<< Chapter < Page Chapter >> Page >

Grading

This is a two-week lab. Your prelab is due a week after the quiz for Lab 4, and the quizzing occurs two weeks after thequiz for Lab 4.

Grading for this lab will be a bit different from past labs:

  • 1 point: Prelab
  • 2 points: Working code, implemented from scratch in assembly language or C.
  • 5 points: Optimization. These points will be assigned based on your cycle counts and the optimizations you have made.
  • 2 points: Oral quiz.

Appendix a:

fsk.c

SINE.asm

C_ASM.bat

1 /* ECE320, Lab 5, Reference Implementation (Non-Optimized) */ 2 /* Michael Frutiger 2/24/04 */ 3 4 #include "v:/ece320/54x/dspclib/core.h" /* Declarations for core file */ 5 6 main() 7 { 8 int *Rcvptr,*Xmitptr; /* pointers to Xmit & Rcv Bufs */ 9 int r1,r2; // temp random bit storage 10 int symbol; // 0 for [00], 1 for [01], 2 for [10], 3 for [11] 11 int n; // dummy variable 12 13 int freqs[4] = {9, 13, 21, 17}; // 32*freqs 14 int phase[32]; 15 int output[64]; // temp output storage 16 17 18 // Initial PN generator register contents 19 int seed = 1; 20 21 // Initial phase 22 int prev_phase = 0; 23 24 25 while( 1 ) 26 { 27 /* Wait for a new block of samples */ 28 WaitAudio(&Rcvptr,&Xmitptr); 29 30 // Get next two random bits 31 r1 = randbit( &seed ); 32 r2 = randbit( &seed ); 33 // Convert 2 bit binary number to decimal 34 symbol = series2parallel(r1,r2); 35 36 for (n=0; n<32; n++) 37 { 38 phase[n] = ( freqs[symbol]*n + prev_phase ) % 64; // get into 0 to 64 range 39 if (phase[n] > 32) phase[n]=phase[n]-64; // get into -32 to 32 range 40 phase[n] = phase[n] * 1024; // 1024=2^15*1/32 41 // [-2^15 2^15] range for use with 42 // SINE.asm 43 } 44 sine(&phase[0], &output[0], 32); // compute SINE, put result in output[0 - 31] 45 prev_phase = ( freqs[symbol]*32 + prev_phase ) % 64; // save current phase offset 46 47 // Get next two random bits 48 r1 = randbit( &seed ); 49 r2 = randbit( &seed ); 50 // Convert 2 bit binary number to decimal 51 symbol = series2parallel(r1,r2); 52 53 for (n=0; n<32; n++) 54 { 55 phase[n] = ( freqs[symbol]*n + prev_phase ) % 64; 56 if (phase[n] > 32) phase[n]=phase[n]-64; 57 phase[n] = phase[n] * 1024; 58 } 59 sine(&phase[0], &output[32], 32); 60 prev_phase = ( freqs[symbol]*32 + prev_phase ) % 64; 61 62 63 // Transfer the two symbols to transmit buffer 64 for (n=0; n<64; n++) 65 { 66 Xmitptr[6*n] = output[n]; 67 } 68 69 } 70 } 71 72 73 // Converts 2 bit binary number (r2r1) to decimal 74 int series2parallel(int r2, int r1) 75 { 76 if ((r2==0)&&(r1==0)) return 0; 77 else if ((r2==0)&&(r1==1)) return 1; 78 else if ((r2==1)&&(r1==0)) return 2; 79 else return 3; 80 } 81 82 //Returns as an integer a random bit, based on the 15 low-significance bits in iseed (which is 83 //modified for the next call). 84 int randbit(unsigned int *iseed) 85 { 86 unsigned int newbit; // The accumulated XORs. 87 newbit = (*iseed >> 14) & 1 ^ (*iseed >> 13) & 1; // XOR bit 15 and bit 14 88 // Leftshift the seed and put the result of the XORs in its bit 1. 89 *iseed=(*iseed << 1) | newbit; 90 return (int) newbit; 91 }

Questions & Answers

how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
Privacy Information Security Software Version 1.1a
Good
Got questions? Join the online conversation and get instant answers!
QuizOver.com Reply

Get the best Algebra and trigonometry course in your pocket!





Source:  OpenStax, Ece 320 spring 2004. OpenStax CNX. Aug 24, 2004 Download for free at http://cnx.org/content/col10225/1.12
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Ece 320 spring 2004' conversation and receive update notifications?

Ask