# 9.2 Measurement

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## Areas of polygons

1. Area of triangle: $\frac{1}{2}×$ base $×$ perpendicular height
2. Area of trapezium: $\frac{1}{2}×$ (sum of $\parallel$ (parallel) sides) $×$ perpendicular height
3. Area of parallelogram and rhombus: base $×$ perpendicular height
4. Area of rectangle: length $×$ breadth
5. Area of square: length of side $×$ length of side
6. Area of circle: $\pi$ x radius ${}^{2}$

Find the area of the following figure:

1. We first need to find the height, BE, of the parallelogram. We can use Pythagoras to do this:
$\begin{array}{ccc}{\text{BE}}^{2}\hfill & =& {\text{AB}}^{2}-{\text{AE}}^{2}\hfill \\ \hfill {\text{BE}}^{2}& =& {5}^{2}-{3}^{2}\hfill \\ \hfill {\text{BE}}^{2}& =& 16\hfill \\ \hfill \text{BE}& =& 4\hfill \end{array}$
2. We apply the formula for the area of a parallelogram to find the area:
$\begin{array}{ccc}\hfill \text{Area}& =& h×b\hfill \\ & =& 4×7\hfill \\ & =& 28\hfill \end{array}$

## Polygons

1. For each case below, say whether the statement is true or false. For false statements, give a counter-example to prove it:
1. All squares are rectangles
2. All rectangles are squares
3. All pentagons are similar
4. All equilateral triangles are similar
5. All pentagons are congruent
6. All equilateral triangles are congruent
2. Find the areas of each of the given figures - remember area is measured in square units (cm ${}^{2}$ , m ${}^{2}$ , mm ${}^{2}$ ).

## Right prisms and cylinders

In this section we study how to calculate the surface areas and volumes of right prisms and cylinders. A right prism is a polygon that has been stretched out into a tube so that the height of the tube is perpendicular to the base (the definition is motivated by the fact that the angle between base and side form a right angle). A square prism has a base that is a square and a triangular prism has a base that is a triangle.

It is relatively simple to calculate the surface areas and volumes of prisms.

## Surface area

The term surface area refers to the total area of the exposed or outside surfaces of a prism. This is easier to understand if you imagine the prism as a solid object.

If you examine the prisms in [link] , you will see that each face of a prism is a simple polygon. For example, the triangular prism has two faces that are triangles and three faces that are rectangles. Therefore, in order to calculate the surface area of a prism you simply have to calculate the area of each face and add it up. In the case of a cylinder the top and bottom faces are circles, while the curved surface flattens into a rectangle.

Surface Area of Prisms

Calculate the area of each face and add the areas together to get the surface area. To do this you need to determine the correct shape of each and every face of the prism and then for each one determine the surface area. The sum of the surface areas of all the faces will give you the total surface area of the prism.

## Discussion : surface areas

In pairs, study the following prisms and the adjacent image showing the various surfaces that make up the prism. Explain to your partner, how each relates to the other.

## Activity: surface areas

Find (or take one yourself) a picture of a building that does not have a well defined shape (i.e. is not simply a rectangle). For example a castle with towers, or a house with gable windows or a porch. Assume you have to paint the outside of the building. How much paint would you need? Think about what you have learnt about surface area and the area of polygons. Can you find regular polygons on your picture and use those to find the surface area?

find the 15th term of the geometric sequince whose first is 18 and last term of 387
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
hmm well what is the answer
Abhi
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can someone help me with some logarithmic and exponential equations.
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
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Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
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Abhi
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Abhi
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Abhi
Commplementary angles
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algebra 2 Inequalities:If equation 2 = 0 it is an open set?
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
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Kristine 2*2*2=8
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Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
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Cied
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I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
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Porter
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Yasmin
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Cesar
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Uday
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Stotaw
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Azam
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Prasenjit
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Azam
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Prasenjit
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Damian
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Azam
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Uday
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Uday
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At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
how did you get the value of 2000N.What calculations are needed to arrive at it
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