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Which are more powerful, messages or monitors?

Message systems vary along several dimensions:

  • Relationship between mailboxes and processes:
    • One mailbox per process, use process name in send and receive (simple but restrictive) [RC4000].
    • No strict mailbox-process association, use mailbox name (can have multiple mailboxes perprocess, can pass mailboxes from process to process, but trickier to implement) [Unix].
  • Extent of buffering:
    • Buffering (more efficient for large transfers when sender and receiver run at varying speeds).
    • None -- rendezvous protocols (simple, OK for call-return type communication, know that message was received).
  • Conditional vs. unconditional ops:
    • Unconditional receive: return message if mailbox is not empty, otherwise wait until message arrives.
    • Conditional receive: return message if mailbox is not empty, otherwise return special "empty" value.
    • Unconditional send: wait until mailbox has space.
    • Conditional send: return "full" if no space in mailbox (message is discarded).

What happens with rendezvous protocols and conditional operations?

  • Additional forms of waiting:
    • Almost all systems allow many processes to wait on the same mailbox at the same time. Messages get passed to processes in order.
    • A few systems allow each process to wait on several mailboxes at once. The process gets the first message to arrive on any of the mailboxes. Thisis actually quite useful (give Caesar as an example).
  • Constraints on what gets passed in messages:
    • None: just a stream of bytes (Unix pipes).
    • Enforce message boundaries (send and receive in same chunks).
    • Protected objects (e.g. a token for a mailbox).

How would the following systems fall into the above classifications?

  • Condition variables
  • Unix pipes

Classical ipc problems

The dining philosophers problem

A classical problem from Dijkstra

  • 5 philosophers sitting at a round table
  • Each has a plate of spaghetti
  • There is a fork between each two
  • Need two forks to eat

What algorithm do you use for access to the shared resource (the forks)?

  • The obvious solution (pick up right; pick up left) deadlocks.
  • Big lock around everything serializes.
  • Good code in the book.

The purpose of mentioning the Dining Philosophers problem without giving the solution is to give a feel of what coordinationproblems are like. The book gives others as well. We are skipping these (again this material would be covered in a sequel course).

The readers and writers problem

  • Two classes of processes.
    • Readers, which can work concurrently.
    • Writers, which need exclusive access.
  • Must prevent 2 writers from being concurrent.
  • Must prevent a reader and a writer from being concurrent.
  • Must permit readers to be concurrent when no writer is active.
  • Perhaps want fairness (e.g., freedom from starvation).
  • Variants
  • Writer-priority readers/writers.
  • Reader-priority readers/writers.

Quite useful in multiprocessor operating systems and database systems. The “easy way out” is to treat all processes as writers inwhich case the problem reduces to mutual exclusion (P and V). The disadvantage of the easy way out is that you give up reader concurrency. Again for moreinformation see the web page referenced above.

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
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Source:  OpenStax, Operating systems. OpenStax CNX. Aug 13, 2009 Download for free at http://cnx.org/content/col10785/1.2
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