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Let v = x z , y z , 0 be the velocity field of a fluid. Let C be the solid cube given by 1 x 4 , 2 y 5 , 1 z 4 , and let S be the boundary of this cube (see the following figure). Find the flow rate of the fluid across S .

This is a figure of a diagram of the given vector field in three dimensions. The x components are x/z, the y components are y/z, and the z components are 0.

9 ln ( 16 )

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[link] illustrates a remarkable consequence of the divergence theorem. Let S be a piecewise, smooth closed surface and let F be a vector field defined on an open region containing the surface enclosed by S . If F has the form F = f ( y , z ) , g ( x , z ) , h ( x , y ) , then the divergence of F is zero. By the divergence theorem, the flux of F across S is also zero. This makes certain flux integrals incredibly easy to calculate. For example, suppose we wanted to calculate the flux integral S F · d S where S is a cube and

F = sin ( y ) e y z , x 2 z 2 , cos ( x y ) e sin x .

Calculating the flux integral directly would be difficult, if not impossible, using techniques we studied previously. At the very least, we would have to break the flux integral into six integrals, one for each face of the cube. But, because the divergence of this field is zero, the divergence theorem immediately shows that the flux integral is zero.

We can now use the divergence theorem to justify the physical interpretation of divergence that we discussed earlier. Recall that if F is a continuous three-dimensional vector field and P is a point in the domain of F , then the divergence of F at P is a measure of the “outflowing-ness” of F at P . If F represents the velocity field of a fluid, then the divergence of F at P is a measure of the net flow rate out of point P (the flow of fluid out of P less the flow of fluid in to P ). To see how the divergence theorem justifies this interpretation, let B r be a ball of very small radius r with center P , and assume that B r is in the domain of F . Furthermore, assume that B r has a positive, outward orientation. Since the radius of B r is small and F is continuous, the divergence of F is approximately constant on B r . That is, if P is any point in B r , then div F ( P ) div F ( P ) . Let S r denote the boundary sphere of B r . We can approximate the flux across S r using the divergence theorem as follows:

S r F · d S = B r div F d V B r div F ( P ) d V = div F ( P ) V ( B r ) .

As we shrink the radius r to zero via a limit, the quantity div F ( P ) V ( B r ) gets arbitrarily close to the flux. Therefore,

div F ( P ) = lim r 0 1 V ( B r ) S r F · d S

and we can consider the divergence at P as measuring the net rate of outward flux per unit volume at P . Since “outflowing-ness” is an informal term for the net rate of outward flux per unit volume, we have justified the physical interpretation of divergence we discussed earlier, and we have used the divergence theorem to give this justification.

Application to electrostatic fields

The divergence theorem has many applications in physics and engineering. It allows us to write many physical laws in both an integral form and a differential form (in much the same way that Stokes’ theorem allowed us to translate between an integral and differential form of Faraday’s law). Areas of study such as fluid dynamics, electromagnetism, and quantum mechanics have equations that describe the conservation of mass, momentum, or energy, and the divergence theorem allows us to give these equations in both integral and differential forms.

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
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The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
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Abhi
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ninjadapaul
20/(×-6^2)
Salomon
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ninjadapaul
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ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
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Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
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ninjadapaul
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Abhi
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At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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