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Name the ordered pair of each point shown:

The graph shows the x y-coordinate plane. The x and y-axis each run from -7 to 7. The point “ordered pair 4, 0” is labeled A. The point “ordered pair 0, 3” is labeled B.  The point “ordered pair -3, 0” is labeled C. The point “ordered pair 0, -5” is labeled D.

  1. A: (4,0)
  2. B: (0,3)
  3. C: (−3,0)
  4. D: (0,−5)

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Name the ordered pair of each point shown:

The graph shows the x y-coordinate plane. The x and y-axis each run from -7 to 7. The point “ordered pair 5, 0” is labeled C. The point “ordered pair 0, 2” is labeled D.  The point “ordered pair -3, 0” is labeled A. The point “ordered pair 0,-3” is labeled B.

  1. A: (−3,0)
  2. B: (0,−3)
  3. C: (5,0)
  4. D: (0,2)

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Verify solutions to an equation in two variables

All the equations we solved so far have been equations with one variable. In almost every case, when we solved the equation we got exactly one solution . The process of solving an equation ended with a statement such as x = 4 . Then we checked the solution by substituting back into the equation.

Here’s an example of a linear equation in one variable , and its one solution.

3 x + 5 = 17 3 x = 12 x = 4

But equations can have more than one variable. Equations with two variables can be written in the general form A x + B y = C . An equation of this form is called a linear equation in two variables.

Linear equation

An equation of the form A x + B y = C , where A and B are not both zero, is called a linear equation in two variables.

Notice that the word “line” is in linear.

Here is an example of a linear equation in two variables, x and y :

A series of equations is shown. The first line shows A x + B x = C. The “A” is red, the “B” is blue, and the “C” is turquoise. The second line shows x + 4 y = 8. The “4” is blue and the “8” is turquoise. The last line shows A =1 in red, B = 4 in blue, and C =8 in turquoise.

Is y = −5 x + 1 a linear equation? It does not appear to be in the form A x + B y = C . But we could rewrite it in this form.

.
Add 5 x to both sides. .
Simplify. .
Use the Commutative Property to put it in A x + B y = C . .

By rewriting y = −5 x + 1 as 5 x + y = 1 , we can see that it is a linear equation in two variables because it can be written in the form A x + B y = C .

Linear equations in two variables have infinitely many solutions. For every number that is substituted for x , there is a corresponding y value. This pair of values is a solution to the linear equation and is represented by the ordered pair ( x , y ) . When we substitute these values of x and y into the equation, the result is a true statement because the value on the left side is equal to the value on the right side.

Solution to a linear equation in two variables

An ordered pair ( x , y ) is a solution to the linear equation A x + B y = C , if the equation is a true statement when the x - and y -values of the ordered pair are substituted into the equation.

Determine which ordered pairs are solutions of the equation x + 4 y = 8 :

  1. ( 0 , 2 )
  2. ( 2 , −4 )
  3. ( −4 , 3 )

Solution

Substitute the x - and y -values from each ordered pair into the equation and determine if the result is a true statement.

( 0 , 2 ) ( 2 , −4 ) ( −4 , 3 )
. . .
( 0 , 2 ) is a solution. ( 2 , −4 ) is not a solution. ( −4 , 3 ) is a solution.
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Determine which ordered pairs are solutions to the given equation: 2 x + 3 y = 6

  1. ( 3 , 0 )
  2. ( 2 , 0 )
  3. ( 6 , −2 )

,

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Determine which ordered pairs are solutions to the given equation: 4 x y = 8

  1. ( 0 , 8 )
  2. ( 2 , 0 )
  3. ( 1 , −4 )

,

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Determine which ordered pairs are solutions of the equation. y = 5 x 1 :

  1. ( 0 , −1 )
  2. ( 1 , 4 )
  3. ( −2 , −7 )

Solution

Substitute the x - and y -values from each ordered pair into the equation and determine if it results in a true statement.

( 0 , −1 ) ( 1 , 4 ) ( −2 , −7 )
. . .
( 0 , −1 ) is a solution. ( 1 , 4 ) is a solution. ( −2 , −7 ) is not a solution.
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Determine which ordered pairs are solutions of the given equation: y = 4 x 3

  1. ( 0 , 3 )
  2. ( 1 , 1 )
  3. ( 1 , 1 )

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Determine which ordered pairs are solutions of the given equation: y = −2 x + 6

  1. ( 0 , 6 )
  2. ( 1 , 4 )
  3. ( −2 , −2 )

,

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Complete a table of solutions to a linear equation

In the previous examples, we substituted the x - and y -values of a given ordered pair    to determine whether or not it was a solution to a linear equation. But how do we find the ordered pairs if they are not given? One way is to choose a value for x and then solve the equation for y . Or, choose a value for y and then solve for x .

Practice Key Terms 7

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Source:  OpenStax, Prealgebra. OpenStax CNX. Jul 15, 2016 Download for free at http://legacy.cnx.org/content/col11756/1.9
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