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Mathematics

Meet bonny and tommy

Educator section

Memorandum

Up to Grade 2 the learners used the word “ones” for “units” but as from Grade 3 we change to “units”. Explain it to the learners.

Use concrete objects and help the learners to discover for themselves what even and uneven numbers are. Do this to 9 at first.

Help them to discover the pattern from 11 to 19.

When they have discovered the pattern of 2 4 6 8 0 on the unit side for even numbers and 1 3 5 7 9 on the unit side for uneven numbers, they have fun applying this to higher numbers.

Leaner section

Content

Activity: even and uneven numbers [lo 1.4, lo 2.2, lo 1.9, lo 1.8]

  • Complete the pattern with numbers:

All the SQUARES belong to Bonny. She has all the numbers with a 2 ................... ................... ................... 0 on the side of the ones (units). All her numbers are therefore even numbers.

All the CIRCLES belong to Tommy. He has all the numbers with a

1 ................. ................. ................. ................. on the side of the ones (units). All his numbers are therefore uneven numbers.

  • Sort Bonny’s and Tommy’s numbers:

23 38 14 9 56 80 75 2 61 97

LO 1.4 LO 2.2
  • Think!
LO 1.9
  • Match the right words: equal to; greater than; less than.
  • We can replace the words with signs:
LO 1.8

Assessment

Learning Outcome 1: The learner will be able to recognise, describe and represent numbers and their relationships, and to count, estimate, calculate and check with competence and confidence in solving problems.

Assessment Standard 1.4: We know this when the learner orders, describes and compares the following numbers:

1.4.1 whole numbers to at least 3-digit numbers;

1.4.2 common fractions including halves, quarters and thirds;

Assessment Standard 1.8: We know this when the learner can perform calculations, using appropriate symbols, to solve problems involving:

1.8.1 addition and subtraction of whole numbers with at least 3 digits;

1.8.2 multiplication of at least whole 2-digit by 1-digit numbers;

1.8.3 division of at least whole 2-digit by 1-digit numbers;

1.8.4 estimation;

Assessment Standard 1.9: We know this when the learner performs mental calculations involving:

1.9.1 addition and subtraction for numbers to at least 50;

1.9.2 multiplication of whole numbers with solutions to at least 50.

Learning Outcome 2: The learner will be able to recognise, describe and represent patterns and relationships, as well as to solve problems using algebraic language and skills.

Assessment Standard 2.2: We know this when the learner copies and extends simple number sequences to at least 1 000.

Questions & Answers

a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
im not good at math so would this help me
Rachael Reply
how did I we'll learn this
Noor Reply
f(x)= 2|x+5| find f(-6)
Prince Reply
f(n)= 2n + 1
Samantha Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Mathematics grade 3. OpenStax CNX. Oct 14, 2009 Download for free at http://cnx.org/content/col11128/1.1
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