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The algebraic solution

Once you work through the algebra for this problem, you will have determined that the answer to the problem is given by the following expression:

centripetal force = 2kg * (5/s) *(3m/s)

Let Google do the work

Enter the following expression into the Google search box and press the Enter key:

2kg * (5/s) *(3m/s)

The following text should appear immediately below the search box.

2 kg * (5 / s) * (3 (m / s)) = 30 newtons

Note that in this case, I used the correct symbols for SI units.

Do it again with the units spelled differently

Enter the following expression into the search box and press the Enter key.

2 kilograms * (5 radians/second) * (3 meters/second)

The following text should appear immediately below the search box.

2 kilograms * ((5 radians) / second) * (3 (meters / second)) = 30 newtons

Do it one more time

Let's do it one more time, this time mixing metric and English units. Enter the following expression into the search box and press the Enter key.

2 kilograms * (5 radians/second) * (9.8425197 feet/second)

The following output should appear below the search box:

2 kilograms * ((5 radians) / second) * (9.8425197 (feet / second)) = 30 newtons

The conclusion

Given an input with units in the correct format, the Google calculator is not only able to deal with those units and perform the calculation correctly, it is also able to properly convertthe result to the correct value in derived units (newtons in this case).

Other units

When analyzing a physics problem, the safest approach is probably to convert all of the given information into SI units and solve the problem in SI units,converting the result back to some other system of units if required. However, some textbooks and some physics professors may not allow that approach.Therefore, you need to know something about the other units of force that you may encounter.


As you learned in an earlier module, the pound is a unit of mass.

There is a very handy online mass unit converter at (External Link) . However, I don't know if it is accessible for screen readers and Braille displays. According to thatconverter,

1 pound = 0.45359237 kilograms

Can use Google for conversion

Even if that converter isn't accessible, you can use the Google calculator to make such conversions. Enter the following in the Google search box and press the Enter key:

conversion pound to kilogram

The following text should appear immediately below the search box:

1 pound = 0.45359237 kilograms

The foot

A foot is a unit of length commonly used for measurements in the United States.

1 foot = 0.3048 meters

The poundal unit of force

A poundal is a unit of force that causes a mass of one pound to accelerate at one foot per second squared (1 ft/s^2).

Because the poundal and the newton are both units of force, we can convert from one to the other as follows:

1 poundal = 0.138254954 newton


The gram is another unit of mass and the centimeter is another unit of length.

1 gram = 0.001 kilogram

1 centimeter = 0.01 meter

The dyne unit of force

Questions & Answers

how to know photocatalytic properties of tio2 nanoparticles...what to do now
Akash Reply
it is a goid question and i want to know the answer as well
Do somebody tell me a best nano engineering book for beginners?
s. Reply
what is fullerene does it is used to make bukky balls
Devang Reply
are you nano engineer ?
what is the Synthesis, properties,and applications of carbon nano chemistry
Abhijith Reply
Mostly, they use nano carbon for electronics and for materials to be strengthened.
is Bucky paper clear?
so some one know about replacing silicon atom with phosphorous in semiconductors device?
s. Reply
Yeah, it is a pain to say the least. You basically have to heat the substarte up to around 1000 degrees celcius then pass phosphene gas over top of it, which is explosive and toxic by the way, under very low pressure.
Do you know which machine is used to that process?
how to fabricate graphene ink ?
for screen printed electrodes ?
What is lattice structure?
s. Reply
of graphene you mean?
or in general
in general
Graphene has a hexagonal structure
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what is biological synthesis of nanoparticles
Sanket Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
many many of nanotubes
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I'm interested in nanotube
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
what is system testing
what is the application of nanotechnology?
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
anybody can imagine what will be happen after 100 years from now in nano tech world
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
silver nanoparticles could handle the job?
not now but maybe in future only AgNP maybe any other nanomaterials
I'm interested in Nanotube
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
can nanotechnology change the direction of the face of the world
Prasenjit Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
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Source:  OpenStax, Accessible physics concepts for blind students. OpenStax CNX. Oct 02, 2015 Download for free at https://legacy.cnx.org/content/col11294/1.36
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