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Mathematics

Multiplication

2.3 1.1 12

1.2 6

1.3 9

1.4 8

1.5 5

1.6 12

1.7 45

1.8 50

1.9 900

1.10 500

1.11 580

1.12 100

1.13 2

1.14 12,5 / 12½

1.15 6

Leaner section

Content

Activity: to use divisibility rules [lo 1.12.1]

Now you can test your skill in division and use the new knowledge that you have gained effectively. Let us see how you cope with the following mental calculation test. Write down answers only, as quickly as you can.

1.1 72 ÷ 6 = ___________________

1.2 54 ÷ 9 = ___________________

1.3 63 ÷ 7 = ___________________

1.4 48 ÷ ___________________ = 6

1.5 35 ÷ ___________________ = 7

1.6 108 ÷ ___________________ = 9

1.7 ___________________ ÷ 5 = 9

1.8 4 500 ÷ ___________________ = 90

1.9 45 000 ÷ 50 = ___________________

1.10 45 000 ÷ ___________________ = 90

1.11 5 800 ÷ 10 = ___________________

1.12 8 900 ÷ ___________________ = 89

1.13 2 420 ÷ 20 = (2 420 ÷ 10) ÷ ___________________

1.14 A half ´ 25 = ___________________

1.15 (30 ÷ 5) = (36 ÷ ___________________)

15

Fill in: I got ___________________ correct!

TIME FOR SELF-ASSESSMENT!

How well do you know the work we have done up to now? Indicate this by marking the appropriate block:

  • Tick the applicable block
Not at all Very uncertain Somewhat uncertain Very well
I know my ÷ tables. (LO 1.9) ____ ____ ____ ____
I knew most of the revision questions. (LO 1.12) ____ ____ ____ ____
I can formulate rules for division by powers of 10 (10 ; 100 ; 1 000 ; 10 000) (LO 1.12) ____ ____ ____ ____
I can divide correctly by 1 000 (LO 1.12) ____ ____ ____ ____
I can divide correctly by 10 000 (LO 1.12) ____ ____ ____ ____
It is easy for me to divide by 10 and 100 (LO 1.12) ____ ____ ____ ____

BRAIN-TEASER!

Francois has a bag of marbles. If he divides them into groups of 4, 2are left over. If he divides them into groups of 5, 1 is left over. How many marbles can there be in his bag? Could you write down 5 possible answers in the bag?

Assessment

Learning Outcome 1: The learner will be able to recognise, describe and represent numbers and their relationships, and to count, estimate, calculate and check with competence and confidence in solving problems.

Assessment Standard 1.12: We know this when the learner recognises, describes and uses:

1.12.1: divisibility rules for 2, 5, 10, 100 and 1 000.

Questions & Answers

a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
im not good at math so would this help me
Rachael Reply
how did I we'll learn this
Noor Reply
f(x)= 2|x+5| find f(-6)
Prince Reply
f(n)= 2n + 1
Samantha Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Mathematics grade 6. OpenStax CNX. Sep 10, 2009 Download for free at http://cnx.org/content/col11030/1.1
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