0.8 Jbs2040-an audio graph of a sinusoid  (Page 5/7)

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Listing 6 ends by scaling the gain factor by 8000 to produce a reasonable audio output level.

Compute the gain for the left and right speakers

Listing 7 examines the sign (positive or negative) of the current value of the sinusoidal function (based on the pulse frequency relative to the center frequency) and uses that information to compute gain factors that will turn one speaker on and turn the other speaker off.

Listing 7 . Compute the gain for the left and right speakers.
```if(freq>= centerFreq){ leftGain = gain;rightGain = 0;//switch off the right channel }else{rightGain = gain; leftGain = 0;//switch off the left channel}//```

Required audio data format

As you learned in an earlier module, given the values that we are using in the AudioFormatParameters01 object, the format requirements for monaural and stereo are shown below. (Note that in both cases, each audio value must be a signed 16-bit value decomposed into a pair of 8-bit bytes.)

Monaural, channels = 1

For mono, each successive pair of bytes in the melody array must contain one audio value. The element with the lower index must contain the most significant eightbits of the 16-bit audio value.

Stereo, channels = 2

For stereo, alternating pairs of bytes must each contain one audio value in the same byte order as for mono. One pair of bytes is routed to the left speakerand the other pair of bytes is routed to the right speaker (almost) simultaneously.

Within the four bytes, the pair with the lowest index is routed to the left speaker and the other pair is routed to the right speaker.

You learned how to use the putShort method belonging to an object of the ByteBuffer class to deposit the short data into the byte array in the earlier module titled Jbs2030-A Pure Sinusoidal Tone .

Deposit stereo audio data in the melody file

Listing 8 used the information from above to compute the current audio value of the pulse and to deposit it into two consecutive pairs of bytes in the melody array. Note that the putShort method is called twice, once for each channel. Note also that the values of leftGain and rightGain are used to scale each audio value so that it will be emitted from only one of the two stereo speakers.

Listing 8 . Deposit stereo audio data in the melody file.
```byteBuffer.putShort((short)(leftGain*Math.sin(2*Math.PI*freq*time))); byteBuffer.putShort((short)(rightGain*Math.sin(2*Math.PI*freq*time)));}//end for loopreturn melody; }//end method getMelody//-------------------------------------------------------------------------// }//end class AudioGraphSinusoidal```

Listing 8 returns a reference to the melody array when the for loop terminates.

Listing 8 also signals the end of the getMelody method and the end of the AudioGraphSinusoidal class.

Controlling stereo speaker output levels

This module demonstrates one way to control the output levels from the two speakers in a stereo melody. It is not necessary that one speaker be turnedcompletely off and the other speaker turned completely on as is the case here. The relativelevels of the audio outputs from the two speakers can be controlled by adjusting the relative values of the left and right gain values.

can someone help me with some logarithmic and exponential equations.
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
Commplementary angles
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
a perfect square v²+2v+_
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algebra 2 Inequalities:If equation 2 = 0 it is an open set?
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
rolling four fair dice and getting an even number an all four dice
Kristine 2*2*2=8
Differences Between Laspeyres and Paasche Indices
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
is it 3×y ?
J, combine like terms 7x-4y
im not good at math so would this help me
yes
Asali
I'm not good at math so would you help me
Samantha
what is the problem that i will help you to self with?
Asali
how do you translate this in Algebraic Expressions
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
what's the easiest and fastest way to the synthesize AgNP?
China
Cied
types of nano material
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
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Yasmin
what is the function of carbon nanotubes?
Cesar
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preparation of nanomaterial
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
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Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
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Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
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Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
can nanotechnology change the direction of the face of the world
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
how did you get the value of 2000N.What calculations are needed to arrive at it
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