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3.1 Tel aan in 2’s vanaf 186 tot 204.

Tel terug in 2’s vanaf 208 tot 194.

3.2 Tel aan in 3’e vanaf 0 tot 36.

Tel terug in 3’e vanaf 36 tot 0.

3.3 Tel aan in 5’e vanaf 375 tot 425.

Tel terug in 5’e vanaf 545 tot 485.

3.4 Tel aan in 10’e vanaf 950 tot 1 020.

Tel terug in 10’e vanaf 950 tot 840.

3.5 Tel aan in 25’s vanaf 625 tot 1 000.

Tel terug in 25’s vanaf 975 tot 675.

3.6 Tel aan in 50’s vanaf 550 tot 1 050.

Tel terug in 50’s vanaf 750 tot 350.

3.7 Tel aan in honderde vanaf 400 tot 1 100.

Tel terug in 100’e vanaf 1 000 tot 0.

4. AANTEL EN TERUGTEL (Indiwidueel):

  • Jou opvoeder mag nou vir jou vra om op jou eie te tel. Kyk of jy nou op jou eie kan aantel en terugtel. Miskien sal jy met groot getalle moet begin. Dit sal ‘n goeie idee wees om dit met ‘n maat te oefen. Eksperimenteer op jou sakrekenaar en begin by groot getalle.

5. TEL MET GROTER GETALLE (Indiwiduele mondelinge werk):

  • Gebruik jou sakrekenaar as 'n hulpmiddel terwyl jy met die ondersoek besig is, indien jy dit nodig het:

5.1 Tel aan in 2’s vanaf 9 980 tot 10 000.

Tel terug in 2’s vanaf 5 010 tot 4 990.

5.2 Tel aan in 3’e vanaf 8 982 tot 9 000.

Tel terug in 3’e vanaf 1 836 tot 1 800.

5.3 Tel aan in 5’e vanaf 4 870 tot 5 015.

Tel terug in 5’e vanaf 9 125 tot 8 980.

5.4 Tel aan in 10’e vanaf 8 960 tot 9 020.

Tel terug in 10’e vanaf 5 100 tot 4 980.

5.5 Tel aan in 25’s vanaf 7 625 tot 7 750.

Tel terug in 25’s vanaf 10 000 tot 9 875.

5.6 Tel aan in 50’s vanaf 8 250 tot 8 500.

Tel terug in 50’s vanaf 9 750 tot 9 500.

5.7 Tel aan in honderde vanaf 5 400 tot 6 000.

Tel terug in 100’e vanaf 7 000 tot 6 000.

DOEN DIT SELF! GESKREWE WERK. Gebruik jou sakrekenaar as 'n ondersoekmiddel terwyl jy met die ondersoek besig is en voltooi die geskrewe werk.

6. VLOEIDIAGRAMME:

  • Volg die pyle en voltooi hierdie “vloeidiagram”:
  • Voltooi hierdie vloeidiagram:

7. ‘N ANDER VLOEIDIAGRAM:

  • Vul die ontbrekende bewerking in, en die invoer- en uitvoergetalle:

8. NOG MEER GROOT GETALLE

Probeer om jou sakrekenaar vir "aantel" en "terugtel" te programmeer, indien jy dit nodig het. Voltooi die volgende reekse. Onthou dat jy jou sakrekenaar mag gebruik, as jy wil.

8.1 10 000; 9 998; 9 996; , , ,

8.2 1 950; 1 960; 1 970; , , ,

8.3 9 450; 9 550; 9 650; 9 750; , , ,

8.4 8 825; 8 820; 8 815; , , , ,

9. GROTER GETALLE IN ‘N VLOEIDIAGRAM.

  • Skryf die ontbrekende invoergetalle, die bewerking en die uitvoergetalle neer:

10. TEL IN INTERVALLE VAN VIER

  • Trek ‘n sirkel om al die getalle wat genoem sal word wanneer jy in 4’e tot by 10 000 tel.

Kontroleer met ‘n vriend, of met ‘n sakrekenaar, indien nodig.

Assessering

Leeruitkomstes(LUs)
LU 1
Getalle, Verwerkings en VerwantskappeDie leerder is in staat om getalle en die verwantskappe daarvan te herken, te beskryf en voor te stel, en om tydens probleemoplossing bevoeg en met selfvertroue te tel, te skat, te bereken en te kontroleer.
Assesseringstandaarde(ASe)
Dit is duidelik wanneer die leerder:
1.1 aan- en terugtel in ‘n verskeidenheid intervalle (insluitend 2’s, 3’e, 5’e, 10’e, 25’s, 50’s en 100’e) tussen 0 en minstens 10 000;
1.9 hoofberekeninge uitvoer wat die volgende behels:
  • optelling en aftrekking;
1.10 ‘n verskeidenheid tegnieke gebruik om sowel skriftelike as hoofberekeninge met heelgetalle te doen, insluitend:
  • opbou en afbreek van getalle;
  • afronding en kompensering;
  • verdubbeling en halvering;
  • gebruik van ‘n getallelyn;
  • gebruik van ‘n sakrekenaar.

Memorandum

AKTIWITEIT 1

TEL IN DIE ALLEDAAGSE WÊRELD

  • 594; 596; 598; 600; 602
  • 985; 990; 995; 1 000; 1 005
  • 670; 680; 690; 700; 710
  • 750; 775; 800; 825; 850
  • 800; 850; 900; 950; 1 000; 1 050
  • 700; 800; 900; 1 000; 1 100
  • 1 402 km
  • LAAT JOU SAKREKENAAR VIR JOU TEL

3. AANTEL EN TERUGTEL

3.1 186; 188; 190; 192; 194; 196; 198; 200; 202; 204

206; 204; 202; 200; 198; 196; 194;

3.2 0; 3; 6; 9; 12; 15; 18; 21; 24; 27; 30; 33; 36

36; 33; 30; 27; 24; 21; 18; 15; 12; 9; 6; 3; 0

3.3 375; 380; 385; 390; 395; 400; 405; 410; 415; 420; 425

545; 540; 535; 530; 525; 520; 515; 510; 505; 500; 495; 490; 485;

3.4 950; 960; 970; 980; 990; 1 000; 1 010; 1 020

950; 940; 930; 920; 910; 900; 890; 880; 870; 860; 850; 840

3.5 625; 650; 675; 700; 725; 750; 775; 800; 825; 850; 875 900; 925; 950; 975; 1 000

975; 950; 925; 900; 875; 850; 825; 700; 775; 750; 725; 600; 675

3.6 500; 550; 600; 650; 700; 750; 800; 850; 900; 950;

1 000; 1 050

750; 700; 650; 600; 550; 500; 450; 400; 350

3.7 400; 500; 600; 700; 800; 900; 1 000; 1 100

1 000; 900; 800; 700; 600; 500; 400; 300; 200; 100; 0

4. AANTEL EN TERUGTEL (indiwidueel)

5. TEL MET GROTER GETALLE (indiwiduele mondelinge werk; kontroleer met behulp van 'n sakrekenaar, indien nodig.)

5.9 980; 9 982; 9 984; 9 986; 9 988; 9 990; 9 992; 9 994; 9 996; 9 998; 10 000

5 010; 5 008; 5 006; 5 004; 5 002; 5 000; 4 998; 4 996; 4 994; 4 992; 4 990

5.2 8 982; 8 985; 8 988; 8 991; 8 994; 8 997

5.2 (vervolg) 1 836; 1 833; 1830; … 1 800

5.3 4 870; 4 875; 4 880l; … 5 015

9 125; 9 120; 9115; … 8 980

5.4 8 960; 8 970; 8 980; … 9 020

5 100; 5 090; 5080; …4 980

5.5 7 625; 7650; 7675; … 7 750

10 000; 9 975; 9 950; … 9 870

5.6 8 250; 8 300; 8 350; …8 500

9 750; 9 700; 9 650; … 9 500

  • 5 400; 5 500; 5 600; …6 000

7 000; 6 900; 6 800; … 6 000

6. VLOEIDIAGRAMME

6.1

98 101

298 301

+ 3

598 601

+ 3

698 701

898 901

  1. 1 001

6.2

991 988

972 969

- 3

963 960

+ 3

954 951

990 987

1 010 1 007

7.

1 525 1 550

1 550 1 575

+ 25

1 575 1 600

+ 3

1 600 1 625

1 625 1 650

1 650 1 675

8. NOG MEER GROOT GETALLE

8.1 9 994; 9 992; 9 990; 9 988

8.2 1 980; 1 990; 2 000; 2 010

8.3 9 850; 9950; 10 050; 10 150

8.4 8 810; 8 805; 8 800; 8 795

\

9. GROTER GETALLE IN ‘N VLOEIDIAGRAM

2 950 3 000

3 000 3 050

+ 50

3 050 3 100

+ 3

3 100 3 150

3 150 3 200

3 200 3 250

10 TEL IN INTERVALLE VAN VIER

Die enigste getalle wat nie 'n kring om het nie, is:

1 998

9 998

9 545

8 894

8 898

Questions & Answers

how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Wiskunde graad 4. OpenStax CNX. Sep 18, 2009 Download for free at http://cnx.org/content/col11100/1.1
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