The properties associated with the summation process are given in the following rule.
Rule: properties of sigma notation
Let
${a}_{1},{a}_{2}\text{,\u2026,}\phantom{\rule{0.2em}{0ex}}{a}_{n}$ and
${b}_{1},{b}_{2}\text{,\u2026,}\phantom{\rule{0.2em}{0ex}}{b}_{n}$ represent two sequences of terms and let
c be a constant. The following properties hold for all positive integers
n and for integers
m , with
$1\le m\le n.$
A few more formulas for frequently found functions simplify the summation process further. These are shown in the next rule, for
sums and powers of integers , and we use them in the next set of examples.
Now that we have the necessary notation, we return to the problem at hand: approximating the area under a curve. Let
$f\left(x\right)$ be a continuous, nonnegative function defined on the closed interval
$\left[a,b\right].$ We want to approximate the area
A bounded by
$f\left(x\right)$ above, the
x -axis below, the line
$x=a$ on the left, and the line
$x=b$ on the right (
[link] ).
How do we approximate the area under this curve? The approach is a geometric one. By dividing a region into many small shapes that have known area formulas, we can sum these areas and obtain a reasonable estimate of the true area. We begin by dividing the interval
$\left[a,b\right]$ into
n subintervals of equal width,
$\frac{b-a}{n}.$ We do this by selecting equally spaced points
${x}_{0},{x}_{1},{x}_{2}\text{,\u2026,}\phantom{\rule{0.2em}{0ex}}{x}_{n}$ with
${x}_{0}=a,{x}_{n}=b,$ and
${x}_{i}-{x}_{i-1}=\frac{b-a}{n}$
for
$i=1,2,3\text{,\u2026,}\phantom{\rule{0.2em}{0ex}}n.$
We denote the width of each subinterval with the notation Δ
x , so
$\text{\Delta}x=\frac{b-a}{n}$ and
also known as the y value so I could say y=2x or f(x)= 2x same thing just using functional notation
your next question is what is dependent and independent variables. I am Dyslexic but know math and which is which confuses me. but one can vary the x value while y depends on which x you use. also
Marc
up domain and range
Marc
enjoy your work and good luck
Marc
I actually wanted to ask another questions on sets if u dont mind please?
Inembo
I have so many questions on set and I really love dis app I never believed u would reply
Inembo
Hmm go ahead and ask you got me curious too much conversation here
Adri
am sorry for disturbing I really want to know math that's why
*I want to know the meaning of those symbols in sets*
e.g n,U,A', etc pls I want to know it and how to solve its problems
Inembo
and how can i solve a question like dis
*in a group of 40 students, 32 offer maths and 24 offer physics and 4 offer neither maths nor physics , how many offer both maths and physics*
Inembo
next questions
what do dy mean by (A' n B^c)^c'
Inembo
The sets help you to define the function. The function is like a magic box where you put inside stuff(numbers or sets) and you get out the stuff but in different shapes (forms).
Adri
I dont understand what you wanna say by (A' n B^c)^c'
Adri
(A' n B (rise to the power of c)) all rise to the power of c
Inembo
Aaaahh
Adri
Ok so the set is formed by vectors and not numbers
Adri
A vector of length n
Adri
But you can make a set out of matrixes as well
Adri
I I don't even understand sets I wat to know d meaning of all d symbolsnon sets
Inembo
Wait what's your math level?
Adri
High-school?
Adri
yes
Inembo
am having big problem understanding sets more than other math topics
Inembo
So f:R->R means that the function takes real numbers and provides real numer. For ex. If f(x) =2x this means if you give to your function a real number like 2,it gives you also a real number 2times2=4
Adri
pls answer this question
*in a group of 40 students, 32 offer maths and 24 offer physics and 4 offer neither maths nor physics , how many offer both maths and physics*
Inembo
If you have f:R^n->R^n you give to your function a vector of length n like (a1,a2,...an) where all a1,.. an are reals and gives you also a vector of length n... I don't know if i answering your question. Otherwise on YouTube you havr many videos where they explain it in a simple way
Adri
I would say 24
Adri
Offer both
Adri
Sorry 20
Adri
Actually you have 40 - 4 =36 who offer maths or physics or both.
Adri
I know its 20 but how to prove it
Inembo
You have 32+24=56who offer courses
Adri
56-36=20 who give both courses... I would say that
Adri
solution: In a question involving sets and Venn diagram, the sum of the members of set A + set B - the joint members of both set A and B + the members that are not in sets A or B = the total members of the set. In symbolic form n(A U B) = n(A) + n (B) - n (A and B) + n (A U B)'.
Mckenzie
In the case of sets A and B use the letters m and p to represent the sets and we have:
n (M U P) = 40; n (M) = 24; n (P) = 32; n (M and P) = unknown; n (M U P)' = 4
Mckenzie
Now substitute the numerical values for the symbolic representation
40 = 24 + 32 - n(M and P) + 4
Now solve for the unknown using algebra:
40 = 24 + 32+ 4 - n(M and P)
40 = 60 - n(M and P)
Add n(M and P), as well, subtract 40 from both sides of the equation to find the answer.
Mckenzie
40 - 40 + n(M and P) = 60 - 40 - n(M and P) + n(M and P)
Solution:
n(M and P) = 20
Mckenzie
thanks
Inembo
Simpler form:
Add the sums of set M, set P and the complement of the union of sets M and P then subtract the number of students from the total.
the domain of the function is all real number excluding zero, because the rational function 1/x is a representation of a fractional equation (precisely inverse function). As in elementary mathematics the concept of dividing by zero is nonexistence, so zero will not make the fractional statement
Mckenzie
a function's answer/range should not be in the form of 1/0 and there should be no imaginary no. say square root of any negative no.
(-1)^1/2
Roha
domain means everywhere along the x axis. since this function is not discontinuous anywhere along the x axis, then the domain is said to be all values of x.
Andrew
Derivative of a function
Waqar
right andrew ... this function is only discontinuous at 0
Roha
of sorry, I didn't realize he was taking about the function 1/x ...I thought he was referring to the function x^3-2x.
Andrew
yep...it's 1/x...!!!
Roha
true and cannot be apart of the domain that makes up the relation of the graph y = 1/x. The value of the denominator of the rational function can never be zero, because the result of the output value (range value of the graph when x =0) is undefined.
Mckenzie
👍
Roha
Therefore, when x = 0 the image of the rational function does not exist at this domain value, but exist at all other x values (domain) that makes the equation functional, and the graph drawable.
Mckenzie
👍
Roha
Roha are u A Student
Lutf
yes
Roha
What is the first fundermental theory of Calculus?
for MSc chemistry... simple formulas of integration
aparna
hello?
funny
how are you
funny
I don't understand integration
aparna
r u insane
aparna
integration is so simple not typical..
funny
tell me any questions about integration then i will solve.
funny
we use integration for whole values or for sum of values any there are some basic rule for integration..
funny
I just formulas
aparna
I just want formulas of integration
aparna
value of log ax
cot-x cos-x
aparna
there are many formulas about integration
funny
more then one formula are exist about integration..
funny
so I want simple formulas Because I'm studying MSc chem...Nd have done bsc from bio...
aparna
I am M.sc physics now i am studying in m.phil
funny
so what can i do
aparna
I will send you basic formula for integration after two mint first of all i write then i will send you.
funny
send me your messenger id where i can send you formulas about integration because there is no option for image sending..
funny
integration f(X) dx
this is basic formula of integration sign is not there you can look integration sign in methematics form...
and f(X) my be any function any values
funny
you send me your any ID where i can send you information about integration