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Part 4: additional tests

Once you have performed all of the tests outlined above, consider the following tests:

•Transfer the thermocouple from ice water to room temperature air.

How does the time constant compare with the one obtained from the air-to-ice-water transition? Is it different?Why or why not?

•When calculating the time constant for the thermocouple in transition from air to ice water, you measured thetime to go 63.2 percent of the way from the initial temperature (around 21 C) to the final temperature (around 0 C). Using the samegraph, recalculate the time constant using14 C as the starting temperature (i.e., what is the time required to go 63.2 percent ofthe way from 14 C to 0 C?). Is this time constant value significantly different from the initial value you computed? Why orwhy not?

Part 5: thought questions

Document your response to these questions in your lab book.

1. How do the time constants of the thermometer, thermocouple, and thermistor compare? Why is thethermometer“slow”compared to the other devices?

2. How do the time constants obtained for air and water compare? Are they significantly different? If so, explainwhy.

3. Does the instrument need to be at steady state before transferring it to the final medium?

4. How accurate (qualitatively) is the first-order model approximation for the different sensors andmedia?

Part 6: frequency response

From the measured time responses of the thermometer, the thermocouple, and the thermistor, it can be seenthat the response time of these sensors is not instantaneous. From this we can infer that these measurement systems may have somedifficulty following inputs that change quickly. Frequency response is a means of characterizing the dynamic response capabilities of asystem.

The frequency response of a system can be determined by calculating the response of a system to sinusoidalinputs at different frequencies. Two important characteristics are:

  • the magnitude ratio between the output and input waveforms
  • the phase difference between the output and input waveforms

For a first-order system, we can create the frequency response plot using only our knowledge of the system timeconstant. The magnitude ratio can be calculated from the following expression.

equation (4)

The phase difference is determined from expression 5.

equation (5)

In Excel, create a frequency response plot for the thermometer, thermocouple, and thermistor using the timeconstant from the ice water tests. Plot the magnitude ratio on a log-log scale and the phase difference on a semilog scale (logscale of frequency axis). Consider frequencies from 0.1 rad/s to 1000 rad/s. Your plots will look nice if you use ten points perdecade of frequency (i.e., 0.1, 0.2, 0.3,…,1, 2, 3,…, 10, 20, 30,…). Overlay the three magnitude responses on one plot and the three phase responses on another. How do the frequency responsecharacteristics of the thermometer, thermocouple, and thermistor compare?

Part 7: dynamic temperature measurement problem

Include the analysis for this problem in your lab book.

Assume that the thermocouple you used is placed in a water stream at a point where the temperature variessinusoidally between 60 C and 80 C at a frequency of 40 rad/s. Assuming that the thermocouple time constant is the same as thevalue you determined in the ice water case, what will be the range of sinusoidal variation in the temperature readings? Repeat thecalculations for a temperature frequency of 2 rad/s. Now assume the thermocouple is in air instead of water. Determine the range of thevariation using input frequencies of 10 rad/s and 1 rad/s.

Clean up:

Please straighten up your lab work area. Turn off the data acquisition hardware and leave your work area clean.Your help in keeping the lab neat is appreciated.

Report:

For this lab, you are to write up the Method section of a full formal report. Guidelines are given in theexample report in the Undergraduate Guide. Avoid presenting results in the Methods section. Your writing assignment is relativelyshort. Take the time to do a good job. Since you will not be submitting Results or Discussion of Results in the report, you willneed to document your results in your lab book. Also, be sure to answer the questions from the lab handout in your lab book.

Questions & Answers

can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
im not good at math so would this help me
Rachael Reply
yes
Asali
I'm not good at math so would you help me
Samantha
what is the problem that i will help you to self with?
Asali
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Introduction to mechanical measurements. OpenStax CNX. Oct 18, 2006 Download for free at http://cnx.org/content/col10385/1.1
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