# 1.3 Game 2302-0110: updating the game math library for graphics  (Page 20/20)

 Page 20 / 20

## Exercise 1

Using Java and the game-math library named GM2D02 , or using a different programming environment of your choice, write a program that draws a horizontalline segment and a vertical line segment representing the x and y axes in a 2D Cartesian coordinate system as shown in Figure 2 .

Cause the origin of your reference frame be at the center of your drawing.

Cause the positive x direction be to the right.

Cause the positive y direction be either up or down according to your choice.

Cause the program to display your name in some manner.

Figure 2 Graphic output from Exercise 1.

## Exercise 2

Using Java and the game-math library named GM2D02 , or using a different programming environment of your choice, write a program that draws x and y axes in a 2DCartesian coordinate system as shown in Figure 3 .

Cause the origin of your reference frame be at the center of your drawing.

Cause the positive x direction be to the right.

Cause the positive y direction be either up or down according to your choice.

Then draw small circles that represent the locations of points at the following coordinates in the reference frame as shown in Figure 3 .

• x = -30, y = -40
• x = 30, y = -40
• x = 30, y = 40

Cause the program to display your name in some manner.

Figure 3 Graphic output from Exercise 2.

## Exercise 3

Using Java and the game-math library named GM2D02 , or using a different programming environment of your choice, write a program that draws xand y axes in a 2D Cartesian coordinate system as shown in Figure 4 .

Cause the origin of your reference frame be at the center of your drawing.

Cause the positive x direction be to the right.

Cause the positive y direction be either up or down according to your choice.

Create six random values in the range from -128 to +127. Use those values as the x and ycoordinates for three points in the 2D reference frame. (The code fragment in Listing 29 shows how to generate random values in the required range in Java.)

Display the six values on a text screen labeled in such a way that it is possible to associate the valueswith the points as shown in Figure 5 .

Draw three small circles that represent the locations of the points.

Draw three line segments that connect the three points in pairs creating the shape of a triangle.

Cause the program to display your name in some manner.

Figure 4 Graphic output from Exercise 3.

Figure 5 . Text output from Exercise 3.
```point0X: -55 point0Y: 17point1X: 9 point1Y: -37point2X: 14 point2Y: 62```
Listing 29. Code for generating random values in Java.
```//Define three randomly located points. Random generator = new Random(new Date().getTime());point0X = (byte)generator.nextInt(); point0Y = (byte)generator.nextInt();point1X = (byte)generator.nextInt(); point1Y = (byte)generator.nextInt();point2X = (byte)generator.nextInt(); point2Y = (byte)generator.nextInt();```

## Exercise 4

Using Java and the game-math library named GM2D02 , or using a different programming environment of your choice, write a program that draws three small circles that represent thelocations of points at the following coordinates in a 2D reference frame.

• point0X = -30
• point0Y = 0
• point1X = 30
• point1Y = 40
• point2X = 30
• point2Y = -40

Then draw three line segments that extend from edge-to-edge of your drawing and intersect the threepoints in pairs as shown in Figure 6 .

Cause the origin of your reference frame be at the center of your drawing.

Cause the positive x direction to be to the right.

Cause the positive y direction be either up or down according to your choice.

Cause the program to display your name in some manner.

Figure 6 Graphic output from Exercise 4.

## Exercise 5

Using Java and the game-math library named GM2D02 , or using a different programming environment of your choice, write a program that draws 24 vectors tail-to-tail in alternatingcolors of red, green, and blue as shown in Figure 7 .

The first vector is red.

The length of each vector is 100 pixels.

The direction of the first vector is +7.5 degrees relative to the horizontal.

The direction of each successive vector is increased by 15 degrees.

For example, the directions of the first four vectors are:

• 7.5
• 22.5
• 37.5
• 52.5

Draw the symbol of your choice to identify the head of each vector.

Draw the axes for a Cartesian coordinate system in the reference frame.

Cause the positive x direction to be to the right.

Cause the positive y direction be either up or down according to your choice.

Cause positive angles to be either clockwise or counter-clockwise according to your choice.

Cause the program to display your name in some manner.

Figure 7 Graphic output from Exercise 5.

## Exercise 6

Using Java and the game-math library named GM2D02 , or using a different programming environment of your choice, write a program that draws24 vectors tail-to-head in alternating colors of red, green, and blue as shown in Figure 8 .

The first vector is red.

The length of each vector is approximately 17 pixels.

Draw the symbol of your choice to identify the head of each vector.

Draw the axes for a Cartesian coordinate system in the reference frame.

Cause the positive x direction to be to the right.

Cause the positive y direction be either up or down according to your choice.

Cause positive angles to be either clockwise or counter-clockwise according to your choice.

Cause the program to display your name in some manner.

Figure 8 Graphic output from Exercise 6.

## Exercise 7

Using Java and the game-math library named GM2D02 , or using a different programming environment of your choice, write a program that draws 24 vectors tail-to-head in alternatingcolors of red, green, and blue as shown in Figure 9 .

The first vector is red.

Begin with a length of 24 pixels for the first vector and reduce the length of each successive vector by one pixel.

Draw the symbol of your choice to identify the head of each vector.

Draw the axes for a Cartesian coordinate system in the reference frame.

Cause the positive x direction to be to the right.

Cause the positive y direction be either up or down according to your choice.

Cause positive angles to be either clockwise or counter-clockwise according to your choice.

Cause the program to display your name in some manner.

Figure 9 Graphic output from Exercise 7.

-end-

can someone help me with some logarithmic and exponential equations.
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
Commplementary angles
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
a perfect square v²+2v+_
kkk nice
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
rolling four fair dice and getting an even number an all four dice
Kristine 2*2*2=8
Differences Between Laspeyres and Paasche Indices
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
is it 3×y ?
J, combine like terms 7x-4y
im not good at math so would this help me
yes
Asali
I'm not good at math so would you help me
Samantha
what is the problem that i will help you to self with?
Asali
how do you translate this in Algebraic Expressions
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
what's the easiest and fastest way to the synthesize AgNP?
China
Cied
types of nano material
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
what is nanomaterials​ and their applications of sensors.
what is nano technology
what is system testing?
preparation of nanomaterial
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
what is system testing
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
can nanotechnology change the direction of the face of the world
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
how did you get the value of 2000N.What calculations are needed to arrive at it
Privacy Information Security Software Version 1.1a
Good
Got questions? Join the online conversation and get instant answers!