

Note that we could have made the left side the variable side instead of the right side, but it would have led to a negative coefficient on the variable term. While we could work with the negative, there is less chance of error when working with positives. The strategy outlined above helps avoid the negatives!

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Solve: 2 a 2 = 6 a + 18 .

a = −5

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Solve: 4 k 1 = 7 k + 17 .

k = −6

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To solve an equation with fractions, we still follow the same steps to get the solution .

Solve: 3 2 x + 5 = 1 2 x 3 .

Solution

Since 3 2 > 1 2 , make the left side the variable side and the right side the constant side.

.
Subtract 1 2 x from both sides. .
Combine like terms. .
Subtract 5 from both sides. .
Simplify. .
Check: Let x = −8 .
.
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Solve: 7 8 x 12 = 1 8 x 2 .

x = 10

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Solve: 7 6 y + 11 = 1 6 y + 8 .

y = −3

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We follow the same steps when the equation has decimals, too.

Solve: 3.4 x + 4 = 1.6 x 5 .

Solution

Since 3.4 > 1.6 , make the left side the variable side and the right side the constant side.

.
Subtract 1.6 x from both sides. .
Combine like terms. .
Subtract 4 from both sides. .
Simplify. .
Use the Division Property of Equality. .
Simplify. .
Check: Let x = −5 .
.
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Solve: 2.8 x + 12 = −1.4 x 9 .

x = −5

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Solve: 3.6 y + 8 = 1.2 y 4 .

y = −5

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Solve equations using a general strategy

Each of the first few sections of this chapter has dealt with solving one specific form of a linear equation . It’s time now to lay out an overall strategy that can be used to solve any linear equation. We call this the general strategy . Some equations won’t require all the steps to solve, but many will. Simplifying each side of the equation as much as possible first makes the rest of the steps easier.

Use a general strategy for solving linear equations.

  1. Simplify each side of the equation as much as possible. Use the Distributive Property to remove any parentheses. Combine like terms.
  2. Collect all the variable terms to one side of the equation. Use the Addition or Subtraction Property of Equality.
  3. Collect all the constant terms to the other side of the equation. Use the Addition or Subtraction Property of Equality.
  4. Make the coefficient of the variable term to equal to 1 . Use the Multiplication or Division Property of Equality. State the solution to the equation.
  5. Check the solution. Substitute the solution into the original equation to make sure the result is a true statement.

Solve: 3 ( x + 2 ) = 18 .

Solution

Simplify each side of the equation as much as possible.
Use the Distributive Property.
.
Collect all variable terms on one side of the equation—all x s are already on the left side. .
Collect constant terms on the other side of the equation.
Subtract 6 from each side
.
Simplify. .
Make the coefficient of the variable term equal to 1. Divide each side by 3. .
Simplify. .
Check: Let x = 4 .
.
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Source:  OpenStax, Prealgebra. OpenStax CNX. Jul 15, 2016 Download for free at http://legacy.cnx.org/content/col11756/1.9
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