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LU 3.4.7


Leeruitkomste 1: LUISTER : Die leerder is in staat om vir inligting en genot te luister en gepas en krities binne ‘n wye verskeidenheid situasies te reageer.

Assesseringstandaard 1.3: Dit is duidelik wanneer die leerder met genot na stories, gedigte, liedjies en ander mondelinge tekste luister en begrip toon:

1.3.3 voorspel wat gaan gebeur;

1.3.4 ‘n reeks gebeurtenisse of idees in ‘n teks oorvertel.

Leeruitkomste 2: PRAAT : Die leerder is in staat om vrymoedig en doeltreffend in gesproke taal binne ‘n wye verskeidenheid situasies te kommunikeer.

Assesseringstandaard 2.1: Dit is duidelik wanneer die leerder oor persoonlike ervarings en algemene nuusgebeure gesels;

Assesseringstandaard 2.3: Dit is duidelik wanneer die leerder eenvoudige stories met ‘n begin, middel en einde skep en vertel deur beskrywende taal te gebruik en herhaling te vermy;

Assesseringstandaard 2.4: Dit is duidelik wanneer die leerder neem deel aan klas- en groepbesprekings:

2.4.3 stel idees voor en brei daarop uit;

2.4.7 vrae beantwoord en redes vir antwoorde gee.

Leeruitkomste 3: LEES EN KYK : Die leerder is in staat om vir inligting en genot te lees en te kyk en krities op die estetiese, kulturele en emosionele waardes in tekste te reageer.

Assesseringstandaard 3.1: Dit is duidelik wanneer die leerder visuele leidrade gebruik om betekenis te skep:

3.1.2 ten opsigte van beelde, die gedrukte media en advertensies;

Assesseringstandaard 3.2: Dit is duidelik wanneer die leerder betekenis uit geskrewe teks skep:

3.2.1 ‘n storie alleen of saam met die onderwyser lees, en:

Assesseringstandaard 3.3: Dit is duidelik wanneer die leerder betekenis uit letters en woorde in langer tekste herken en skep:

3.3.1 met toenemende spoed en vlotheid lees;

3.3.2 hardop lees en die korrekte uitspraak en gepaste klem gebruik;

Assesseringstandaard 3.4: Dit is duidelik wanneer die leerder klankbewustheid ontwikkel:

3.4.6 ‘n toenemende aantal hoëfrekwensiesigwoorde herken;

3.4.7 enkelklanke hersien.

Leeruitkomste 4 SKRYF : Die leerder is in staat om verskillende soorte feitelike en verbeeldingstekste vir ‘n wye verskeidenheid doeleindes te skryf.

Assesseringstandaard 4.1: Dit is duidelik wanneer die leerder toenemend leesbaar skryf:

Assesseringstandaard 4.2: Dit is duidelik wanneer die leerder pre-skryfstrategieë gebruik om ‘n skryfstuk te begin:

Assesseringstandaard 4.6: Dit is duidelik wanneer die leerder woordeskat opbou en woorde begin spel sodat ander dit kan lees en verstaan:

4.6.5 ‘n woordbank en ‘n persoonlike woordeboek opbou;

Assesseringstandaard 4.7: Dit is duidelik wanneer die leerder gepaste grammatikale strukture en skryfkonvensies gebruik en skryf sodat ander kan verstaan:

4.7.2 basiese punktuasie gebruik (hoofletters en punte);

Assesseringstandaard 4.8: Dit is duidelik wanneer die leerder woorde, sinne en stories illustreer om begrip te toon.

Leeruitkomste 6 TAALSTRUKTUUR EN –GEBRUIK : Die leerder ken en is in staat om die klanke, woordeskat en grammatika van die taal te gebruik om tekste te skep en te interpreteer.

Assesseringstandaard 6.2: Dit is duidelik wanneer die leerder met woorde werk;

6.2.1 bekende woorde korrek spel.

Questions & Answers

how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
Commplementary angles
Idrissa Reply
im all ears I need to learn
right! what he said ⤴⤴⤴
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
many many of nanotubes
what is the k.e before it land
what is the function of carbon nanotubes?
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
what is system testing
what is the application of nanotechnology?
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
anybody can imagine what will be happen after 100 years from now in nano tech world
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
silver nanoparticles could handle the job?
not now but maybe in future only AgNP maybe any other nanomaterials
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Afrikaans huistaal graad 2. OpenStax CNX. Oct 15, 2009 Download for free at http://cnx.org/content/col11132/1.1
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