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Wiskunde

Gewone breuke

Opvoeders afdeling

Memorandum

1. a) 3

b) 6

2. a) 4 7 size 12{ { { size 8{4} } over { size 8{7} } } } {} = 12 21 size 12{ { { size 8{"12"} } over { size 8{"21"} } } } {}

2 3 size 12{ { { size 8{2} } over { size 8{3} } } } {} = 14 21 size 12{ { { size 8{"14"} } over { size 8{"21"} } } } {}

<

b) 8 9 size 12{ { { size 8{8} } over { size 8{9} } } } {} = 80 90 size 12{ { { size 8{"80"} } over { size 8{"90"} } } } {}

9 10 size 12{ { { size 8{9} } over { size 8{"10"} } } } {} = 81 90 size 12{ { { size 8{"81"} } over { size 8{"90"} } } } {}

<

3. a) = 4 2 3 size 12{ { { size 8{2} } over { size 8{3} } } } {} + 4 5 size 12{ { { size 8{4} } over { size 8{5} } } } {}

= 4 10 15 size 12{ { { size 8{"10"} } over { size 8{"15"} } } } {} + 12 15 size 12{ { { size 8{"12"} } over { size 8{"15"} } } } {}

x = 5 7 15 size 12{ { { size 8{7} } over { size 8{"15"} } } } {}

b) = 2 1 3 size 12{ { { size 8{1} } over { size 8{3} } } } {} - 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {}

= 2 2 6 size 12{ { { size 8{2} } over { size 8{6} } } } {} - 3 6 size 12{ { { size 8{3} } over { size 8{6} } } } {}

z = 1 5 6 size 12{ { { size 8{5} } over { size 8{6} } } } {}

4. a) = 13 1 × 5 6 size 12{ { { size 8{"13"} } over { size 8{1} } } times { { size 8{5} } over { size 8{6} } } } {}

= 65 6 size 12{ { { size 8{"65"} } over { size 8{6} } } } {}

t = 10 5 6 size 12{ { { size 8{5} } over { size 8{6} } } } {}

b) = 30 56 size 12{ { { size 8{"30"} } over { size 8{"56"} } } } {}

t = 15 28 size 12{ { { size 8{"15"} } over { size 8{"28"} } } } {}

c) = 14 3 × 19 8 size 12{ { { size 8{"14"} } over { size 8{3} } } times { { size 8{"19"} } over { size 8{8} } } } {}

= 133 12 size 12{ { { size 8{"133"} } over { size 8{"12"} } } } {}

t = 11 1 12 size 12{"11" { { size 8{1} } over { size 8{"12"} } } } {}

5. a) = 36 35

48 x 50

j = 21

40

6.

a) = 6 1 × 2 5 size 12{ { { size 8{6} } over { size 8{1} } } times { { size 8{2} } over { size 8{5} } } } {}

w = 2 2 5 size 12{2 { { size 8{2} } over { size 8{5} } } } {}

b) = 7 9 × 1 3 size 12{ { { size 8{7} } over { size 8{9} } } times { { size 8{1} } over { size 8{3} } } } {}

d = 7 27 size 12{ { { size 8{7} } over { size 8{"27"} } } } {}

c) = 7 48 × 12 21 size 12{ { { size 8{7} } over { size 8{"48"} } } times { { size 8{"12"} } over { size 8{"21"} } } } {}

a = 1 12 size 12{ { { size 8{1} } over { size 8{"12"} } } } {}

d) = 13 4 × 8 19 size 12{ { { size 8{"13"} } over { size 8{4} } } times { { size 8{8} } over { size 8{"19"} } } } {}

= 26 19 size 12{ { { size 8{"26"} } over { size 8{"19"} } } } {}

g = 1 7 19 size 12{1 { { size 8{7} } over { size 8{"19"} } } } {}

7. a) = 13 2 × 9 4 size 12{ { { size 8{"13"} } over { size 8{2} } } times { { size 8{9} } over { size 8{4} } } } {} + 25 b) = 41 6 ÷ size 12{ { { size 8{"41"} } over { size 8{6} } } div } {} 3 2 9 size 12{3 { { size 8{2} } over { size 8{9} } } } {}

= 117 8 size 12{ { { size 8{"117"} } over { size 8{8} } } } {} + 25 = 41 6 ÷ 29 9 size 12{ { { size 8{"41"} } over { size 8{6} } } div { { size 8{"29"} } over { size 8{9} } } } {}

3

= 14 1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {} + 25 = 41 6 size 12{ { {"41"} over {6} } } {} size 12{ div } {} 9 29 size 12{ { {9} over {"29"} } } {}

2

v = 39 1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {} = 123 58 size 12{ { { size 8{"123"} } over { size 8{"58"} } } } {}

= 2 7 58 size 12{ { { size 8{7} } over { size 8{"58"} } } } {}

41 6 size 12{ { {"41"} over {6} } } {} size 12{ div } {} 29 9 size 12{ { {"29"} over {9} } } {}

Leerders afdeling

Inhoud

Aktiwiteit: module toets

1. Vul die ontbrekende antwoorde in:

a) . . . 7 = 24 56 size 12{ { { size 8{ "." "." "." } } over { size 8{7} } } = { { size 8{"24"} } over { size 8{"56"} } } } {}

b) 5 . . . = 25 30 size 12{ { { size 8{5} } over { size 8{ "." "." "." } } } = { { size 8{"25"} } over { size 8{"30"} } } } {}

(2)

2. Vul in:<;>of = :

a) 4 7 2 3 size 12{ { { size 8{4} } over { size 8{7} } } ~ * ~ { { size 8{2} } over { size 8{3} } } } {}

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b) 8 9 9 10 size 12{ { { size 8{8} } over { size 8{9} } } ~ * ~ { { size 8{9} } over { size 8{"10"} } } } {}

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(2)

3. Bereken:

a) x = 1 2 3 + 3 4 5 size 12{x=1 { { size 8{2} } over { size 8{3} } } +3 { { size 8{4} } over { size 8{5} } } } {}

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b) z = 6 1 3 4 1 2 size 12{z=6 { { size 8{1} } over { size 8{3} } } - 4 { { size 8{1} } over { size 8{2} } } } {}

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(3 × 2 = 6)

4. Bereken die waarde van t:

a) t = 13 × 5 6 size 12{t="13" times { { size 8{5} } over { size 8{6} } } } {}

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b) t = 6 7 × 5 8 size 12{t= { { size 8{6} } over { size 8{7} } } times { { size 8{5} } over { size 8{8} } } } {}

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(2 × 2 = 4)

c) t = 4 2 3 × 2 3 8 size 12{t=4 { { size 8{2} } over { size 8{3} } } times 2 { { size 8{3} } over { size 8{8} } } } {}

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(4)

5. Bereken die volgende deur van kansellering gebruik te maak:

a) j = 36 48 × 35 50 size 12{j= { { size 8{"36"} } over { size 8{"48"} } } times { { size 8{"35"} } over { size 8{"50"} } } } {}

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(2)

6. Vind die kwosiënt v.d. volgende:

a) w = 6 ÷ 5 2 size 12{w=6 div { { size 8{5} } over { size 8{2} } } } {}

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b) d = 7 9 ÷ 3 size 12{d= { { size 8{7} } over { size 8{9} } } div 3} {}

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(1 × 2 = 2)

c) a = 7 48 ÷ 21 12 size 12{a= { { size 8{7} } over { size 8{"48"} } } div { { size 8{"21"} } over { size 8{"12"} } } } {}

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d) g = 3 1 4 ÷ 2 3 8 size 12{g=3 { { size 8{1} } over { size 8{4} } } div 2 { { size 8{3} } over { size 8{8} } } } {}

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(2 + 3 = 5)

7. Pas die volgorde van bewerkings toe en bereken:

a) v = 6 1 2 × 2 1 4 + 5 8 of 40 size 12{v=6 { { size 8{1} } over { size 8{2} } } times 2 { { size 8{1} } over { size 8{4} } } + { { size 8{5} } over { size 8{8} } } `of`"40"} {}

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(4)

b) b = 6 5 6 ÷ 5 8 9 2 2 3 size 12{b=6 { { size 8{5} } over { size 8{6} } } div left (5 { { size 8{8} } over { size 8{9} } } - 2 { { size 8{2} } over { size 8{3} } } right )} {}

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(4)

(35)

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Source:  OpenStax, Wiskunde graad 7. OpenStax CNX. Oct 21, 2009 Download for free at http://cnx.org/content/col11076/1.2
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