# 2.8 Fractions - 04

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## Memorandum

8. a) a) $\frac{2}{6}$

b) $\frac{1}{3}$

c) $\frac{3}{9}$

d) $\frac{4}{\text{12}}$

b) Every one eats the same amount of food. / Fractions are the same.

9. $\frac{2}{3}$ = $\frac{6}{9}$

$\frac{4}{5}$ = $\frac{\text{80}}{\text{100}}$

$\frac{\text{18}}{\text{20}}$ = $\frac{9}{\text{10}}$

$\frac{\text{75}}{\text{100}}$ = $\frac{3}{4}$

$\frac{2}{3}$ = $\frac{\text{16}}{\text{24}}$

$\frac{\text{25}}{\text{30}}$ = $\frac{5}{6}$

## Activity: fractions [lo 1.4.1, lo 1.11, lo 2.1.5]

8. Four learners have been rewarded with a chocolate for their good work. They don’t eat it up immediately, but only the section that has been coloured in.

i)

ii)

iii)

iv)

1. What fraction does each one eat?

i) Carli: ___________________

ii) Peter-John: ______________

iii) Kayla: __________________

iv) Vusi: ___________________

b) What do you notice?

_____________________________________________________________________

_____________________________________________________________________

_____________________________________________________________________

8.2 Do you still remember?

In our example $\frac{2}{6}=\frac{1}{3}=\frac{3}{9}=\frac{4}{\text{12}}$

We call these fractions equivalent fractions.

Equivalent fractions are thus the same quantity or equal to each other

8.3 TAKE NOTE:

To form an equivalent fraction, you must multiply or divide the numerator AND denominator by THE SAME NUMBER.

 e.g.
 2 × 4 5 × 4
=
 8 20
;
 18  6 24  6
=
 3 4

9. Join the fraction in column A with its equivalent in column B:

 A B $\frac{2}{3}$ $\frac{3}{4}$ $\frac{4}{5}$ $\frac{6}{9}$ $\frac{\text{18}}{\text{20}}$ $\frac{9}{\text{10}}$ $\frac{\text{75}}{\text{100}}$ $\frac{5}{6}$ $\frac{2}{3}$ $\frac{\text{16}}{\text{24}}$ $\frac{\text{25}}{\text{30}}$ $\frac{\text{80}}{\text{100}}$

## Assessment

Learning Outcome 1: The learner will be able to recognise, describe and represent numbers and their relationships, and to count, estimate, calculate and check with competence and confidence in solving problems.

Assessment Standard 1.4: We know this when the learner recognises and uses equivalent forms of the rational numbers listed above, including:

1.4.1: common fractions;

1.11: recognises, describes and uses:

Learning Outcome 2: The learner will be able to recognise, describe and represent patterns and relationships, as well as to solve problems using algebraic language and skills.

Assessment Standard 2.1: We know this when the learner investigates and extends numeric and geometric patterns looking for a relationship or rules, including patterns:

2.1.5: represented in tables.

can someone help me with some logarithmic and exponential equations.
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
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