# 4.10 Performance analysis

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A performance analysis of correlator-type and matched filter receivers on binary symbol transmission using both orthogonal and antipodal signal sets. Both types of receivers perform identically with the same detection criteria.

In this section we will evaluate the probability of error of both correlator type receivers and matched filter receivers. Wewill only present the analysis for transmission of binary symbols. In the process we will demonstrate that both of thesereceivers have identical bit-error probabilities.

## Antipodal signals

${r}_{t}={s}_{m}(t)+{N}_{t}$ for $0\le t\le T$ with $m=1$ and $m=2$ and ${s}_{1}(t)=-{s}_{2}(t)$

An analysis of the performance of correlation receivers with antipodal binary signals can be found here . A similar analysis for matched filter receivers can be found here .

## Orthogonal signals

${r}_{t}={s}_{m}(t)+{N}_{t}$ for $0\le t\le T$ with $m=1$ and $m=2$ and ${s}_{1}\dot {s}_{2}=0$

An analysis of the performance of correlation receivers with orthogonal binary signals can be found here . A similar analysis for matched filter receivers can be found here .

It can be shown in general that correlation and matched filter receivers perform with the same symbol error probability if thedetection criteria is the same for both receivers.

#### Questions & Answers

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SUYASH
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Ebrahim
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Ebrahim
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s.
Graphene has a hexagonal structure
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Cied
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I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
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Porter
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Yasmin
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Cesar
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Uday
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Stotaw
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Azam
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Azam
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Uday
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At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
how did you get the value of 2000N.What calculations are needed to arrive at it
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