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Two overloaded methods

The program defines two overloaded methods named overLoadMthd . One requires an incoming parameter of type Test , and the other requires an incoming parameter of type DumIntfc . When called, each of the overloaded methods prints a message indicating the type of itsargument.

Two objects of the class Test

The program instantiates two objects of the class Test . It assigns one of the object's references to a reference variable named a , which is declared to be of type Test .

The program assigns the other object's reference to a reference variable named b , which is declared to be of type DumIntfc . (Remember, both objects were instantiated from the class Test .)

No surprises here

Then it calls the overloaded method named overLoadMthd twice in succession, passing first the reference variable of type Test and then the reference variable of type DumIntfc .

The program output doesn't produce any surprises. When the reference variable of type Test is passed as a parameter, the overloaded method requiring that type of parameter is selected for execution. When the referencevariable of type DumIntfc is passed as a parameter, the overloaded method requiring that type of parameter is selected for execution.

Back to Question 6

Answer 5

C. float 2.14748365E9 float 9.223372E18double 4.2

Explanation 5

Another subtle method selection issue

This program illustrates a subtle issue in the automatic selection of an overloaded method based on assignment compatibility.

This program defines two overloaded methods named square . One requires an incoming parameter of type float , and the other requires an incoming parameter of type double .

When called, each of these methods prints the type of its formal argument along with the value of the incoming parameter as represented by its formalargument type. In other words, the value of the incoming parameter is printed after it has been automatically converted to the formal argument type.

Printout identifies the selected method

This printout makes it possible to determine which version is called for different types of parameters. It also makes it possible to determine the effectof the automatic conversion on the incoming parameter. What we are going to see is that the conversion process can introduce serious accuracy problems.

Call the method three times

The square method is called three times in succession, passing values of type int , long , and double during successive calls.

(Type long is a 64-bit integer type capable of storing integer values that are much larger than can be stored intype int . The use of this type here is important for illustration of data corruption that occurs through automatic typeconversion.)

The third invocation of the square method, passing a double as a parameter, is not particularly interesting. There is a version of square with a matching argument type, and everything behaves as would be expected for this invocation. The interesting behavioroccurs when the int and long values are passed as parameters.

Passing an int parameter

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
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how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
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I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
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is it a question of log
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Commplementary angles
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what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
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a perfect square v²+2v+_
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Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
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rolling four fair dice and getting an even number an all four dice
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Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
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how do you translate this in Algebraic Expressions
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Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
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. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
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Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
what is system testing
what is the application of nanotechnology?
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
anybody can imagine what will be happen after 100 years from now in nano tech world
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
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silver nanoparticles could handle the job?
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I'm interested in Nanotube
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
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