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Wiskunde

Getalbegrip, optelling en aftrekking

Aftrekking

Opvoeders afdeling

Memorandum

2.1 en 2.2 eie antwoord

LEERDERS AFDELING

Inhoud

Aktiwiteit: om die gelykwaardigheid en geldigheid van verskillende voorstellings te bepaal [lu 2.6]

Om strategieë te gebruik om oplossings te kontroleer [lu 1.11]

  • By aktiwiteit 3.8 het julle jul eie tegnieke en strategieë gebruik om die probleme op te los. In jul terugvoering aan die klas het jul seker gesien dat daar meer as een manier is waarop ons getalle kan aftrek. Verdeel in groepe van drie. Lees die volgende probleem goed deur en werk dan saam deur die verskillende metodes om dit op te los:

32 564 mans en 29 436 dames het na ’n rugbywedstryd gaan kyk.

  • Hoeveel meer mans as dames was daar?

1.1 Ek hou daarvan om by te tel:

32 564 – 29 436

Dus:29 436 + 64 = 29 500

29 500 + 500 = 30 000

30 000 + 2 564 = 32 564

64 + 500 + 2 564 = 3 128

Daar was dus 3 128 meer mans as dames.

1.2 Ek rond die tweede getal af tot die naaste 100 :

32 564 – 29 436

Dus: 32 564 – 29 400 = 3 164

3 164 – 36 = 3 128

Die antwoord is 3 128 meer mans.

1.3 Ek verkies om die aftrekker af te rond tot die naaste 1 000 :

32 564 – 29 436

Dus: 32 564 – 29 000 = 3 564

3 564 – 436 = 3 128

1.4 Ek werk die verskil “stuk vir stuk” (stap vir stap) uit :

32 564 – 29 436

Dus: 32 000 – 29 000 = 3 000

564 – 436 = 128

3000 + 128 = 3 128

1.5 Ek skryf die getalle eers in uitgebreide notasie:

32 564 – 29 436

Dus: 30 000 + 2 000 + 500 + 60 + 4

- 20 000 + 9 000 + 400 + 30 + 6

Nou hergroepeer ek:

20 000 + 12 000 + 500 + 50 + 14

- 20 000 + 9 000 + 400 + 30 + 6

0 + 3 000 + 100 + 20 + 8

Die antwoord is dus 3 128

1.6 Ek bereken die verskil deur met negatiewe getalle te werk:

32 564 – 29 436

Dus: 30 000 – 20 000 = 10 000

2 000 – 9 000 = – 7 000 (ek moet nog 7 000 aftrek)

500 – 400 = 100

60 – 30 = 30

4 – 6 = – 2 (ek moet nog 2 aftrek)

Die verskil is dus:

10 000 – 7 000 + 100 + 30 – 2 = 3 128

2. 2.1 Watter van bogenoemde metodes is vir JOU die maklikste? _____________________________________________________________________

Hoekom? _______________________________________________________________

_____________________________________________________________________

__________________________________________________________________________________________________________________________________________

2.2 Kan julle groep aan nog ‘n metode dink om die verskil te bereken?

_____________________________________________________________________

__________________________________________________________________________________________________________________________________________

Assessering

Leeruitkomste 1: Die leerder is in staat om getalle en die verwantskappe daarvan te herken, te beskryf en voor te stel, en om tydens probleemoplossing bevoeg en met selfvertroue te tel, te skat, te bereken en te kontroleer.

Assesseringstandaard 1.11: Dit is duidelik wanneer die leerder ‘n verskeidenheid strategieë gebruik om oplossings te kontroleer en die redelikheid van oplossings te beoordeel.

Leeruitkomste 2: Die leerder is in staat om patrone en verwantskappe te herken, te beskryf en voor te stel en probleme op te los deur algebraïese taal en vaardighede te gebruik.

Assesseringstandaard 2.6: Dit is duidelik wanneer die leerder bepaal, deur bespreking en vergelyking, die ekwivalensie van verskillende beskrywings van dieselfde verwantskap of reël wat soos volg voorgestel word:

2.6.1 woordeliks;

2.6.2 in vloeidiagramme;

2.6.3 met getalsinne.

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
Abhi
how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
hmm
Abhi
is it a question of log
Abhi
🤔.
Abhi
I rally confuse this number And equations too I need exactly help
salma
But this is not salma it's Faiza live in lousvile Ky I garbage this so I am going collage with JCTC that the of the collage thank you my friends
salma
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
hi
salma
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Wiskunde graad 5. OpenStax CNX. Sep 07, 2009 Download for free at http://cnx.org/content/col10993/1.1
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