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A Java program can be syntactically correct but still not compile because of errors related to the semantics of the language.

This group of errors results from code that is syntactically correct but violates the semantics of Java, in particular the rules relating to type checking.

variable ... might not have been initialized

An instance variable declared in a class has a default initial value. A class is a template that is used to create or instantiate instances called objects . Since memory is allocated separately for each object, these variables are called instance variables . However, a local variable declared within a method does not, so you are required to initialize it before use, either in its declaration or in anassignment statement:

void m(int n) {   // n is initialized from the actual parameter   int i, j;  i = 2;             // i is initialized by the assignment   int k = 1;         // k is initialized in its declaration  if (i == n)        // OK     k = j;           // Error, j is not initialized  else     j = k;}

The variable must be initialized on every path from declaration to use even if the semantics of the program ensure that the path cannot be taken:

void m(int n) {   int i;  if (n == n)           // Always true     i = n;  else     n = i;              // Error, although never executed!!}

Eclipse: The local variable ... may not have been initialized

Note: If the expression in the if -statement can be computed at compile-time:

if (true)                  // OK if ('n' == 'n')            // OK

the error will not occur.

... in ... cannot be applied to ...

This error message is very common and results from an incompatibility between a method call and the method's declaration:

void m(int i) { ... }  m(5.5);        // Error, the literal is of type double, not int

Check the declaration and call carefully. You can also get the error message cannot find symbol if the declaration of the method is in the API. The Application Programming Interface (API) describes how to use the library of classes supplied as part of the Java system. Byextension, it is also used as a name for the library itself.

Eclipse: The method ... in the type ... is not applicable for the arguments ...

operator ... cannot be applied to ...,...

Operators are only defined for certain types, although implicit type conversion is allowed between certain numeric types:

int a = 5; boolean b = true;int c = a + b;       // Error, can't add a boolean value double d = a + 1.4;  // OK, int is implicitly converted to double

Eclipse: The operator + is undefined for the argument type(s) int, boolean

possible loss of precision

This error arises when trying to assign a value of higher precision to a variable of lower precision without anexplicit type cast. Surprisingly, perhaps, floating point literals are of type double and you will get this message if you try to assign one to a variable of type float :

float sum = 0.0;          // Error, literal is not of type float

The correct way to do this is to use a literal of type float or an explicit type cast:

float sum = 0.0f;         // OK float sum = (float) 0.0;  // OK

Eclipse: Type mismatch: cannot convert from double to float

incompatible types

Java checks that the type of an expression is compatible with the type of the variable in an assignment statement and this error will result ifthey are incompatible:

boolean b = true; int a = b;              // Error, can't assign boolean to int

Eclipse: Type mismatch: cannot convert from boolean to int

Important note
In the C language it is (unfortunately!) legal to write if (a = b) using the assignment operator instead of if (a == b) using the equality operator. The meaning is to execute the assignment, convert the value to an integerand use its value to make the decision for the if -statement (zero is false and non-zero is true). In Java, the assignment is legal and results in a value,but (unless a is of type boolean !) this error message will result because the expression in an if -statement must be of type boolean , not int . Writing == instead of = becomes a simple compile-time error in Java, whereas in C this error leads to runtime errors that are extremelydifficult to find.

inconvertible types

Not every type conversion is legal:

boolean b = true; int x = (int) b;   // Error, can't convert boolean to int

Eclipse: Type mismatch: cannot convert from ... to ...

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
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how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
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sure. what is your question?
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I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
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Commplementary angles
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what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
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a perfect square v²+2v+_
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Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
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. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
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types of nano material
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I start with an easy one. carbon nanotubes woven into a long filament like a string
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Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
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what is system testing
what is the application of nanotechnology?
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
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after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
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how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
silver nanoparticles could handle the job?
not now but maybe in future only AgNP maybe any other nanomaterials
I'm interested in Nanotube
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Compile and runtime errors in java. OpenStax CNX. Dec 28, 2009 Download for free at http://cnx.org/content/col10913/1.2
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