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Wiskunde

Gewone breuke

Opvoeders afdeling

Memorandum

18.1

OPTELLING

1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {} + 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {} + 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {} + 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {} + 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {}

1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {} + 1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {} + 1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {} + 1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {} + 1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {} + 1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {}

3 7 size 12{ { { size 8{3} } over { size 8{7} } } } {} + 3 7 size 12{ { { size 8{3} } over { size 8{7} } } } {}

2 3 size 12{ { { size 8{2} } over { size 8{3} } } } {} + 2 3 size 12{ { { size 8{2} } over { size 8{3} } } } {} + 2 3 size 12{ { { size 8{2} } over { size 8{3} } } } {}

2 5 size 12{ { { size 8{2} } over { size 8{5} } } } {} + 2 5 size 12{ { { size 8{2} } over { size 8{5} } } } {} + 2 5 size 12{ { { size 8{2} } over { size 8{5} } } } {} + 2 5 size 12{ { { size 8{2} } over { size 8{5} } } } {}

PRODUK

2 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {}

1 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {}

6 7 size 12{ { { size 8{6} } over { size 8{7} } } } {}

2

1 3 5 size 12{ { { size 8{3} } over { size 8{5} } } } {}

b) Getallelyn / Teller x Teller

Noemer x Noemer

d)

(i) 21 10 size 12{ { { size 8{"21"} } over { size 8{"10"} } } } {}

= 2 1 10 size 12{ { { size 8{1} } over { size 8{"10"} } } } {}

(ii) 12 3 size 12{ { { size 8{"12"} } over { size 8{3} } } } {}

= 4

(iii) 84 9 size 12{ { { size 8{"84"} } over { size 8{9} } } } {}

= 9 1 3 size 12{ { { size 8{1} } over { size 8{3} } } } {}

19.1

a) 1

b) 1

c) 1

d) 1

19.2 Produk is elke keer 1

19.4 a) 20 17 size 12{ { { size 8{"20"} } over { size 8{"17"} } } } {}

b) 1 40 size 12{ { { size 8{1} } over { size 8{"40"} } } } {}

c) 5 31 size 12{ { { size 8{5} } over { size 8{"31"} } } } {}

d) 8 73 size 12{ { { size 8{8} } over { size 8{"73"} } } } {}

19.5 c) 5 31 size 12{ { { size 8{5} } over { size 8{"31"} } } } {} : Maak eers onegte breuk ( 31 5 size 12{ { { size 8{"31"} } over { size 8{5} } } } {} )

d) 8 73 size 12{ { { size 8{8} } over { size 8{"73"} } } } {} : Maak eers onegte breuk ( 73 8 size 12{ { { size 8{"73"} } over { size 8{8} } } } {} )

20. a) 1 2 3 size 12{ { { size 8{2} } over { size 8{3} } } } {} x 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {}

= 5 3 size 12{ { { size 8{5} } over { size 8{3} } } } {} x 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {}

= 5 6 size 12{ { { size 8{5} } over { size 8{6} } } } {} m = 83, 3 . size 12{ {3} cSup { size 8{ "." } } } {} cm

b) 5 6 size 12{ { { size 8{5} } over { size 8{6} } } } {} x 1 3 size 12{ { { size 8{1} } over { size 8{3} } } } {} = 5 18 size 12{ { { size 8{5} } over { size 8{"18"} } } } {} m

= 27, 7 . size 12{ {7} cSup { size 8{ "." } } } {} cm

22.

(a) 32

(b) 15

(c) 25

(d) 25

(e) 45

(f) 2

(g) 8

(h) 7

(i) 7

(j) 6

(k) 6

(l) 8

(m) 8

(n) 8

(o) 100

Leerders afdeling

Inhoud

Aktiwiteit: vermenigvuldiging van breuke [lu 1.7.3, lu 2.1.5]

18. VERMENIGVULDIGING VAN BREUKE

18.1 Vermenigvuldiging van breuke met natuurlike getalle

Jy weet reeds dat vermenigvuldiging eintlik herhaalde optelling is.

a) Kyk of jy die volgende tabel kan voltooi:

b) Kyk goed na die voltooide tabel. Kan jy aan ’n korter manier / metode dink om die antwoorde te vind?

..........................................................................................................................................

..........................................................................................................................................

..........................................................................................................................................

c) LET OP!

Jy kan ook dié metode volg:

1. Skryf albei getalle as breuke, bv. 6 × 1 4 = 6 1 × 1 4 size 12{6 times { { size 8{1} } over { size 8{4} } } = { { size 8{6} } over { size 8{1} } } times { { size 8{1} } over { size 8{4} } } } {}

2. Vermenigvuldig die tellers met mekaar: 6 × 1 = 6

3. Vermenigvuldig die noemers met mekaar: 1 × 4 = 4

4. Vereenvoudig die antwoord: 6 4 = 1 2 4 = 1 1 2 size 12{ { { size 8{6} } over { size 8{4} } } =1 { { size 8{2} } over { size 8{4} } } =1 { { size 8{1} } over { size 8{2} } } } {}

d) Bereken:

(i) 7 × 3 10 size 12{7 times { { size 8{3} } over { size 8{"10"} } } } {}

___________________________________________________

___________________________________________________

___________________________________________________

___________________________________________________

(ii) 2 3 × 6 size 12{ { { size 8{2} } over { size 8{3} } } times 6} {}

___________________________________________________

___________________________________________________

___________________________________________________

___________________________________________________

(iii) 12 × 7 9 size 12{"12" times { { size 8{7} } over { size 8{9} } } } {}

___________________________________________________

___________________________________________________

___________________________________________________

___________________________________________________

e) Op ’n getallelyn sou ons 6 × 1 4 size 12{6 times { { size 8{1} } over { size 8{4} } } } {} so kon voorstel:

f) Stel die volgende op ’n getallelyn voor: x = 4 × 2 3 size 12{x=4 times { { size 8{2} } over { size 8{3} } } } {}

18.2 Vermenigvuldiging van breuke met breuke

a) Kyk goed na die volgende voorbeelde:

(i) Die helfte ( 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {} ) van ’n driekwart ( 3 4 size 12{ { { size 8{3} } over { size 8{4} } } } {} ) kan so voorgestel word:

Dus: 1 2 × 3 4 = 3 8 size 12{ { { size 8{1} } over { size 8{2} } } times { { size 8{3} } over { size 8{4} } } = { { size 8{3} } over { size 8{8} } } } {}

(ii) Een derde ( 1 3 size 12{ { { size 8{1} } over { size 8{3} } } } {} ) van ’n half ( 1 2 size 12{ { { size 8{1} } over { size 8{2} } } } {} ) lyk so:

Dus 1 3 × 1 2 = 1 6 size 12{ { { size 8{1} } over { size 8{3} } } times { { size 8{1} } over { size 8{2} } } = { { size 8{1} } over { size 8{6} } } } {}

b) Maak nou soortgelyke sketse vir:

(i) 1 5 × 1 2 size 12{ { { size 8{1} } over { size 8{5} } } times { { size 8{1} } over { size 8{2} } } } {}

(ii) 3 10 × 1 2 size 12{ { { size 8{3} } over { size 8{"10"} } } times { { size 8{1} } over { size 8{2} } } } {}

c) LET OP!

As ons ’n breuk met ’n breuk vermenigvuldig, bv. 2 3 × 3 8 size 12{ { { size 8{2} } over { size 8{3} } } times { { size 8{3} } over { size 8{8} } } } {}

1. Vermenigvuldig ons eers die tellers met mekaar: 2 × 3 = 6

2. Dan vermenigvuldig ons die noemers met mekaar: 3 × 8 = 24

3. Ons vereenvoudig ook waar nodig: 6 ÷ 6 24 ÷ 6 = 1 4 size 12{ { { size 8{6~ div ~6} } over { size 8{"24"~ div ~6} } } = { { size 8{1} } over { size 8{4} } } } {}

d) Onthou jy nog?

Om te kan vereenvoudig , moet jy altyd die teller en die noemer deur dieselfde getal deel .

e) Het jy geweet?

Ons kan ook van kansellering gebruik maak om die produk te bepaal.

Questions & Answers

how does Neisseria cause meningitis
Nyibol Reply
what is microbiologist
Muhammad Reply
what is errata
Muhammad
is the branch of biology that deals with the study of microorganisms.
Ntefuni Reply
What is microbiology
Mercy Reply
studies of microbes
Louisiaste
when we takee the specimen which lumbar,spin,
Ziyad Reply
How bacteria create energy to survive?
Muhamad Reply
Bacteria doesn't produce energy they are dependent upon their substrate in case of lack of nutrients they are able to make spores which helps them to sustain in harsh environments
_Adnan
But not all bacteria make spores, l mean Eukaryotic cells have Mitochondria which acts as powerhouse for them, since bacteria don't have it, what is the substitution for it?
Muhamad
they make spores
Louisiaste
what is sporadic nd endemic, epidemic
Aminu Reply
the significance of food webs for disease transmission
Abreham
food webs brings about an infection as an individual depends on number of diseased foods or carriers dully.
Mark
explain assimilatory nitrate reduction
Esinniobiwa Reply
Assimilatory nitrate reduction is a process that occurs in some microorganisms, such as bacteria and archaea, in which nitrate (NO3-) is reduced to nitrite (NO2-), and then further reduced to ammonia (NH3).
Elkana
This process is called assimilatory nitrate reduction because the nitrogen that is produced is incorporated in the cells of microorganisms where it can be used in the synthesis of amino acids and other nitrogen products
Elkana
Examples of thermophilic organisms
Shu Reply
Give Examples of thermophilic organisms
Shu
advantages of normal Flora to the host
Micheal Reply
Prevent foreign microbes to the host
Abubakar
they provide healthier benefits to their hosts
ayesha
They are friends to host only when Host immune system is strong and become enemies when the host immune system is weakened . very bad relationship!
Mark
what is cell
faisal Reply
cell is the smallest unit of life
Fauziya
cell is the smallest unit of life
Akanni
ok
Innocent
cell is the structural and functional unit of life
Hasan
is the fundamental units of Life
Musa
what are emergency diseases
Micheal Reply
There are nothing like emergency disease but there are some common medical emergency which can occur simultaneously like Bleeding,heart attack,Breathing difficulties,severe pain heart stock.Hope you will get my point .Have a nice day ❣️
_Adnan
define infection ,prevention and control
Innocent
I think infection prevention and control is the avoidance of all things we do that gives out break of infections and promotion of health practices that promote life
Lubega
Heyy Lubega hussein where are u from?
_Adnan
en français
Adama
which site have a normal flora
ESTHER Reply
Many sites of the body have it Skin Nasal cavity Oral cavity Gastro intestinal tract
Safaa
skin
Asiina
skin,Oral,Nasal,GIt
Sadik
How can Commensal can Bacteria change into pathogen?
Sadik
How can Commensal Bacteria change into pathogen?
Sadik
all
Tesfaye
by fussion
Asiina
what are the advantages of normal Flora to the host
Micheal
what are the ways of control and prevention of nosocomial infection in the hospital
Micheal
what is inflammation
Shelly Reply
part of a tissue or an organ being wounded or bruised.
Wilfred
what term is used to name and classify microorganisms?
Micheal Reply
Binomial nomenclature
adeolu
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Source:  OpenStax, Wiskunde graad 7. OpenStax CNX. Oct 21, 2009 Download for free at http://cnx.org/content/col11076/1.2
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