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Listing 24 . Source code for the program named VectorAdd04.

/*VectorAdd04.java Copyright 2008, R.G.BaldwinRevised 02/15/08 This program illustrates the addition of a Vector to aPoint producing a new Point. Both points and the vector are drawn on the screen.Tested using JDK 1.6 under WinXP. *********************************************************/import java.awt.*; import javax.swing.*;import java.awt.geom.*; class VectorAdd04{public static void main(String[] args){GUI guiObj = new GUI(); }//end main}//end controlling class VectorAdd04 //======================================================//class GUI extends JFrame{ //Specify the horizontal and vertical size of a JFrame// object. int hSize = 225;int vSize = 225; Image osi;//an off-screen imageint osiWidth;//off-screen image width int osiHeight;//off-screen image heightMyCanvas myCanvas;//a subclass of CanvasGUI(){//constructor //Set JFrame size, title, and close operation.setSize(hSize,vSize); setTitle("Copyright 2008,R.G.Baldwin");setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);//Create a new drawing canvas and add it to the // center of the JFrame.myCanvas = new MyCanvas(); this.getContentPane().add(myCanvas);//This object must be visible before you can get an// off-screen image. It must also be visible before // you can compute the size of the canvas.setVisible(true); osiWidth = myCanvas.getWidth();osiHeight = myCanvas.getHeight(); //Create an off-screen image and get a graphics// context on it. osi = createImage(osiWidth,osiHeight);Graphics2D g2D = (Graphics2D)(osi.getGraphics());//Draw some graphical objects on the off-screen // image.drawOffScreen(g2D); //Cause the overridden paint method belonging to// myCanvas to be executed. myCanvas.repaint();}//end constructor //----------------------------------------------------////The purpose of this method is to add a Vector object// to a Point object and to draw the result onto an // off-screen image..void drawOffScreen(Graphics2D g2D){//Translate the origin on the off-screen // image and draw a pair of orthogonal axes on it.setCoordinateFrame(g2D); //Define one pointGM2D04.Point point = new GM2D04.Point( new GM2D04.ColMatrix(50,-25));//Define one vector.GM2D04.Vector vecA = new GM2D04.Vector( new GM2D04.ColMatrix(25,-50));//Add the Vector object to the Point object producing// a new Point object GM2D04.Point newPoint = point.addVectorToPoint(vecA);//Draw vecA in RED with its tail at the original// point. g2D.setColor(Color.RED);vecA.draw(g2D,point);//Draw the original point in GREEN. g2D.setColor(Color.GREEN);point.draw(g2D);//Draw the new point in BLUE. g2D.setColor(Color.BLUE);newPoint.draw(g2D); }//end drawOffScreen//----------------------------------------------------// //This method is used to set the origin of the// off-screen image and to draw orthogonal axes on the // off-screen image that intersect at the origin.private void setCoordinateFrame(Graphics2D g2D){ //Translate the origin to a point near the lower-left// corner of the off-screen image. g2D.translate(0.2*osiWidth,0.8*osiHeight);//Draw new X and Y-axes in default BLACK g2D.drawLine(-(int)(0.2*osiWidth),0,(int)(0.8*osiWidth),0);g2D.drawLine(0,-(int)(0.8*osiHeight), 0,(int)(0.2*osiHeight));}//end setCoordinateFrame method//====================================================////This is an inner class of the GUI class.class MyCanvas extends Canvas{ //Override the paint() method. This method will be// called when the JFrame and the Canvas appear on the // screen or when the repaint method is called on the// Canvas object. //The purpose of this method is to display the// off-screen image on the screen. public void paint(Graphics g){g.drawImage(osi,0,0,this); }//end overridden paint()}//end inner class MyCanvas}//end class GUI//======================================================//

Exercises

Exercise 1

Using Java and the game-math library named GM2D04 , or using a different programming environment of your choice, write a program that creates twelve random values in theapproximate range from -64 to +63. Use those values in pairs to define six mathematical vectors.

Draw the six vectors in a head-to-tail arrangement in alternating colors of green and blue with the tail ofthe first vector at the origin as shown in Figure 8 .

Compute and draw the sum of the six vectors in red with the tail of the sum vector at the origin.

Cause the origin of your reference frame to be at the center of your drawing and draw the axes for a Cartesiancoordinate system in the reference frame in black.

Cause the positive x direction to be to the right.

Cause the positive y direction be either up or down according to your choice.

Use a symbol of your choice to indicate the head of each vector.

Cause the program to display your name in some manner.

Figure 8 Screen output from Exercise 1.

Missing image.

Exercise 2

Using Java and the game-math library named GM2D04 , or using a different programming environment of your choice, write a program that creates four random values in theapproximate range from -128 to +127. Use those values in pairs to define two mathematical vectors.

Create a third vector as the sum of the first two vectors.

Using red, green, and blue, draw the three vectors in a way that illustrates the parallelogram rule for vectoraddition as shown in Figure 9 .

Cause the origin of your reference frame to be at the center of your drawing and draw the axes for a Cartesiancoordinate system in the reference frame in black.

Cause the positive x direction to be to the right. Cause the positive y direction be either up or downaccording to your choice.

Use a symbol of your choice to indicate the head of each vector.

Cause the program to display your name in some manner.

Because of the random nature of the vectors, you may need to run your program more than once to open up the vectordiagram and get a clear picture of the parallelogram rule for vector addition.

Figure 9 Screen output from Exercise 2.

Missing image.

-end-

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
Abhi
how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
hmm
Abhi
is it a question of log
Abhi
🤔.
Abhi
I rally confuse this number And equations too I need exactly help
salma
But this is not salma it's Faiza live in lousvile Ky I garbage this so I am going collage with JCTC that the of the collage thank you my friends
salma
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
hi
salma
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Game 2302 - mathematical applications for game development. OpenStax CNX. Jan 09, 2016 Download for free at https://legacy.cnx.org/content/col11450/1.33
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