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Persentasies

Opvoeders afdeling

Memorandum

18.2

KOSPRYS VERKOOPPRYS VERLIES/WINS % WINS/VERLIES
a) R623 24,92% wins
b) R80 28,57% verlies
c) R9,99 27,75% wins
d) R19,14 R2,64
e) R765 R135
  • a) 14%
  1. Werkvoorsiening; welsyns- en maatskaplike uitgawes; behuising; ens.
  2. Melk; vars groente; vars vrugte; vleis

19.3 a) 41c

b) R2,66

c) R69,86

  1. R770

20. Betaal eers BTW, dan afslag.

21.

a)>

b)<

c) =

d)<

e) =

f) =

g)>

h)>

i) 0,55

j) 0,125

k) 1,42

l) 0,03

m) 0,45

n) 0,075

o) 0,625

Leerders afdeling

Inhoud

Aktiwiteit: wins en verlies [lu 1.4, lu 2.3.3]

18. WINS EN VERLIES

18.1 Belangrik om te weet!

Wins = verkoopprys – kosprys

% wins = verkoopprys – kosprys
kosprys
×
100
1
= wins
kosprys
×
100
1

Verlies = wanneer jy meer vir ’n item betaal as waarvoor jydit verkoop

% verlies = verlies
kosprys
×
100
1

18.2 Voltooi die tabel met behulp van jou sakrekenaar.

Kosprys Verkoopprys Verlies / Wins % Wins / Verlies
Bv. R125 R160 R35 28% wins
a) R2 500 R3 123 ................. .........................
b) R280 R200 ................. .........................
c) R36 R45,99 ................. .........................
d) R16,50 ................. ................. 16% wins
e) R900 ................. ................. 15% verlies

19.1 Het jy geweet?

Belasting op toegevoegde waarde (BTW) is ’n bedrag geld wat deur die Minister van Finansies vasgestel word as deel van die regering se begroting. Dit word ook soms “verkoopbelasting” genoem.

19.2 Vind uit

a) Hoeveel % BTW moet ons tans betaal? ………………………………………..

…………………………………………………………………………………………..

b) Waarvoor gebruik die regering die geld wat hulle met BTW in?

…………………………………………………………………………………………..

…………………………………………………………………………………………..

c) Watter items is vrygestel van BTW? …………………………………………..

…………………………………………………………………………………………..

…………………………………………………………………………………………..

19.3 Bereken die BTW op die volgende teen 14% met behulp van jou sakrekenaar.

a) R2,95 : ………………………………………………………………………….

b) R18,99 : ………………………………………………………………………...

c) R499 : …………………………………………………………………………..

d) R 5 500 : ………………………………………………………………………..

20. KOPKRAPPER!

Jy koop ’n artikel kontant en kry 10% afslag, maar moet 14% BTW betaal. Wat is die voordeligste vir jou: om eers belasting te betaal en dan die afslag te kry, of andersom?

…………………………………………………………………………………………..

…………………………………………………………………………………………..

…………………………………………………………………………………………..

…………………………………………………………………………………………..

21. Kan jy die volgende hoofrekentoets binne 3 minute voltooi?

Vul in:<;>; = : Skryf as desimale breuk:
a) 0,8 ........... 8% i) 55% : ....................
b) 3 4 size 12{ { { size 8{3} } over { size 8{4} } } } {} ............ 76% j) 1 8 size 12{ { { size 8{1} } over { size 8{8} } } } {} : ....................
c) 60% ........... 0,6 k) 142% : ....................
d) 4 5 size 12{ { { size 8{4} } over { size 8{5} } } } {} ............ 85% l) 3% : ....................
e) 0,835 ........... 83,5% m) 9 20 size 12{ { { size 8{9} } over { size 8{"20"} } } } {} : ....................
f) 0,02 ........... 2% n) 7 1 2 size 12{7 { { size 8{1} } over { size 8{2} } } } {} % : ....................
g) 1 3 size 12{ { { size 8{1} } over { size 8{3} } } } {} ............ 33% o) 62 1 2 size 12{"62" { { size 8{1} } over { size 8{2} } } } {} % : ....................
h) 12,5% ............ 1 8 size 12{ { { size 8{1} } over { size 8{8} } } } {}

(15)

Assessering

Leeruitkomste 1: Die leerder is in staat om getalle en die verwantskappe daarvan te herken, te beskryf en voor te stel, en om tydens probleemoplossing bevoeg en met selfvertroue te tel, te skat, te bereken en te kontroleer.

Assesseringstandaard 1.4: Dit is duidelik wanneer die leerder ekwivalente vorms van rasionale getalle herken en gebruik;

Leeruitkomste 2: Die leerder is in staat om patrone en verwantskappe te herken, te beskryf en voor te stel en probleme op te los deur algebraïese taal en vaardighede te gebruik.

Assesseringstandaard 2.3: Dit is duidelik wanneer die leerder voorstellings maak van en verwantskappe tussen veranderlikes gebruik sodat inset- en/of uitsetwaardes op ‘n verskeidenheid maniere bepaal kan word deur die gebruik van:

2.3.3 tabelle.

Questions & Answers

can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
im not good at math so would this help me
Rachael Reply
yes
Asali
I'm not good at math so would you help me
Samantha
what is the problem that i will help you to self with?
Asali
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
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Source:  OpenStax, Wiskunde graad 7. OpenStax CNX. Oct 21, 2009 Download for free at http://cnx.org/content/col11076/1.2
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